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The standard free energy change for the formation of H2(g)=12O2(g) from H2O(l) is ∆G°=+237.13KJ The reactions are

cathode:2H2O+2e-⇌H2(g)+20H-Anode:H2O⇌12O2(g)+2H++2e-

Calculate the standard voltageE°needed to decompose water into its elements by electrolysis. What does the word standard mean in this question?

Short Answer

Expert verified
  • The standard voltage E = -1.229 V needed to decompose water into its elements by electrolysis.

Step by step solution

01

Definition of Standard free energy:

  • The standard free energy of a substance represents the free energy change associated with the formation of the substance from the elements in their most stable forms as they exist under standard conditions.
02

Step 2: Method of calculating Standard Voltage:

We can calculate standard voltage using this equation:

∆G=-n.F.E

So, the is,

E=-∆Gn.FE=-237.13.103j2.96485C/molE=--1.229V

03

Elucidating the word Standard:

  • The word standard mean that the reluctant and products are in standard states.

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Most popular questions from this chapter

A dilute Na2SO4solution is to be electrolyzed with a pair of smooth Pt electrodes at a current density of 100A/m2and a current of 0.100A. The products areH2(g)andO2(g)at1.00barandatbar. Calculate the required voltage if the cell resistance is2.00Ωand there is no concentration polarization. What voltage would be required if the Pt electrodes were replaced by Au electrodes?

What is a Clark electrode, and how does it work?

Explain how the endpoint is detected in a Karl Fischer titration in Figure 17-35.

17-17. The experiment in Figure 17 - 9 required 5.32mA for 864s for complete reaction of a5.00 - mLaliquot of unknown cyclohexene solution.

(a) How many moles of electrons passed through the cell?

(b) How many moles of cyclohexene reacted?

(c) What was the molarity of cyclohexene in the unknown?

Coulometric titration of sulfite in wine. Sulfur dioxide is added to many foods as a preservative. In aqueous solution, the following species are in equilibrium:

Bisulfite reacts with aldehydes in food near neutral pH:


Sulfite is released from the adduct in 2MNaOH and can be analyzed by its reaction with I3- to give I-and sulfate. ExcessI3- must be present for quantitative reaction.

Here is a coulometric procedure for analysis of total sulfite in white wine. Total sulfite means all species in Reaction and the adduct in Reaction . We use white wine so that we can see the color of a starch-iodine end point.

1. Mix 9.00 mL of wine plus 0.8gNaOH and dilute to 10.00mL. The releases sulfite from its organic adducts.

2. Generate I3-at the working electrode (the anode) by passing a known current for a known time through the cell in Figure 17 - 10. The cell containsofacetate buffer () plus. In the cathode compartment, is reduced to H2+OH-. The frit retards diffusion of into the main compartment, where it would react with I3- to giveIO-.

3. Generate I3- at the anode with a current of for.

4. Inject 2.000mL of the wine/ solution into the cell, where the sulfite reacts with leaving excess.

5. Add of thiosulfate to consume by Reaction and leave excess thiosulfate.

6. Add starch indicator to the cell and generate freshI3- with a constant current of 10.0mA. A time of 131s was required to consume excess thiosulfate and reach the starch end point.

(a) In what pH range is each form of sulfurous acid predominant?

(b) Write balanced half-reactions for the anode and cathode.

(c) At pH 3.7, the dominant form of sulfurous acid isand the dominant form of sulfuric acid is HSO42-. Write balanced reactions between andand between I3-and HSO3-thiosulfate.

(d) Find the concentration of total sulfite in undiluted wine.

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