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Suppose you had a \(3.15-\mathrm{L}\) sample of neon gas at \(21{ }^{\circ} \mathrm{C}\) and a pressure of \(0.951\) atm. What would be the volume of this gas if the pressure were increased to \(1.292 \mathrm{~atm}\) while the temperature remained constant?

Short Answer

Expert verified
The volume of the gas is approximately 2.319 L under the new pressure.

Step by step solution

01

Understand Boyle's Law

Boyle's Law states that for a given mass of gas at constant temperature, the product of the pressure and volume is a constant. In this problem, as the temperature remains constant, Boyle's Law can be applied. The formula is given as \( P_1 V_1 = P_2 V_2 \), where \( P_1 \) and \( V_1 \) are the initial pressure and volume, and \( P_2 \) and \( V_2 \) are the final pressure and volume.
02

Identify Known Values

From the problem, we know the initial volume \( V_1 = 3.15 \, \text{L} \), the initial pressure \( P_1 = 0.951 \, \text{atm} \), and the final pressure \( P_2 = 1.292 \, \text{atm} \). We are tasked with finding the final volume \( V_2 \).
03

Rearrange Boyle's Law Formula

To find \( V_2 \), we need to rearrange the formula to solve for it: \( V_2 = \frac{P_1 V_1}{P_2} \). This will allow us to calculate the unknown volume under the new pressure condition.
04

Substitute Known Values into the Formula

Substitute the known values into the rearranged formula: \[ V_2 = \frac{0.951 \, \text{atm} \times 3.15 \, \text{L}}{1.292 \, \text{atm}} \].
05

Perform the Calculation

Calculate \( V_2 \) using the substituted values: \[ V_2 = \frac{2.99565 \, \text{L atm}}{1.292 \, \text{atm}} \approx 2.319 \, \text{L} \]. Thus, the volume of the gas decreases when the pressure is increased to 1.292 atm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Gas laws are a group of physical laws that describe the behavior of gases, particularly how they respond to changes in pressure, volume, and temperature. These laws provide a reliable framework for understanding how gases behave under different conditions. For students studying chemistry or physics, it's critical to understand gas laws as they explain many natural phenomena and are instrumental in industrial applications.
Some primary gas laws include:
  • Boyle's Law: Describes the inverse relationship between pressure and volume of a gas when the temperature is held constant.
  • Charles's Law: States that a gas's volume is directly proportional to its temperature when the pressure is kept constant.
  • Avogadro's Law: Indicates that the volume of a gas is directly proportional to the number of moles of gas at constant temperature and pressure.
  • Ideal Gas Law: Combines the other laws into one equation, expressed as \( PV = nRT \), where \( n \) is the number of moles, and \( R \) is the gas constant.
Understanding these laws helps us to predict how gases will react under certain conditions. This exercise focuses on Boyle's Law because the temperature is constant, and we are investigating changes in pressure and volume.
Pressure-Volume Relationship
The pressure-volume relationship of gases is elegantly described by Boyle's Law. This law tells us that for a given mass of gas at constant temperature, the volume of the gas is inversely proportional to its pressure.
In mathematical terms, Boyle's Law is expressed as:\[ P_1 V_1 = P_2 V_2 \]Where:
  • \( P_1 \) and \( V_1 \) represent the initial pressure and volume
  • \( P_2 \) and \( V_2 \) represent the new pressure and volume conditions
This means if you increase the pressure on the gas, its volume decreases, and vice versa, assuming the temperature remains constant. In our original exercise, this concept was vital to solving for the final volume \( V_2 \) after a pressure change.
For instance, if we start with a gas at a specific pressure and volume, increasing the pressure while keeping the temperature constant will see the volume decrease. This relationship is fundamental in understanding how gases can be compressed or expanded and is practically applied in various fields like pneumatics and meteorology.
Ideal Gas Behavior
Ideal gas behavior refers to the way gases respond under certain standard conditions that are summarized by the ideal gas law equation. While real gases do show ideal behavior under many conditions, they deviate at high pressures and low temperatures.
The ideal gas law is given by:\[ PV = nRT \]Where:
  • \( P \) is pressure
  • \( V \) is volume
  • \( n \) is the number of moles
  • \( R \) is the gas constant (approximately 0.0821 L·atm/mol·K for gases)
  • \( T \) is temperature in Kelvin
Resistance to ideal behavior often occurs due to molecular size and intermolecular forces, but Boyle's Law assumes these can be neglected at standard conditions. Therefore, Boyle's Law and similar equations work best for gases considered "ideal," which means the gas particles are assumed to move randomly without significant attractions or repulsions between them.
In the exercise, neon gas is treated as ideal because it follows Boyle’s Law under normal lab conditions, highlighting the usefulness of this concept in approximating gas behavior for calculations.

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Most popular questions from this chapter

A container is filled with \(16.0 \mathrm{~g}\) of \(\mathrm{O}_{2}\) and \(14.0 \mathrm{~g}\) of \(\mathrm{N}_{2}\). a. What is the volume of the container at STP? b. What is the partial pressure of the \(\mathrm{O}_{2}\) gas? C. What are the mole fraction and the mole percent of the \(\mathrm{N}_{2}\) in the mixture.

The density of air at \(20^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm}\) is \(1.205 \mathrm{~g} / \mathrm{L}\). If this air were compressed at the same temperature to equal the pressure at \(40.0 \mathrm{~m}\) below sea level, what would be its density? Assume the barometric pressure is constant at \(1.00 \mathrm{~atm} .\) The density of seawater is \(1.025 \mathrm{~g} / \mathrm{cm}^{3}\).

A rigid \(1.0\) - \(\mathrm{L}\) container at \(75^{\circ} \mathrm{C}\) is fitted with a gas pressure gauge. A \(1.0\) -mol sample of ideal gas is introduced into the container. a. What would the pressure gauge in the container be reading in \(\mathrm{mmHg}\) ? b. Describe the interactions in the container that are causing the pressure. c. Say the temperature in the container were increased to \(150^{\circ} \mathrm{C}\). Describe the effect this would have on the pressure, and, in terms of kinetic theory, explain why this change occurred.

An experiment calls for \(3.50\) mol of chlorine, \(\mathrm{Cl}_{2}\). What volume will this be if the gas volume is measured at \(34^{\circ} \mathrm{C}\) and \(4.00 \mathrm{~atm} ?\)

Consider the following setup, which shows identical containers connected by a tube with a valve that is presently closed. The container on the left has \(1.0 \mathrm{~mol}\) of \(\mathrm{H}_{2}\) gas; the container on the right has \(1.0 \mathrm{~mol}\) of \(\mathrm{O}_{2}\). Note: Acceptable answers to some of these questions might be "both" or "neither one." a. Which container has the greatest density of gas? b. Which container has molecules that are moving at a faster average molecular speed? C. Which container has more molecules? d. If the valve is opened, will the pressure in each of the containers change? If it does, how will it change (increase, decrease, or no change)? e. \(2.0 \mathrm{~mol}\) of \(\mathrm{Ar}\) is added to the system with the valve open. What fraction of the total pressure will be due to the \(\mathrm{H}_{2}\) ?

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