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Glycogen phosphorylase catalyzes the removal of glucose from glycogen. The \(\Delta G^{\prime \circ}\) for this reaction is \(3.1 \mathrm{kJ} / \mathrm{mol}\) (a) Calculate the ratio of [Pi] to [glucose 1-phosphate] when the reaction is at equilibrium. (Hint: The removal of glucose units from glycogen does not change the glycogen concentration.) (b) The measured ratio [Pil/glucose 1-phosphate] in myocytes under physiological conditions is more than 100: 1 . What does this indicate about the direction of metabolite flow through the glycogen phosphorylase reaction in muscle? (c) Why are the equilibrium and physiological ratios different? What is the possible significance of this difference?

Short Answer

Expert verified
The equilibrium [Pi]/[G1P] ratio is 3.5:1, but physiologically it's 100:1, driving reaction forward.

Step by step solution

01

Understand the Reaction

The glycogen phosphorylase reaction removes glucose from glycogen, producing glucose-1-phosphate ( Pi + glycogen → glucose-1-phosphate + glycogen(n-1)). The standard change in Gibbs free energy, ΔG'°, for the reaction is +3.1 kJ/mol.
02

Use the Gibbs Free Energy Equation

At equilibrium, ΔG = ΔG'° + RTln(Q) = 0, where Q is the reaction quotient. Rearranging gives Q = e^(-ΔG'°/RT). Here, R is 8.314 J/mol·K (universal gas constant) and T is temperature in Kelvin (typically 298K for biological reactions).
03

Calculate the Equilibrium Constant (K_eq)

Using ΔG'° = 3.1 kJ/mol = 3100 J/mol, calculate; K_eq = e^(-3100 J/mol / (8.314 J/mol·K * 298 K)) ≈ e^(-1.25) ≈ 0.286.
04

Relate Equilibrium Constant to Concentrations

At equilibrium, K_eq = [glucose-1-phosphate]/[Pi]; since K_eq is 0.286, it implies the ratio [Pi]/[glucose-1-phosphate] at equilibrium is 1/K_eq ≈ 3.5.
05

Interpret Physiological Ratio

Given that the physiological ratio [Pi]/[glucose-1-phosphate] is more than 100:1, this indicates a significant excess of Pi, driving the reaction towards the formation of glucose-1-phosphate in physiological conditions.
06

Compare Equilibrium and Physiological Ratios

The difference between the equilibrium (3.5:1) and physiological ratio (100:1) indicates that cellular conditions strongly favor the forward reaction, likely due to continual consumption or conversion of glucose-1-phosphate, maintaining the gradient and ensuring metabolite flow.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
Every chemical reaction has a unique equilibrium constant, denoted as \(K_{eq}\). This constant is a number that gives us a snapshot of the balance between reactants and products when the reaction is at equilibrium.
In simpler terms, it tells us if the reaction favors the starting materials (reactants) or the ending substances (products).
For the Glycogen Phosphorylase reaction, removing glucose from glycogen, we use this concept to understand how much glucose-1-phosphate is produced compared to how much inorganic phosphate \([Pi]\) is left behind.To calculate \(K_{eq}\), use the Gibbs Free Energy equation at equilibrium:
  • \( \Delta G = \Delta G'^{\circ} + RT\ln(Q) = 0 \)
  • Rearranging gives \( Q = e^{-\Delta G'^{\circ}/RT} \)
By finding the equilibrium constant (approx. 0.286 for this reaction), we learn that the equilibrium favors the reactants more, shown by a larger amount of \([Pi]\) relative to glucose-1-phosphate.
This result can be interpreted through the ratio \([Pi]/[glucose-1-phosphate] \approx 3.5\).
This ratio helps predict how reactions behave under different conditions.
Gibbs Free Energy
Gibbs Free Energy is a thermodynamic concept that explains if a reaction can proceed spontaneously or not.
In essence, it tells us whether the reaction occurs under specific conditions and gives insights into energy usage or release.
The intrinsic energy of the Glycogen Phosphorylase reaction is described by the standard Gibbs Free Energy change (\(\Delta G^{\prime \circ}\)), which is measured at standard conditions.Mathematically, the relationship is:
  • \( \Delta G = \Delta G^{\prime \circ} + RT \ln(Q) \)
For our reaction, a \(\Delta G^{\prime \circ}\) of 3.1 kJ/mol means that it isn't spontaneously favorable under standard conditions.
Yet, in cells, reactions rarely occur under standard conditions.
Thus, understanding \(\Delta G^{\prime \circ}\) helps us see why the body needs to maintain conditions favoring the product (glucose-1-phosphate) formation.
This directional push is achieved by keeping a high \([Pi]\) to \([glucose-1-phosphate]\) ratio, as observed in physiological settings.
Metabolic Pathway
Metabolic pathways are the sequences of enzymatic reactions within our cells that convert molecules into other forms, producing energy or building materials needed for life.
Glycogenolysis, the breakdown of glycogen, involves Glycogen Phosphorylase catalyzing the removal of glucose units.
This enzyme-driven reaction is part of a larger network working together for energy regulation.The significance of the discrepancy between the equilibrium and physiological ratios \(([Pi]: [glucose-1-phosphate] = 100:1)\) shows how our body actively manages these pathways.
It reflects how cells strive to maximize the production of crucial molecules like glucose-1-phosphate.
Such regulation ensures a constant glucose supply for energy, especially crucial in active muscles.
  • The specific conditions in cells are shaped by additional factors, beyond mere concentration changes.
  • This creates the necessary gradients for flow, enabling pathways to meet the demands of varying cellular activities.
Overall, the divergence from equilibrium in living cells reflects adaptive mechanisms ensuring crucial metabolites are ready and available whenever energy is needed.

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Most popular questions from this chapter

A man with insulin-dependent diabetes is brought to the emergency room in a near-comatose state. While vacationing in an isolated place, he lost his insulin medication and has not taken any insulin for two days. (a) For each tissue listed below, is each pathway faster, slower, or unchanged in this patient, compared with the normal level when he is getting appropriate amounts of insulin? (b) For each pathway, describe at least one control mechanism responsible for the change you predict. Tissue and Pathways 1\. Adipose: fatty acid synthesis 2\. Muscle: glycolysis; fatty acid synthesis; glycogen synthesis 3\. Liver: glycolysis; gluconeogenesis; glycogen synthesis; fatty acid synthesis; pentose phosphate pathway

Between your evening meal and breakfast, your blood glucose drops and your liver becomes a net producer rather than consumer of glucose. Describe the hormonal basis for this switch, and explain how the hormonal change triggers glucose production by the liver.

Researchers can manipulate the genes of a mouse so that a single gene in a single tissue either produces an inactive protein (a "knockout" mouse) or produces a protein that is always (constitutively) active. What effects on metabolism would you predict for mice with the following genetic changes: (a) knockout of glycogen debranching enzyme in the liver; (b) knockout of hexokinase IV in liver; (c) knockout of FBPase- 2 in liver; (d) constitutively active FBPase-2 in liver; (e) constitutively active AMPK in muscle; (f) constitutively active ChREBP in liver?

The intracellular use of glucose and glycogen is tightly regulated at four points. To compare the regulation of glycolysis when oxygen is plentiful and when it is depleted, consider the utilization of glucose and glycogen by rabbit leg muscle in two physiological settings: a resting rabbit, with low ATP demands, and a rabbit that sights its mortal enemy, the coyote, and dashes into its burrow. For each setting, determine the relative levels (high, intermediate, or low) of AMP, ATP, citrate, and acetyl-CoA and describe how these levels affect the flow of metabolites through glycolysis by regulating specific enzymes. In periods of stress, rabbit leg muscle produces much of its ATP by anaerobic glycolysis (lactate fermentation) and very little by oxidation of acetyl-CoA derived from fat breakdown.

Measuring the concentrations of metabolic inter-mediates in a living cell presents great experimental difficulties-usually a cell must be destroyed before metabolite concentrations can be measured. Yet enzymes catalyze metabolic interconversions very rapidly, so a common problem associated with these types of measurements is that the findings reflect not the physiological concentrations of metabolites but the equilibrium concentrations. A reliable experimental technique requires all enzyme-catalyzed reactions to be instantaneously stopped in the intact tissue so that the metabolic intermediates do not undergo change. This objective is accomplished by rapidly compressing the tissue between large aluminum plates cooled with liquid nitrogen \(\left(-190^{\circ} \mathrm{C}\right),\) a process called freeze- clamping. After freezing, which stops enzyme action instantly, the tissue is powdered and the enzymes are inactivated by precipitation with perchloric acid. The precipitate is removed by centrifu-gation, and the clear supernatant extract is analyzed for metabolites. To calculate intracellular concentrations, the intracellular volume is determined from the total water content of the tissue and a measurement of the extracellular volume. The intracellular concentrations of the substrates and products of the phosphofructokinase- 1 reaction in isolated rat heart tissue are given in the table below. $$\begin{array}{lc} \text { Metabolite } & \text { Concentration }(\mu \mathrm{M})^{*} \\ \hline \text { Fructose } 6 \text { -phosphate } & 87.0 \\ \text { Fructose } 1,6 \text { -bisphosphate } & 22.0 \\ \mathrm{ATP} & 11,400 \\ \mathrm{ADP} & 1,320 \\ \hline \end{array}$$ (a) Calculate \(Q, \text { [fructose } 1,6 \text { -bisphosphate }][\mathrm{ADP}] /\) [fructose \(6 \text { -phosphate }][\mathrm{ATP}],\) for the PFK-1 reaction under physiological conditions. (b) Given a \(\Delta G^{\prime \circ}\) for the PFK-1 reaction of \(-14.2 \mathrm{kJ} / \mathrm{mol}\) calculate the equilibrium constant for this reaction. (c) Compare the values of \(Q\) and \(K_{\mathrm{eq}^{\prime}}^{\prime}\) Is the physiological reaction near or far from equilibrium? Explain. What does this experiment suggest about the role of PFK-1 as a regulatory enzyme?

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