/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Oxalic acid, \(\mathrm{H}_{2} \m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), is oxidized by permanganate ion to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) $$\begin{array}{r}2 \mathrm{MnO}_{4}^{-}(a q)+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+6 \mathrm{H}^{+}(a q)\longrightarrow \\\2 \mathrm{Mn}^{2+}(a q)+10 \mathrm{CO}_{2}(g)+8 \mathrm{H}_{2} \mathrm{O}(l)\end{array}$$ The rate law is $$\text { Rate }=k\left[\mathrm{Mn} \mathrm{O}_{4}^{-}\right]\left[\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right]$$ What is the order with respect to each reactant? What is the overall order?

Short Answer

Expert verified
The reaction is first order with respect to each reactant and second order overall.

Step by step solution

01

Analyze the Rate Law Expression

The rate law for the reaction is given as \(\text{Rate} = k[\mathrm{MnO}^{-}_{4}][\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}]\). This expression contains the rate constant \(k\) and the concentrations of the reactants \([\mathrm{MnO}^{-}_{4}]\) and \([\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}]\).
02

Determine the Order for Each Reactant

The order of the reaction with respect to a reactant is the exponent of the concentration term for that reactant in the rate law.- For \([\mathrm{MnO}^{-}_{4}]\), the exponent is 1, indicating that the reaction is first order with respect to permanganate ion.- For \([\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}]\), the exponent is also 1, indicating that the reaction is first order with respect to oxalic acid.
03

Calculate the Overall Order

The overall order of a reaction is the sum of the orders with respect to all reactants. In this case, the order with respect to \(\mathrm{MnO}^{-}_{4}\) is 1 and the order with respect to \(\mathrm{H}_{2}\mathrm{C}_{2}\mathrm{O}_{4}\) is 1.Therefore, the overall order of the reaction is \(1 + 1 = 2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
The rate law of a chemical reaction provides insights into how the rate of the reaction depends on the concentration of the reactants. For the given reaction, the rate law is expressed as:
  • \( ext{Rate} = k[ ext{MnO}_4^-][ ext{H}_2 ext{C}_2 ext{O}_4] \)
Here, \(k\) is the rate constant that is specific to the reaction and changes with temperature.
The concentration terms in square brackets indicate how the rate of reaction is proportional to the concentration of each reactant. In other words, this particular reaction has its rate directly dependent on the concentrations of both the permanganate ion and oxalic acid.
Understanding the rate law helps chemists control and manipulate reaction conditions—like temperature and concentration—to achieve desired reaction rates.
Order of Reaction
The order of reaction specifies the power to which the concentration of a reactant must be raised in the rate law.
This order is crucial because it gives insight into the reaction mechanism and how the concentration changes as the reaction proceeds.
  • First Order: For this reaction, each reactant—\([ ext{MnO}_4^-]\) and \([ ext{H}_2 ext{C}_2 ext{O}_4]\)—has an exponent of 1. This means the reaction is first order with respect to each reactant.
  • Overall Reaction Order: The overall order is the sum of the orders with respect to each reactant. Thus, \(1 + 1 = 2\), making it a second-order reaction overall.
This implies that if the concentration of a reactant is doubled, the rate also doubles (for first order), and in this reaction's case, a change in concentration influences the overall reaction as a second order process.
Reaction Mechanism
The sequence of steps that describe the movement of atoms and molecules during a reaction is called the reaction mechanism.
It provides detailed insights into how reactants transform into products, capturing all the intermediate stages.
  • A reaction mechanism must account for the experimentally observed rate law.
  • For example, if a reaction is first order with respect to a reactant, the reactant might be involved in a single step that determines the rate.
  • Mechanisms often involve multiple species and include intermediates that may not appear in the overall balanced equation.
Understanding the mechanism can reveal why a reaction prefers certain pathways over others and can help chemists design catalysts and other factors to optimize reactions.
Oxidation-Reduction Reaction
Also known as redox reactions, these processes involve the transfer of electrons between species.
In the exercise, oxalic acid is oxidized, meaning it loses electrons, while the permanganate ion is reduced, meaning it gains electrons.
  • Oxidation occurs when an atom, ion, or molecule loses electrons.
  • Reduction is the gain of electrons.
  • The two processes are always coupled: If something is oxidized, something else must be reduced.
These reactions are crucial in both biological systems and industrial processes.
Understanding the electron transfer that occurs during redox reactions can help in fields such as energy production and environmental chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the rate law for the following gas-phase elementary reaction? $$2 \mathrm{I}+\mathrm{H}_{2} \longrightarrow 2 \mathrm{HI}$$

The decomposition of aqueous hydrogen peroxide in a given concentration of catalyst yielded the following data: \(\begin{array}{lllll}\text { Time } & 0.0 \mathrm{~min} & 5.0 \mathrm{~min} & 10.0 \mathrm{~min} & 15.0 \mathrm{~min} \\ {\left[\mathrm{H}_{2} \mathrm{O}_{2}\right]} & 0.1000 M & 0.0804 M & 0.0648 \mathrm{M} & 0.0519 \mathrm{M}\end{array}\) Verify that the reaction is first order. Determine the rate constant for the decomposition of \(\mathrm{H}_{2} \mathrm{O}_{2}\) (in units of \(/ \mathrm{s}\) ) from the slope of the straight-line plot of \(\ln \left[\mathrm{H}_{2} \mathrm{O}_{2}\right]\) versus time.

For the reaction of nitrogen monoxide, NO, with chlorine, \(\mathrm{Cl}_{2}\) $$2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NOCl}(g)$$ the observed rate law is $$\text { Rate }=k[\mathrm{NO}]^{2}\left[\mathrm{Cl}_{2}\right]$$ What is the reaction order with respect to nitrogen monoxide? with respect to \(\mathrm{Cl}_{2}\) ? What is the overall order?

At high temperature, the reaction $$\mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g)$$ is thought to occur in a single step. What should be the rate law in that case?

Tertiary butyl chloride reacts in basic solution according to the equation $$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCl}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Cl}^{-}$$ The accepted mechanism for this reaction is $$\begin{aligned}\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCl} & \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}+\mathrm{Cl}^{-} \\\ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}+\mathrm{OH}^{-} & \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH} \end{aligned}$$ What should be the rate law for this reaction?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.