/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q74P Rank the following species in ea... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q74P (page 451)

Rank the following species in each set from best nucleophile to poorest nucleophile.

Short Answer

Expert verified

As the size of an atom is increased the more easily it can break the bond from its compound and behave as nucleophile.

Bigger size atom has more bond length so it can break easily the bond from its compound and attach with other compound.

Step by step solution

01

Reactivity depends upon size

As the size of an atom is increased the more easily it can break the bond from its compound and behave as nucleophile.

Bigger size atom has more bond length so it can break easily the bond from its compound and attach with other compound.

02

Final answer

As sulphur has bigger size than oxygen and in last nucleophile electrons will delocalize so it is not easy to break the bond.

In second nucleophile electrons will delocalize so it is not easy to break the bond.

Nitrogen is less electronegative than oxygen.

Bigger the size better is the nucleophile.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Why do cis-1-bromo-2-ethylcyclohexane and trans-1-bromo-2-ethylcyclohexane form different major products when they undergo an E2 reaction?

You were told in Section 7.11 that is best to use a methyl halide or a primary alkyl halide for the reaction of an acetylide ion with an alkyl halide. Explain why this is so.

Draw the substitution products for each of the following reactions; if the products can exist as stereoisomers, show what stereoisomers are obtained:

a. ( R )-2-bromopentane + CH3O-

b. ( R )-3-bromo-3-methylheptane + CH3OH

c. benzyl chloride + CH3CH2OH

d. allyl chloride + CH3OH

e. 1-bromo-2-butene + CH3O-

f. 1-bromo-2-butene + CH3OH

a. Explain why the reaction of an alkyl halide with ammonia gives a low yield of primary amine.

b. Explain why a much better yield of primary amine is obtained from the reaction of an alkyl halide with an azide ion (-N3), followed by catalytic hydrogenation. (Hint: An alkyl azide is not nucleophilic.)

Draw the structure of DDE.
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Physical Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Nuclear Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.