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Determination of sulfur by combustion analysis produces a mixture of SO2and SO3 that can be passed through H2O2to convert both into H2SO4, which is titrated with standard base. When 6.123m g of a substance were burned, the H2SO4 required 3.01mL of0.010576MNaOHfor titration. Find wt% sulfur in the sample.

Short Answer

Expert verified

The weight percent of sulfur in the sample is 0.124 .

Step by step solution

01

Derfining the weight percent.

The Weight Percentage is simply the ratio of a solute's mass to the mass of a solution multiplied by 100. The Weight Percentageis also referred to as the Mass Percentage.

Percentbyweight=gramofsolute100gofsolutionPercentbyweight=gramofsolute100gofsolution

02

Determining the moles of NaOH and H2So$

Here of were required for titration of when of a substance were burned. We need to find the weight percent of sulfur in the sample.

Consider the following reaction:

H2SO4+2NaOH→2H2O+Na2SO4nNaOH=c×VnNaOH=0.01576M×3.01×10-3LnNaOH=4.744×10-5molnH2SO4=2.372×10-5mol

03

Calculating the weight percent.

Then we will find the weight percent of sulfur in the sample:

wt%=mSmsamplewt%=0.7607mg6.123mgwt%=0.124

Therefore the weight percent of sulfur in the sample is 0.124 .

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