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Consider the type of orbitals involved, and rank the following nitrogen compounds in order of decreasing basicity. Give the structure of their conjugate acids; and estimate their pKas from similar compounds in Appendix 4. Rank the conjugate acids in order of increasing acidity. (Hint: These two orders should be the same!)

Short Answer

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The residual part of acid after losing a proton (H+) will have a tendency to accept a proton (H+) . Therefore, it will behave as a base. These pairs of substances which differ from one another by a proton (H+) are known as conjugate acid-base pairs. Consider a general example of an acid:

Step by step solution

01

Conjugate acid-base pair

The residual part of acid after losing a proton (H+) will have a tendency to accept a proton (H+) . Therefore, it will behave as a base. These pairs of substances which differ from one another by a proton (H+) are known as conjugate acid-base pairs. Consider a general example of an acid:

02

Ka  and  pKa

Ka is known as the acid dissociation constant and its value indicates the relative strength of the acid. pKa is defined as the negative logarithm (base 10 ) of Ka. Mathematically, pKa= -logKa. pKa value of strong acids is usually zero or even negative while the pKa value of weaker acids are greater than 4.

03

Hybridization

The mixing of atomic orbitals to give equal number of symmetrically hybridized orbitals is known as hybridization. The different types of hybridization are sp , sp2 , sp3 , sp3d, sp3d2 or d2sp3, sp3d3. sp hybridization is linear with a bond angle of 1800, sp2 hybridization is trigonal planar with a bond angle of 1200and sp3 hybridization is tetrahedral with a bond angle of 109.50.

04

Explanation and calculation

Acidity of N-H bonds vary with hybridization in the order sp>sp2>sp3 which means that basicity will decrease in the order sp3>sp2>sp.

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Most popular questions from this chapter

The pKa of ascorbic acid (vitamin C, page 9) is 4.17 , showing that it is lightly more acidic than acetic acid (CH3COOH,pKa =4.74) .

(a)Show four different conjugate bases that would be formed by deprotonation of the four different OH groups in ascorbic acid.

(b) Compare the stabilities of these four conjugate bases, and predict which OH group of ascorbic acid is the most acidic.

(c) Compare the most stable conjugate base of ascorbic acid with the conjugate base of acetic acid, and suggest why these two compounds have similar acidities, even though ascorbic acid lacks the carboxylic acid (COOH ) group

Like nitrogen and carbon, oxygen also shows this same hybridization effect on acidity. Both of the following compounds can lose a proton from a positively charged oxygen with three bonds to give a conjugate base containing a neutral oxygen with two bonds. One of these structures has pKa = -2.4 , while the other has pKa = -8.0.

  1. Show the reaction of each compound with water.
  2. Match each structure with its pKa , and explain your choice.

N-Methylpyrrolidine has a boiling point of81οC, and piperidine has a boiling point of106οC.

  1. Explain the large difference (25οC) in boiling point for these two isomers.
  2. Tetrahydropyran has a boiling point of 88οC, and cyclopentanol has a boiling point of 141οC. These two isomers have a boiling point difference of 53οC.Explain why the two oxygen-containing isomers have a much larger boiling point difference than two amine isomers.
  3. N,N-Dimethylformamide has a boiling point of 150οC, and N-methylacetamide has a boiling point of 206οC, for a difference of 56οC.Explain why these two nitrogen-containing isomers have a much larger boiling point difference than the two amine isomers. Also explain why these two amides have higher boiling points than any of the other four compounds shown (two amines, an ether, and an alcohol).

The N-F bond is more polar than N-H bond, but NF3 has smaller dipole moment than NH3. Explain the curious result.

NH3: µ= 1.5 D, NF3: µ= 0.2D

The following compound can become protonated on any of the three nitrogen atoms. One of these nitrogens is much more basic than the others, however.

  1. Draw the important resonance forms of the products of protonation on each of the three nitrogen atoms.
  2. Determine which nitrogen atom is the most basic.

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