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Chapter 28: Question 28.64 (page 1150)

Draw the structure of a disaccharide formed from two mannose units joined by a 1-4鈫�伪glycosidic linkage.

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01

Disaccharide

Disaccharides constitute sugars generated when two monosaccharides are connected via a glycosidic linkage. Some examples of monosaccharides include maltose and lactose.

02

Glycosidic linkage

Glycosidic linkage or glycosidic bond constitutes a covalent bond that links a carbohydrate to another molecule. Molecules comprising a glycosidic bond are termed glycosides.

03

Structure of the disaccharide formed from two mannose units

The structure of a disaccharide generated by linking two mannose units is:

Disaccharides formed from two mannose units

The disaccharide is produced by alpha linkage as the -OH group is located below the ring. The formation of disaccharides also involves a condensation reaction. The water molecules are eliminated in the condensation reactions.

The structure of the mannose is:

Structure of mannose

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Most popular questions from this chapter

Draw a Haworth projection for each compound using the structures in Figures 28.4 and 28.5.

a. Identify the glycosidic linkage in disaccharide C, classify the glycosidic bond as 伪or尾, and use numbers to designate its location.

b. Identify the lettered compounds in the following reaction.

(a) Why can鈥檛 two purine bases (A and G) form a base pair and hydrogen bond to each other on two strands of DNA in the double helix? (b) Why is hydrogen bonding between guanine and cytosine more favorable than hydrogen bonding between guanine and thymine?

Deduce the structure of the disaccharide maltose from the following data.

[1]Hydrolysis yields D-glucose exclusively.

[2] Isomaltose is cleaved with -伪glycosidase enzymes.

[3] Isomaltose is a reducing sugar.

[4]Methylation with excess CH3I,Ag2Oand then hydrolysis withH3O+ forms two products:

(Both anomers are present.)

Convert each compound to a Fischer projection and label each stereogenic center as R or S.

(a.)

(b.)

(c.)

(d.)

(e.)

(f.)
See all solutions

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