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To practice working through the early parts of a multistep synthesis, devise syntheses of

(a) pentan-3-one from alcohols containing no more than three carbon atoms.

(b) 3-ethylpentan-2-one from compounds containing no more than three carbon atoms.

Short Answer

Expert verified

(a)

(b)

Step by step solution

01

Multiple-step synthesis

It is carried out by more than one step and forms multiple intermediate compounds. It is the process were the complex product is formed from multiple steps using readily available compounds.

02

Synthesis

(a) When propanol is treated with 1 equivalent of NaOCl, it forms propanal. Aldehydes, when reacted with Grignard reagent, form secondary alcohol. Therefore, propanal reacts with ethyl magnesium bromide followed by hydrolysis from pentan-3-ol. Pentan-3-ol is treated with NaOCl and HOAc to form pentan-3-one.

Formation of pentan-3-one

(b) When propanoyl chloride is treated with ethyl magnesium bromide followed by hydrolysis form 3-ethyl-pentan-3-ol. 3-ethyl-pentan-3-ol treated with sulphuric acid undergoes dehydration to form 3-ethyl-pentan-2-ene, which on further reaction with BH3. THF and H2O2, HO- form 3-ethyl-pentan-2-ol. 3-ethyl-pentan-2-ol treated with NaOCl and HOAc forms 3-ethylpentan-2-one.

Formation of 3-ethylpentan-2-one

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Most popular questions from this chapter

When 1-cyclohexylethanol is treated with concentrated aqueous, the major product is 1-bromo-1-ethylcyclohexane.

(a)Propose a mechanism for this reaction.

(b) How would you convert 1-cyclohexylethanol to (1-bromoethyl)cyclohexane in good yield?

Show how you would accomplish the following synthetic conversions

(a)

(b)

(c)

(d)

The compound shown below has three different types of OH groups, all with different acidities. Show the structure produced after this compound is treated with different amounts of NaH followed by a methylating reagent. Add a brief explanation.

(a)1 equivalent of NaH, followed by 1 equivalent of CH3l and heat

(b)2 equivalents of NaH, followed by 2 equivalents of CH3l and heat

(c) 3 equivalents of NaH, followed by 3 equivalents of CH3l and heat

Contrast the mechanism of the two preceding reactions, the dehydration and condensation of ethanol.

Both cis- and trans-2-methylcyclohexanol undergo dehydration in warm sulfuric acid to give 1-methylcyclohexene as the major alkene product. These alcohols can also be converted to alkenes by tosylation usingand pyridine, followed by elimination using KOC(CH3)3as a strong base. Under these basic conditions, the tosylate of cis-2-methylcyclohexanol eliminates to give mostly 1-methylcyclohexene, but the tosylate of trans-2-methylcyclohexanol eliminates to give only 3-methylcyclohexene. Explain how this stereochemical difference in reactants controls a regiochemical difference in the products of the basic elimination, but not in the acid-catalyzed elimination.

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