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Propose a mechanism for the reaction of pent-1-yne with HBr in the presence of peroxides. Show why anti-Markovnikov orientation results.

Short Answer

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Anti-Markovnikov orientation results to form the more stable20free radical.

Step by step solution

01

Step-by-Step SolutionStep 1: Anti- Markovnikov rule

When the unsymmetrical reagent (HBr, HCl, etc) is added to an unsymmetrical alkene, the positive part of the unsymmetrical reagent goes to that unsaturated bond (double or triple) having a greater number of hydrogen atoms.

The product formed from such a reaction is governed by the anti-Markovnikov rule.

Anti- Markovnikov rule governs the product for many chemical reactions.

02

Mechanism for the reaction of pent-1-yne with HBr in the presence of peroxide 

In the initiation step, radicals are formed.

Initiation step

In the propagation step, the bromide radical adds to triple bond of pent-1-yne to generate alkyl radical on the secondary carbon atom, and then the secondary alkyl radical abstract hydrogen atom from HBr to generate product and bromide radical.

Mechanism showing the reaction of pent-1-yne with HBr in the presence of peroxides

03

Reason for anti-Markovnikov orientation

The anti- Markovnikov orientation result when pent-1-yne react with HBr in the presence of peroxide to form a more stable free radical. The more substituted radical is more stable; thus, 20radical is more stable than 10radical.

Hence, the bromine radical first attack forms a more stable 20radical forming the anti- Markovnikov oriented product.

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Most popular questions from this chapter

Question:The application box in the margin of page 473 states, 鈥淭he addition of an acetylide ion to a carbonyl group is used in the synthesis of ethchlorvynol, a drug used to cause drowsiness and induce sleep.鈥 Show how you would accomplish this synthesis from acetylene and a carbonyl compound.

ethchlorvynol

Oxidative cleavages can help to determine the positions of the triple bonds in alkynes.

(a) An unknown alkyne undergoes oxidative cleavage to give adipic acid and two equivalents of acetic acid. Propose a structure for the alkyne.

(b) An unknown alkyne undergoes oxidative cleavage to give the following triacid plus one equivalent of propionic acid. Propose a structure for the alkyne.

Disiamylborane adds only once to alkynes by virtue of its two bulky secondary isoamyl groups. Disiamylborane is prepared by the reaction of BH3. THF with an alkene.

(a) Draw the structural formulas of the reagents and the products in the preparation of disiamylborane.

(b) Explain why the reaction in part (a) goes only as far as the dialkylborane. Why is Sia3B not formed?

Question: Solved Problem 9-1 showed the synthesis of dec-3-yne by adding the hexyl group first, then the ethyl group. Show the reagents and intermediates involved in the other order of synthesis of dec-3-yne by adding the ethyl group first and the hexyl group last.

Propose a mechanism for the entire reaction of pent-1-yne with 2 moles of HBr. Show why Markovnikov鈥檚 rule should be observed in both the first and second additions of HBr.

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