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Chapter 0: Q11P (page 1)

Titration of metal ion with EDTA. Use Equation 12-11 to compute curves (pM versus mL of EDTA added) for the titration of 10.00 mL of 1.00 mM M2+ (= Cd2+ or Cu2+) with 10.0 mM EDTA at pH 5.00. Plot both curves on one graph.

Short Answer

Expert verified

The curves for both the metals Cd and Cu are shown below

Step by step solution

01

Information given

Titration of 10.0 mL of 1.0mM M2+ with 10 mM EDTA. The titration should be carried out at pH=5.00.

02

Equation need to be used to develop spreadsheet

Using Equation 12-11 the equation for the fraction of titration of metal ion with EDTA is as follows

蠒CLVLCMVM=1+KfM-M+KfM2CMKfM+M+KfM2CL

Other formulas need to be used

M=10-pM

Here instead of formation constant (Kf), conditional formation constant Kfshould be taken in the above formula stated.

From table 12-1 the value of aY4for EDTA at 250C and pH 5 is 2.9脳10-7

From table 12-2 we get log Kffor Cu2+= 18.78

From table 12-2 we get log Kf for Cd2+= 16.5

03

Spreadsheet

Spreadsheets developed are shown below

04

Graph Plot

The curves for both the metals Cd and Cu are shown below

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Most popular questions from this chapter

Effect of concentration in the titration of weak acid with strong base.Use your spreadsheet from Problem 11-66 to prepare a family of titration curves for pKa = 6, with the following combinations of concentrations: (a) Ca = 20 mM, Cb = 100 mM; (b) Ca = 2 mM, Cb = 10 mM; (c) Ca = 0.2 mM, Cb = 1 mM.

The figure shows reversed-phase retention data for three compounds.


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