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(a) Based on what you know about the relative stabilities of alkyl cations and benzylic cations, predict the product of addition of HBr to 1-phenylpropene.

(b) Propose a mechanism for this reaction.

(c) Based on what you know about the relative stabilities of alkyl radicals and benzylic radicals, predict the product of addition of HBr to 1-phenylpropene in the presence of a free-radical initiator.

(d) Propose a mechanism for this reaction.

Short Answer

Expert verified

猞 Benzylic cations are more stable than alkyl cations because of resonance. The product of the addition of HBr to 1-phenylpropene is 1-bromo-1-phenylpropane.

猞 The mechanism:

猞 Benzylic radicals are more stable than alkyl radicals because of resonance. The product of the addition of HBr to 1-phenylpropene in presence of a free radical initiator is 2-bromo-1-phenylpropane.

猞 The mechanism:

Step by step solution

01

Radicals

An atom, molecule, or ion that comprises at least one unpaired valence electron is known as a free radical. Unpaired electrons present in radicals make them highly chemically reactive.

02

Subpart (a)

The Benzylic cations are stabilized by the resonance (+R effect) which makes them more stable than alkyl cations. The alkyl cations on the other hand are stabilized by the +I (inductive) effect only.

The product of the addition of HBr to 1-phenylpropene is 1-bromo-1-phenylpropane.

03

Subpart (b) Mechanism of the reaction in presence of a free radical initiator.

The hydrohalogenation of an alkene with HBr is shown below.

Here, the benzylic cation is more stable than the secondary cation. Therefore, the major product formed is 1-bromo-1-phenylpropane.

04

Subpart (c)

The benzylic radicals are more stable than alkyl radicals because of resonance (+R effect).

The benzylic radical is formed when bromine gets added first to the second carbon.

Later, the free H-radical goes to carbon radical to form 2-bromo-1-phenylpropane.

Hence, the product of the addition of HBr to 1-phenylpropene in presence of a free radical initiator is 2-bromo-1-phenylpropane.

05

Subpart (d) Mechanism of the reaction in presence of a free radical initiator

In the initiation step, the free radicals are formed in presence of light.

The free radicals are reactive and unstable. As soon as the benzylic radical is formed, the hydrogen radical goes to it to stabilize the compound and decrease the energy.

Firstly, bromine is added and then H-radical comes in. The reaction goes as;

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Most popular questions from this chapter

Predict the major products of treating the following compounds with hot, concentrated potassium permanganate, followed by acidification with dilute HCl.

(a) isopropylbenzene

(b) p-xylene

(c) tetralin

Propose products (if any) and mechanisms for the following AICI3-catalyzed reactions:

猞 chlorocyclohexane with benzene

猞 methyl chloride with anisole

猞 3-chloro-2,2-dimethylbutane with isopropylbenzene

Which reactions will produce the desired product in good yield? You may assume that aluminum chloride is added as a catalyst in each case. For the reactions that will not give a good yield of the desired product, predict the major products.

Reagents Desired Product

(a) benzene + n-butyl bromide n-butylbenzene

(b) ethylbenzene + tert-butyl chloride p-ethyl-tert-butylbenzene

(c) bromobenzene + ethyl chloride p-bromoethylbenzene

(d) benzamide (PhCONH3) + CH3 CH2 CI p-ethylbenzamide

(e) toluene + HNO3, H2SO4 , heat 2,4,6-trinitrotoluene (TNT)

Starting with benzene and any other reagents you need, show how you would synthesize the compound shown here. (Hint: Consider a Pd-catalyzed coupling for the final step).

Unlike most other electrophilic aromatic substitutions, sulfonation is often reversible. When one sample of toluene is sulfonated at 0 掳C and another sample is sulfonated at 100 掳C, the following ratios of substitution products result:

(a) Explain the change in the product ratios when the temperature is increased.

(b) Predict what will happen when the product mixture from the reaction at 0 掳C is heated to 100 掳C.

(c) Because the SO3Hgroup can be added to a benzene ring and removed later, it is sometimes called a blocking group. Show how 2,6-dibromotoluene can be made from toluene using sulfonation and desulfonation as intermediate steps in the synthesis

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