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NMR spectra for two compounds are given here, together with the molecular formulas. Each compound is a ketone or an aldehyde. In each case, show what characteristics of the spectrum imply the presence of a ketone or an aldehyde, and propose a structure for the compound.

Short Answer

Expert verified

Structure obtained from the given spectrum is,

C9H10Ohas five elements of unsaturation. 1Hdoublet with very small coupling constant is observed at chemical shift value 9.7 indicates aldehydic hydrogen next to data-custom-editor="chemistry" CH. data-custom-editor="chemistry" 5Hmultiple peaks at chemical shift value 7.2-7.4 indicates a monosubstituted benzene. 1Hmultiplet at chemical shift value 3.6 and 3Hdoublet at chemical shift value 1.4 indicates CHCH3. Combining all the fragments together, we get the proposed structure to be 2-phenylpropanal.

Step by step solution

01

Step-1. Information about the structure from given spectrum:

C9H10Ohas five elements of unsaturation. 1Hdoublet with very small coupling constant is observed at chemical shift value 9.7 indicates aldehydic hydrogen next to CH. 5Hmultiple peaks at chemical shift value 7.2-7.4 indicates a monosubstituted benzene. 1Hmultiplet at chemical shift value 3.6 and 3Hdoublet at chemical shift value 1.4 indicates CHCH3.

02

Step-2. Structure determination:

By combining all the fragements from the data obtained from the given spectrum we have,

The only structure possible from the data and fragments will be,

The splitting of the hydrogen on carbon-2 which is next to the aldehyde in the obtained structure looks like a quartet due to splitting from adjacent methyl group. A closer examination of the peaks shows that each peak of the quartet is split into two peaks and this is due to splitting from the aldehydic hydrogen. The aldehyde hydrogen and the methyl hydrogens are not equivalent so it is expected that coupling contants are not equal.

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Most popular questions from this chapter

Show how you would accomplish the following synthetic conversions by adding an organolithium reagent to an acid.

Show how the following transformations may be accomplished in good yield. You may use any additional reagents that are needed.

(a) bromobenzene → propiophenone

(b) CH3CH2CN → heptan-3-one

(c) benzoic acid → phenyl cyclopentyl ketone

(d) 1-bromo-hept-2-ene → oct-3- enal

Question: The family of macrolide antibiotics all have large rings (macrocycle) in which an ester is what makes the ring; a cyclic ester is termed as a lactone. One example is amphotericin B, used as an anti-fungal treatment of last resort because of its liver and heart toxicity. Professor Martin Burke of the University of Illnois has been making analogs to retain the antifungal properties but without the toxicity, including this structure published in 2015. (Nature Chemical Biology, (2015) doi: 10.1038/nchembio.1821). The carboxylate of amphotericin B has been replaced with the urea group (shown in red).

(a) Where is the lactone group that forms the ring?

(b) Two groups are circled. What type of functional group are they? Explain.

(a) Simple aminoacetals hydrolyze quickly and easily in dilute acid. Propose a mechanism for hydrolysis of the following aminoacetal:

(b) The nucleosides that make up DNA have heterocyclic rings linked to deoxyribose by an aminoacetal functional group. Point out the aminoacetal linkages in deoxycytidine and deoxyadenosine.

(c) The stability of our genetic code depends on the stability of DNA. We are fortunate that the aminoacetal linkages of DNA are not easily cleaved. Show why your mechanism for part (a) does not work so well with deoxycytidine and deoxyadenosine.

Propose a mechanism for each cyanohydrin synthesis just shown.

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