Q12P Marie Curie dissolved 0.091 92 g... [FREE SOLUTION]

Chapter 27: Q12P (page 767)

Marie Curie dissolved 0.091 92 g of RaCl₂ and treated it with excess AgNO₃to precipitate 0.088 90 g of AgCl. In her time (1900), the atomic mass of Ag was known to be 107.8 and that of Cl
was 35.4. From these values, find the atomic mass of Ra that Marie Curie would have calculated.

Short Answer

Expert verified

The atomic mass of Ra is calculated as 225.22 g / mol.

Step by step solution

calculate moles of AgCl and Ra:

In this task we have 0.09192 g of RaCl₂ dissolves and treated with excess AgNO₃ to precipitate 0.08890 g of AgCl. In 1900, the atomic mass of Ag was known to be 107.8 and that Cl was 35.4 (M (AgCl) = 143.2 g/mol). We will use these values in order to find the atomic mass of Ra.

Calculate the moles of AgCl and Ra:

$n (AgCl) = m / M n (AgCl) = \frac{0.0889 g}{143.2 g / mol} n (AgCl) = 6.2081 脳 10^{- 4} mol n (Ra) = \frac{n (AgCl)}{n_{1} (Ra)} n (Ra) = \frac{6.2081 脳 10^{- 4} mol}{2 mol} n (Ra) = 3.1040 脳 10^{- 4} mol$

n₁ = 2 mol because in RaCl₂there is 2 mol of Cl per 1 mol of Ra.

Calculate the molecular mass of RaCl2:

$3.1040 脳 10^{- 4} mol = \frac{m ({RaCl}_{2})}{M ({RaCl}_{2})} M ({RaCl}_{2}) = \frac{m ({RaCl}_{2})}{3.1040 脳 10^{- 4} mol} M ({RaCl}_{2}) = \frac{0.09192 g}{3.1040 脳 10^{- 4} mol}$

Calculate the atomic mass of Ra:

$M ({RaCl}_{2}) = M (Ra) + 2 M (Cl) M (Ra) = M ({RaCl}_{2}) - 2 M (Cl) M (Ra) = 296.13 g / mol - 70.91 g / mol M (Ra) = 225.22 g / mol$

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91影视

Marie Curie dissolved 0.091 92 g of RaCl₂ and treated it with excess AgNO₃to precipitate 0.088 90 g of AgCl. In her time (1900), the atomic mass of Ag was known to be 107.8 and that of Cl
was 35.4. From these values, find the atomic mass of Ra that Marie Curie would have calculated.

Short Answer

Step by step solution

calculate moles of AgCl and Ra:

Calculate the molecular mass of RaCl2:

Calculate the atomic mass of Ra:

One App. One Place for Learning.

Most popular questions from this chapter

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91影视

Marie Curie dissolved 0.091 92 g of RaCl2 and treated it with excess AgNO3to precipitate 0.088 90 g of AgCl. In her time (1900), the atomic mass of Ag was known to be 107.8 and that of Clwas 35.4. From these values, find the atomic mass of Ra that Marie Curie would have calculated.

Short Answer

Step by step solution

calculate moles of AgCl and Ra:

Calculate the molecular mass of RaCl2:

Calculate the atomic mass of Ra:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Chemical Analysis

Making Measurements

Chemistry Branches

Chemical Reactions

Kinetics

Study anywhere. Anytime. Across all devices.

Marie Curie dissolved 0.091 92 g of RaCl₂ and treated it with excess AgNO₃to precipitate 0.088 90 g of AgCl. In her time (1900), the atomic mass of Ag was known to be 107.8 and that of Cl
was 35.4. From these values, find the atomic mass of Ra that Marie Curie would have calculated.