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What is the rate law for the following gas-phase elementary reaction? $$2 \mathrm{I}+\mathrm{H}_{2} \longrightarrow 2 \mathrm{HI}$$

Short Answer

Expert verified
Rate law is: \( \text{Rate} = k[\text{I}]^2[\text{H}_2] \)

Step by step solution

01

Identify the Reaction Order

For an elementary reaction, the reaction order can be directly determined from the stoichiometry of the reactants. In this reaction, the stoichiometry is 2 for iodine (I) and 1 for hydrogen ( H_2 ). Therefore, the reaction order is 2 with respect to iodine and 1 with respect to hydrogen.
02

Write the General Rate Law Expression

Write the rate law expression for an elementary reaction as the product of a rate constant and the concentration of reactants each raised to the power of their coefficients in the balanced equation. The general form for this reaction is: \[ ext{Rate} = k[ ext{I}]^2[ ext{H}_2]^1 \]
03

Specify the Rate Constant

In the rate law expression, the term \( k \) represents the rate constant. It incorporates all factors affecting the rate constant, such as temperature and catalysts, but it does not include terms associated with the concentrations of reactants.
04

Combine Components of the Rate Law

Substitute the stoichiometric coefficients from the balanced equation into the rate law to establish the complete expression. The rate law that describes the reaction is: \[ ext{Rate} = k[ ext{I}]^2[ ext{H}_2] \] This shows that the reaction rate depends quadratically on the concentration of iodine and linearly on the concentration of hydrogen gas.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Order
The reaction order is a crucial concept in understanding how the concentration of reactants influences the rate of a chemical reaction. For an elementary reaction, such as the reaction between iodine (I) and hydrogen (H\(_2\)), the reaction order can be directly determined from the stoichiometry. In this particular reaction, iodine has a stoichiometric coefficient of 2, and hydrogen has a coefficient of 1.
This means the order of reaction with respect to iodine is 2, and with respect to hydrogen, it is 1. Thus, the overall reaction order is the sum of these values, which in this case is 3. The reaction order provides insight into the mechanism of the reaction and dictates how changes in reactant concentrations can affect the rate.
Elementary Reaction
An elementary reaction is a simple form of reaction that occurs in a single step, involving only one transition state. In the context of the reaction between iodine and hydrogen (2I + H\(_2\) → 2HI), this simplicity allows us to determine the reaction order directly from the balanced equation.
Elementary reactions are fundamental because they offer a straightforward look at reaction dynamics without the complexities of intermediate steps. Each reactant's coefficient in the balanced equation represents its role in the reaction's mechanism, which directly informs the rate law of the reaction.
Rate Constant
The rate constant, denoted as \(k\), is a proportionality factor in the rate law that encompasses all the factors affecting the rate of reaction, barring the concentrations of reactants. These factors can include temperature, the presence of a catalyst, or the medium of reaction.
In the rate law expression, \( k [\mathrm{I}]^2 [\mathrm{H}_2]^1 \), the value of \(k\) is experimentally determined and unique to each reaction. It remains constant as long as conditions such as temperature remain unaltered. However, its value can change with differing reaction conditions. The unit of \(k\) can vary depending on the overall order of the reaction, ensuring consistency in the dimensions of the rate equation.
Stoichiometry
Stoichiometry refers to the quantitative relationships between reactants and products in a chemical reaction. It is foundational to understanding reaction mechanisms and determining reaction order in an elementary reaction. By examining the stoichiometry of the reaction \(2\mathrm{I} + \mathrm{H}_2 \rightarrow 2\mathrm{HI}\), we learn not just the amount of each substance involved but also how these quantities influence the rate law of the reaction.
In this reaction, stoichiometry tells us that it takes two molecules of iodine for every molecule of hydrogen to produce two molecules of hydrogen iodide. This ratio directly affects the rate law through the powers to which the concentrations of iodine and hydrogen are raised. Understanding stoichiometry is crucial for predicting and controlling the outcomes of chemical reactions.

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Most popular questions from this chapter

The rate of a particular reaction quadruples when the temperature is increased from \(25^{\circ} \mathrm{C}\) to \(35^{\circ} \mathrm{C}\). Calculate the activation energy for this reaction.

Benzene diazonium chloride, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NNCl}\), decomposes by a first-order rate law. $$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NNCl} \longrightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{N}_{2}(g)$$ If the rate constant at \(20^{\circ} \mathrm{C}\) is \(4.3 \times 10^{-5} / \mathrm{s}\), how long will it take for \(75 \%\) of the compound to decompose?

A compound decomposes by a first-order reaction. The concentration of compound decreases from \(0.1180 \mathrm{M}\) to \(0.0950 M\) in \(5.2 \mathrm{~min} .\) What fraction of the compound remains after \(7.1\) min?

Nitrogen monoxide reacts with oxygen to give nitrogen dioxide. $$2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)$$ The rate law is \(-\Delta[\mathrm{NO}] / \Delta t=k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right]\), where the rate constant is \(1.16 \times 10^{-5} \mathrm{~L}^{2} /\left(\mathrm{mol}^{2} \cdot \mathrm{s}\right)\) at \(339^{\circ} \mathrm{C}\). A vessel contains NO and \(\mathrm{O}_{2}\) at \(339^{\circ} \mathrm{C}\). The initial partial pressures of \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) are \(155 \mathrm{mmHg}\) and \(345 \mathrm{mmHg}\), respectively. What is the rate of decrease of partial pressure of \(\mathrm{NO}\) (in \(\mathrm{mmHg}\) per second)? (Hint: From the ideal gas law, obtain an expression for the molar concentration of a particular gas in terms of its partial pressure.)

The chemical reaction \(\mathrm{A} \longrightarrow \mathrm{B}+\mathrm{C}\) has a rate constant that obeys the Arrhenius equation. Predict what happens to both the rate constant \(k\) and the rate of the reaction if the following were to occur. a. a decrease in temperature b. an increase in the activation energy of the forward and reverse reactions C an increase in both activation energy and temperature

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