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Chapter 23: PROBLEM 23.65 (page 1257)

Question. Retroviruses like HIV, the pathogen responsible for AIDS, incorporate an RNA template that is copied into DNA during infection. The reverse transcriptaseenzyme that copies RNA into DNA is relatively nonselective and error-prone, leading to a high mutation rate. Its lack of selectivity is exploited by the anti-HIV drug AZT (3’-azido-2’,3’-dideoxythymidine), which becomes phosphorylated and is incorporated by reverse transcriptase into DNA, where it acts as a chain terminator. Mammalian DNA polymerases are more selective, having a low affinity for AZT, so its toxicity is relatively low.

  1. Draw the structures of AZT and natural deoxythymidine.
  2. Draw the structure of AZT 5’-triphosphate, the derivative that inhibits reverse transcriptase.

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01

Retrovirus

A retrovirus is a biological term. It is a virus that uses RNA and has DNA intermediate in its life cycle.These are protein enveloped and one of the retroviruses is HIV, known as Human Immunodeficiency Virus.

02

Structure of AZT and natural deoxythymidine

AZT is an analog of thymidine deoxynucleoside and functions by inhibiting the HIV reverse transcriptase. Due to this, the progression of AIDS slows down and the virus's life cycle halts down. AZT is selective for HIV reverse transcriptase and blocks the activity of certain human polymerase enzymes

Structure of natural deoxythymidine

Structure of AZT

03

Structure of AZT 5’-triphosphate

AZT triphosphate inhibits DNA polymerase but has more affinity for HIV reverse transcriptase. It also inhibits HIV replication without affecting other functions of uninfected cells.

Structure of AZT 5’-triphosphate

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Most popular questions from this chapter

Erwin Chargaff’s discovery that DNA contains equimolar amounts of guanine and cytosine and also equimolar amounts of adenine and thymine has come to be known as Chargaff’s rule:

G = C and A = T

(a) Does Chargaff’s rule imply that equal amounts of guanine and adenine are present in DNA? That is, does G = A?

(b) Does Chargaff’s rule imply that the sum of the purine residues equals the sum of the pyrimidine residues? That is, does A + G = C + T?

(c) Does Chargaff’s rule apply only to double-stranded DNA, or would it also apply to each individual strand if the double helical strand were separated into its two complementary strands?

Emil Fischer synthesized L-gulose, an unusual aldohexose that reduces to give D-glucitol. Suggest a structure for this L sugar, and show how L-gulose gives the same alditol as D-glucose. (Hint: D-Glucitol has -CH2OHgroups at both ends. Either of these primary alcohol groups might have come from reduction of an aldehyde.)

Raffinose is a trisaccharide (C18H32O16) isolated from cottonseed meal. Raffinose does not reduce Tollens reagent, and it does not mutarotate. Complete hydrolysis of raffinose gives D-glucose, D-fructose, and D-galactose. When raffinose is treated with invertase, the products are D-fructose and a reducing disaccharide called melibiose. Raffinose is unaffected by treatment with a-galactosidase, but an α -galactosidase hydrolyzes it to D-galactose and sucrose. When raffinose is treated with dimethyl sulfate and base followed by hydrolysis, the products are 2,3,4-tri-O-methylglucose, 1,3,4,6-tetra-O-methylfructose, and 2,3,4,6-tetra-O-methylgalactose. Determine the complete structures of raffinose and melibiose and give a systematic name for melibiose.

H. G. Khorana won the Nobel Prize in Medicine in 1968 for developing the synthesis of DNA and RNA and for helping to unravel the genetic code. Part of the chemistry he developed was the use of selective protecting groups for the 5′ OH group of nucleosides.

The trityl ether derivative of just the 5′ OH group is obtained by reaction of the nucleoside with trityl chloride, MMT chloride, or DMT chloride and a base like Et3N. The trityl ether derivative can be removed in dilute aqueous acid. DMT derivatives hydrolyze fastest, followed by MMT derivatives, and trityl derivatives slowest.

(a) Draw the product with the trityl derivative on the 5′ oxygen.

(b) Explain why the trityl derivative is selective for the 5′ OH group. Why doesn’t it react at 2′ or 3′? (c) Why is the DMT group easiest to remove under dilute acid conditions? Why does the solution instantly turn orange when acid is added to a DMT derivative?

Draw the structures (using chair conformations of pyranoses) of the following disaccharides.

(a) 4-O-(α -D-glucopyranosyl)-D-galactopyranose

(b) α -D-fructofuranosyl-β -D-mannopyranoside

(c) 6-O-(β -D-galactopyranosyl)-D-glucopyranose

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