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Why would a reprecipitation be employed in a gravimetric analysis?

Short Answer

Expert verified

The reprecipitation method in the gravimetric analysis is used for reducing the level of impurities.

Step by step solution

01

Precipitation:

Precipitation gravimetry is an analytical technique that uses a precipitation reaction to separate ions from a solution. The chemical that is added to cause the precipitation is called the precipitant or precipitating agent.

During first precipitation, impurities are present in high concentrations and also are unwanted species.

02

Reprecipitation:

After returning a precipitate to a dissolved state, the process of precipitating it again.

During reprecipitation, precipitate is purer due to reduced level of impurities in a solution.

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Most popular questions from this chapter

Write a balanced equation for the combustion of benzoic acid,C6H5CO2H, to giveCO2 and H2O. How many milligrams of and of will be produced by the combustion of 4.635mgof benzoic acid?

What is the purpose of theWO3 and Cu in Figure 27-8?

1.475-g sample containing NH4Cl(FM53.491),K2CO3(FM 138.21), and inert ingredients was dissolved to give 0.100 L of solution. A 25.0-mL aliquot was acidified and treated with excess sodium tetraphenylborate,Na+B(C6H5)4-, to precipitateK+and

NH4+ions completely:

(C6H5)4B-+K+→(C6H5)4BK(s)FM358.33(C6H5)4B-+NH4+→(C6H5)4BNH4(s)FM337.27

The resulting precipitate amounted to 0.617 g. A fresh 50.0-mL aliquot of the original solution was made alkaline and heated to drive off all theNH3.

NH4++OH-→NH3(g)+H2O

It was then acidified and treated with sodium tetraphenylborate to give 0.554 g of precipitate. Find the weight percent ofNH4ClandK2CO3in the original solid.

Why are many ionic precipitates washed with electrolyte solution instead of pure water?

Statistics of coprecipitation. 17In Experiment 1,200.0mL of solution containing 10.0mg of SO42-(from Na2SO4) were treated with excess Bacl2 solution to precipitate BaSO4 containing some coprecipitated Cl-. To find out how much coprecipitated was present, the precipitate was dissolved in 35mL of 98wt%H2SO4 and boiled to liberate , which was removed by bubbling gas through the H2SO4. The HCI/N2 stream was passed into a reagent solution that reacted with to give a color that was measured. Ten replicate trials gave values of 7.8,9.8,7.8,7.8,7.8,7.8,13,7,12.7,13.7, and 12.7. Experiment 2 was identical to the first one, except that the mL solution also contained of from ). Ten replicate trials gave 7.8,10,8,8.8,7.8,6.9, 8.8, 15.7 , 12.7 , 13.7and 14.7μ³¾´Ç±ô°ä±ô-.

(a) Find the mean, standard deviation, and 95% confidence interval for Cl-in each experiment.

(b) Is there a significant difference between the two experiments? What does your answer mean?

(c) If there were no coprecipitate, what mass of BaSO4(FM 233.39) would be expected?

(d) If the coprecipitate is (FM 208.23), what is the average mass of precipitate(BaSO4+BaCl2)in Experiment 1. By what percentage is the mass greater than the mass in part (c)?

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