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Magazine Chapter 4: Q48E (page 143)
Identify whether each of the structure in the second row is an enantiomer of, is a diastereomer of, or is identical to the structure in the top row.
Short Answer
Compound A in the second row is an enantiomer of the top row compound. Because in compound A, there are two chiral carbons (represented by *), A is mirror image of the top compound and both mirror images are non-superimposable on each other.
Step by step solution
Step: 1 What are enantiomers:
A compound with one or more chiral center, form mirror image and if both, compound and its mirror image are non-superimposable on each other thus, both are called enantiomers of each other or stereoisomers.
Step:2 Explanation
Compound A, has two chiral centers means there are two carbon present which have four different groups attached to it. Chiral center or carbon is represented by *.
Now, as we form its mirror image we get same compound in top row and both are non-superimposable images. Thus, compound A is enantiomer of compound in top row.
Both are non-superimposable images at 00 rotation or at 180 0rotation.
Step:3 Conclusion
Thus, compound A is an enantiomer of the compound in the top row because compound A is a mirror image of the compound at the top row, and both are non-superimposable images.
Thus, compound D is identical to the compound in the top row because compound D after rotating 600, we get the same compound as a compound in the top row.
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