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Chapter 6: Q13 P (page 142)

Henry's law states that the concentration of a gas dissolved in a liquid is proportional to the pressure of the gas. This law is a consequence of the equilibrium

X(g)鈬�KhX(aq)Kh=[x]pX

where Khis called the Henry's law constant. For the gasoline additive MTBE, Kh=1.71M/bar . Suppose we have a closed container with aqueous solution and air in equilibrium. If the concentration of MTBE in the water is 1.00x102ppm (=100渭驳MTBE/gsolution鈮�100渭驳/mL), what is the pressure of MTBE in the air?

CH3-O-C(CH3)3Methyl- -butyl ether (MTBE, FM 88.15)

Short Answer

Expert verified

The pressure of MTBE in the gas phase was calculated as 0.663 mbar .

Step by step solution

01

The concept used.

Henry's law:

This law states that the concentration of a gas dissolved in a liquid is directly proportional to the pressure of the gas. Henry's law is a sign of equilibrium.

Ag鈬�KhAaqKh=APA

here,

Kh is Henry's law constant.

02

The pressure of MTBE in gas phase

Henry's law constant for gasoline = 1.71M/bar

The concentration of gasoline in the water is1.00脳102ppm

The concentration of gasoline in the solution is 100渭g/mL=100mg/L

The molarity of MTBE,

Molarity=0.100g/L88.15g/mol=1.134脳10-3M

Therefore, the pressure of MTBE present in the gas phase:

Pressure=concerntrationKh=1.134脳10-3M1.71M/bar=0.663mbar

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