/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q23-P (a) Compute the heats of reacti... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Compute the heats of reaction for abstraction of a primary hydrogen and a secondary hydrogen from propane by a fluorine radical.

(b) How selective do you expect free-radical fluorination to be?

(c) What product distribution you expect to obtain from the free-radical fluorination of propane?

Short Answer

Expert verified

(a) For abstraction of primary hydrogen by a fluorine radical,ΔH = -159  kJ/mol

For abstraction of secondary hydrogen by a fluorine radical,ΔH = -172  kJ/mol

(b) Free-radical fluorination is nearly non-selective.

(c) The second reaction has more negative change in enthalpy which implies that it is more feasible. Secondary carbon is more easily fluorinated.

Step by step solution

01

Free radicals

An atom or group of atoms containing odd or unpaired electrons is known as free radical. The unpaired electron is represented by a single unpaired dot in the formula. Free radicals are electrically neutral. They are highly reactive species formed by homolytic fission of a covalent bond

02

Steps involved in free radical chain reaction

In a free-radical chain reaction, free radicals are generally created in the initiation step. A free radical and a reactant are combined to yield a product in the propagation step. Lastly, the number of free radicals generally decreases in the termination step.

03

Bond dissociation enthalpy (BDE)

BDE is the amount of enthalpy required to break a bond homolytically in such a way that each bonded atom retains one of the bond’s two electrons.

Mathematically,

Δ±á0=∑(BDE  of  bonds  broken)-∑(BDE  of  bonds  formed)

04

Primary hydrogen  (10)

Primary hydrogen is hydrogen that resides on a carbon which is only attached to one carbon atom.

05

Secondary hydrogen  (20)

Secondary hydrogen is hydrogen that resides on a carbon which is only attached to two carbon atoms.

06

Explanation

(a)

abstraction of primary hydrogen by a fluorine radical

breaking  primary  C-H  bond: 410  kJ/molforming     F-H  bond  :  -569   kJ/molΔH = 410 kJ/mol + (-569kJ/mol) = -159  kJ/mol

abstraction of secondary hydrogen by fluorine radical

breaking  secondary  C-H  bond: 397  kJ/molforming     F-H  bond  :  -569   kJ/molΔH = 397 kJ/mol + (-569kJ/mol) = -172  kJ/mol

(b) Free-radical fluorination is nearly non-selective.

(c)

products from free-radical fluorination of propane

The second reaction has more negative change in enthalpy which implies that it is more feasible. Secondary carbon is more easily fluorinated.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) When n-heptaneburns in a gasoline engine, the combustion process takes place too quickly. The explosive detonation makes a noise called knocking. When 2,2,4 trimethylpentane (isooctane) is burned, combustion takes place in a slower, more controlled manner. Combustion is a free-radical chain reaction, and its rate depends on the reactivity of the free-radical intermediates. Explain why isooctane has less tendency to knock than doesn-heptane

(b) Alkoxy radicals (R-O)are generally more stable than alkyl (R) radicals. Write an equation showing an alkyl free radical (from burning gasoline) abstracting a hydrogen atom from tert-butyl alcohol,(CH3)3COH. Explain whytert-butyl alcohol works as an antiknock additive for gasoline.

(c) Use the information in Table 4-2 (page 203) to explain why toluene (PhCH3) has a very high-octane rating of 111. Write an equation to show how toluene reacts with an alkyl free radical to give a relatively stable radical.

For each compound, predict the major product of free-radical bromination. Remember that bromination is highly selective, and only the most stable radical will be formed.

(a) cyclohexane

(b) methylcyclopentane

(c) decalin

(d) hexane

(e)

(f)

In the presence of a small amount of bromine, the following light -promoted reaction has been observed.

(a) Write a mechanism for this reaction. Your mechanism should explain how both products are formed. (Hint: Notice which H atom has been lost in both products)

(b) Explain why only this one type of hydrogen atom has been replaced, in preference to any of the other hydrogen atoms in the starting material.

Question: (a) Write the propagation steps leading to the formation of dichloromethane (CH2Cl2).

(b) Explain why free-radical halogenation usually gives mixture of products.

(c) How could an industrial plant control the proportions of methane and chlorine to favor production of CCl4? To favor production of CH3Cl?

(a) Draw the reaction-energy diagram for the following reverse reaction:

(b) What is the activation energy for this reverse reaction?

(c) What is the heat of reaction (Δ H0 )for this reverse reaction?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.