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You fill a balloon with helium gas to a volume of \(2.68 \mathrm{~L}\) at \(23^{\circ} \mathrm{C}\) and \(789 \mathrm{mmHg}\). Now you release the balloon. What would be the volume of helium if its pressure changed to \(632 \mathrm{mmHg}\) but the temperature were unchanged?

Short Answer

Expert verified
The volume of helium is approximately 3.35 L at 632 mmHg.

Step by step solution

01

Identify the Given Variables

We have an initial volume \( V_1 = 2.68 \text{ L} \), initial pressure \( P_1 = 789 \text{ mmHg} \), final pressure \( P_2 = 632 \text{ mmHg} \), and the temperature is constant. We need to find the final volume \( V_2 \).
02

Use Boyle's Law

According to Boyle's Law, which deals with the pressure and volume of a gas at a constant temperature, the relationship can be written as \( P_1 V_1 = P_2 V_2 \). This equation will allow us to find the unknown volume \( V_2 \).
03

Rearrange the Formula

Rearrange the formula to solve for \( V_2 \): \[V_2 = \frac{P_1 V_1}{P_2}\]
04

Substitute the Known Values

Substituting the known values into the equation gives:\[V_2 = \frac{789 \text{ mmHg} \times 2.68 \text{ L}}{632 \text{ mmHg}}\]
05

Perform the Calculation

Calculate \( V_2 \) using the values provided:\[ V_2 = \frac{789 \times 2.68}{632} \]This simplifies to \( V_2 \approx 3.35 \text{ L} \).
06

Conclusion

The volume of the helium when the pressure changes to 632 mmHg, while the temperature remains constant, is approximately 3.35 L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Gas laws are a fundamental topic in chemistry that describe how gases behave under different conditions of pressure, volume, and temperature. They are essential for understanding how gases interact and change in response to changes in their environment. Boyle's Law, Charles's Law, and Avogadro's Law are some of the well-known gas laws. These laws are combined into the Ideal Gas Law, which provides a complete description of the behavior of ideal gases.

The most famous among these, Boyle's Law, deals with the relationship between pressure and volume at a constant temperature. This concept is crucial when working with gases, as it allows us to predict how a gas will react when contained in a fixed volume and subjected to external pressure changes. Understanding these fundamental principles enables us to apply them in various practical and scientific contexts, such as designing balloons, predicting weather patterns, and even in medical fields like respiratory therapy.
Pressure-Volume Relationship
The pressure-volume relationship is a key component of Boyle's Law. It states that for a given amount of gas at constant temperature, the pressure exerted by the gas is inversely proportional to the volume it occupies. In mathematical terms, this relationship can be expressed as \[P_1 V_1 = P_2 V_2\]where:
  • \(P_1\) is the initial pressure,
  • \(V_1\) is the initial volume,
  • \(P_2\) is the final pressure,
  • \(V_2\) is the final volume.
This equation implies that if the pressure on a gas increases, its volume decreases, and vice versa, provided the temperature remains constant. This principle is very intuitive, as it resembles squeezing a balloon; the more you squeeze, the smaller it gets. In our exercise, the balloon's helium gas expands as the pressure decreases, illustrating Boyle's Law in action. Understanding this relationship is necessary to predict how gases will behave in closed systems.
Helium Gas
Helium is a colorless, odorless, and tasteless inert gas, known for its lower density compared to air, which is why it makes balloons float. As a noble gas, helium does not easily react with other elements, giving it a stable, nonreactive nature that makes it safe for various applications, from party balloons to cooling superconducting magnets in medical MRI machines.

When utilizing Boyle's Law with helium, its inert characteristics do not affect the basic operations of the gas law. The ideal gas approximation can typically be applied to helium because it behaves almost ideally even at varying pressures and temperatures. Hence, when solving problems involving helium, we assume it follows Boyle's Law closely, as in the example exercise, where the gas expands due to a decrease in external pressure.
Constant Temperature
The concept of constant temperature is central to Boyle's Law application. It refers to a thermodynamic condition where the gas does not absorb or release heat energy, maintaining a steady temperature throughout the process. This means that the internal energy remains unchanged while the gas expands or contracts.

In practical terms, maintaining a constant temperature requires either an insulated system or monitoring to ensure that any external influences do not lead to temperature changes. This assumption allows the pressure-volume relationship to hold true as stated in Boyle's Law. In our balloon exercise, assuming the temperature is constant lets us use the original pressures and volumes directly in our calculations without additional adjustments for thermal expansion or contraction. This simplifies our prediction of how the helium will behave when subjected to different pressures.

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Most popular questions from this chapter

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A sample of sodium peroxide, \(\mathrm{Na}_{2} \mathrm{O}_{2}\), was reacted with an excess of water. $$ 2 \mathrm{Na}_{2} \mathrm{O}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 4 \mathrm{NaOH}(a q)+\mathrm{O}_{2}(g) $$ All of the sodium peroxide reacted, and the oxygen was collected over water at \(21^{\circ} \mathrm{C}\). The barometric pressure was 771 \(\mathrm{mmHg}\). The apparatus was similar to that shown in Figure \(5.20 .\) However, the level of water inside the tube was \(25.0 \mathrm{~cm}\) above the level of water outside the tube. If the volume of gas in the tube is \(31.0 \mathrm{~mL}\), how many grams of sodium peroxide were in the sample?

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