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Draw the electrophoretic separation of Trp, Cys, and His at pH 6.0.

Short Answer

Expert verified

At pH 6.0, tryptophan which is having isoelectric point of 5.9 has a charge of zero and thus, will not migrate. Cysteine which has isoelectric point of 5.0 has a partial negative charge and will move towards the anode. Histidine which has isoelectric point of 7.6 has a partial positive charge and thus, will move towards the cathode.

Step by step solution

01

Step-1. Electrophoretic separation and isoelectric point:

Electrophoresis can be defined as the migration and separation of charged particles (ions) under the application of electric field. The system consists of two electrodes of opposite charges that is, anode and cathode which are connected by the medium known as electrolyte. The isoelectric point is the pH of an aqueous solution of an amino acid at which the molecules on average have no net charge. In an acidic solution, amino acids exist as cation, thus the movement of amino acid will be towards cathode which is the negative electrode. Movement of amino acid will be towards anode in basic solution when amino acids exist as anion.

02

Step-2. Electrophoretic separation of Trp,  Cys, and His at pH 6.0:

The movement of amino acids towards anode or cathode will depend on the overall charge the amino acid is carrying at pH 6.0. At pH 6.0, tryptophan which is having isoelectric point of 5.9 has a charge of zero and thus, will not migrate. Cysteine which has isoelectric point of 5.0 has a partial negative charge and will move towards the anode which is the positive terminal. Histidine which has isoelectric point of 7.6 has a partial positive charge and thus, will move towards the cathode which is the negative terminal. That’s how the separation of amino acids is done electrophoretically.

Electrophoretic separation of Trp, Cys, and His at pH 6.0

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Most popular questions from this chapter

Write the complete structures for the following peptides. Tell whether each peptide is acidic, basic, or neutral.

  1. Methionylthreonine
  2. Threonylmethionine
  3. Arginylaspartyllysine
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There are many methods for activating a carboxylic acid in preparation for coupling with an amine. The following method converts the acid to an N-hydroxysuccinimide (NHS) ester.

(a) Explain why an NHS ester is much more reactive than a simple alkyl ester.

(b) Propose a mechanism for the reaction shown.

(c) Propose a mechanism for the reaction of the NHS ester with an amine, R-NH2

Draw the resonance forms of a protonated guanidino group and explain why arginine has such a strongly basic isoelectric point.

Histidine is an important catalytic residue found at the active sites of many enzymes. In many cases, histidine appears to remove protons or to transfer protons from one location to another.

(a) Show which nitrogen atom of the histidine heterocycle is basic and which is not.

(b) Use resonance forms to show why the protonated form of histidine is a particularly stable cation.

(c) Show the structure that results when histidine accepts a proton on the basic nitrogen of the heterocycle and then is deprotonated on the other heterocyclic nitrogen. Explain how histidine might function as a pipeline to transfer protons between sites within an enzyme and its substrate.

Show how the following amino acids might be formed in the laboratory by reductive amination of the appropriate α-ketoacid.

Phenylalanine (b) Cysteine (c) Serine (d) Alanine

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