/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q51P Phosgene is the acid chloride of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Phosgene is the acid chloride of carbonic acid. Although phosgene was used as a war gas in World War I, it is now used as a reagent for the synthesis of many useful products. Phosgene reacts like other acid chlorides, but it can react twice.

(a) Predict the products formed when phosgene reacts with excess propan-1-ol.

(b) Predict the products formed when phosgene reacts with 1 equivalent of ethanol, followed by 1 equivalent of aniline.

(c) Iso-butyloxycarbonyl chloride is an important reagent for the synthesis of peptides and proteins. Show how you would use phosgene to synthesize iso-butyloxycarbonyl chloride.

Isobutyloxycarbonyl chloride

Short Answer

Expert verified

(a)

Phosgene propan-1-ol propyl carbonochloridate

Formation of propyl carbonochloridate

(b)

Phosgene Ethanol Ethyl carbonochloridate

Formation of ethyl carbonochloridate

Ethyl carbonochloridate Aniline

Formation of the desired product

(c)

Formation of isobutyloxycarbonyl chloride

Step by step solution

01

Phosgene

Phosgene is an organic compound with chemical formula COLCl2and is used in industrial work for the production of polycarbonate plastics.

02

The reaction of phosgene with propan-1-ol

(a) Treatment of phosgene with the excess of propan -1-ol gives propyl carbonochloridate. This reaction proceeds through the nucleophilic acyl substitution. The reaction is represented as:

Phosgene propan-1-ol propyl carbonochloridate

Formation of propyl carbonochloridate

03

The reaction of phosgene with ethanol and aniline

When phosgene is reacted with ethanol, then it gives ethyl carbonochloridate. Here, the ethyl carbonochloridate reacts with aniline and gives the desired product.

04

Formation of the desired product

(b) The formation of the desired product is represented as:

Phosgene Ethanol Ethyl carbonochloridate

Formation of ethyl carbonochloridate

Ethyl carbonochloridate Aniline

Formation of the desired product

05

The reaction of phosgene with isobutyl alcohol

Phosgene reacts with isobutyl alcohol replacing one of the chloride groups of phosgene with an alcoholic group by removing the water molecule.

06

Formation of isobutyloxycarbonyl chloride

(c) The isobutyloxycarbonyl chloride is formed as given below:

Formation of isobutyloxycarbonyl chloride

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Arrange each group of compounds in order of increasing basicity.

  1. CH3COO-,CICH2C00- , and PhO-
  2. sodium acetylide, sodium amide, and sodium acetate
  3. sodium benzoate, sodium ethoxide, and sodium phenoxide
  4. pyridine, sodium ethoxide, and sodium acetate

Most of the Fischer esterification mechanism is identical with the mechanism of acetal formation. The difference is in the final step, where a resonance-stabilized carbocation loses a proton to give the ester. Write mechanisms for the following reactions, with the comparable steps directly above and below each other. Explain why the final step of the esterification (proton loss) cannot occur in acetal formation, and show what happens instead.

Show how you would synthesize the following compounds, starting with acetylene and any compounds containing no more than four carbon atoms.

(a)hex-1-yne

(b)hex-2-yne

(c)cis-hex-2-ene

(d)trans-hex-2-ene

(e)1,1-dibromohexane

(f)2,2-dibromohexane

(g)pentanal, CH3CH2CH2CH2CHO

(h)pentan-2-one, CH3-CO-CH 2CH2 CH3

(i) (+/)-3,4-dibromohexane

(j)meso-butan-2,3-diol

(k)2-methylhex-3-yn-2-ol

Question: A carboxylic acid has two oxygen atoms, each with two nonbonding pairs of electrons.

  1. Draw the resonance forms of a carboxylic acid that is protonated on the hydroxy oxygen atom.
  2. Compare the resonance forms with those given previously for an acid protonated on the carbonyl oxygen atom.
  3. Explain why the carbonyl oxygen atom of a carboxylic acid is more basic than the hydroxy oxygen.

Show how you would accomplish the following syntheses. Some of these conversions may require more than one step.

(a) isopentyl alcohol isopentyl acetate (banana oil)

(b) 3-ethylpentanoic acid3-ethylpentanenitrile

(c) isobutylamineN-isobutylformamide

(d) ethyl acetate3-methylpentan-3-ol

(e) cyclohexylamineN-cyclohexylacetamide

(f) bromocyclohexanedicyclohexylmethano

(g)

(h)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.