/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q14P Rank the following acids in decr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Rank the following acids in decreasing order of their acid strength. In each case, explain why the previous compound should be a stronger acid than the one that follows it.

Short Answer

Expert verified

Stronger electron-withdrawing groups stabilize the anion of the conjugate base more than weaker groups do, leading to stronger acids. Chlorine is more electronegative and a stronger withdrawing group than bromine, making chloropentanoic acid a stronger acid than bromopentanoic acid.

Step by step solution

01

     Step 1

Stronger electron-withdrawing groups stabilize the anion of the conjugate base more than weaker groups do, leading to stronger acids. Chlorine is more electronegative and a stronger withdrawing group than bromine, making chloropentanoic acid a stronger acid than bromopentanoic acid.

02

Step 2

Adding a chlorine atom to pentanoic acid increases its acidity, and the effect is larger if the chlorine atom is closer to the acidic group.

03

Step 3

In case of bromopentanoic acid, acidic effect is larger if the bromine atom is closer to the acidic group. Therefore 2-bromopentanoic acid is more acidic than 4-bromopentanoic acid.

04

Step 4

Multiple electron-withdrawing groups stabilize the conjugate base and increase the acidity more than a single group does. Therefore 2,2 dichloropentanoic acid is more acidic than 2-chloropentanoic acid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.