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Iron(III) chloride is reduced by tin(II) chloride. $$2 \mathrm{FeCl}_{3}(a q)+\mathrm{SnCl}_{2}(a q) \longrightarrow 2 \mathrm{FeCl}_{2}(a q)+\mathrm{SnCl}_{4}(a q)$$ The concentration of \(\mathrm{Fe}^{3+}\) ion at the beginning of an experiment was \(0.03586 M\). After \(4.00 \mathrm{~min}\), it was \(0.02638 M\). What is the average rate of reaction of \(\mathrm{FeCl}_{3}\) in this time interval?

Short Answer

Expert verified
The average rate of reaction is \( 0.001185 \ M/\mathrm{min} \) for \( \mathrm{FeCl}_3 \).

Step by step solution

01

Identify Initial and Final Concentrations

Start with the initial concentration of \( \mathrm{Fe}^{3+} \), which is \( 0.03586 \ M \), and the final concentration after \( 4.00 \ \mathrm{min} \), which is \( 0.02638 \ M \). These will be used to calculate the change in concentration.
02

Calculate Change in Concentration

Subtract the final concentration of \( \mathrm{Fe}^{3+} \) from the initial concentration to determine the change in concentration over the time period: \[ \Delta [\mathrm{Fe}^{3+}] = 0.03586 \ M - 0.02638 \ M = 0.00948 \ M. \]
03

Determine the Time Interval

The given time interval is \( 4.00 \ \mathrm{min} \). This will be used to calculate the rate of the reaction.
04

Calculate Average Rate of Reaction

Use the formula for the average rate of reaction: \[ \text{Average Rate} = \frac{\Delta [\mathrm{Fe}^{3+}]}{\Delta t}. \] Substituting the values we get, \[ \text{Average Rate} = \frac{0.00948 \ M}{4.00 \ \mathrm{min}} = 0.00237 \ M/\mathrm{min}. \]
05

Adjust Rate Based on Stoichiometry

According to the balanced reaction equation, \( 2 \ \mathrm{FeCl}_3 \) participates in the reaction. Therefore, the rate must be divided by 2 to find the rate for \( \mathrm{FeCl}_3 \), resulting in: \[ \text{Rate for FeCl}_3 = \frac{0.00237 \ M/\mathrm{min}}{2} = 0.001185 \ M/\mathrm{min}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Iron(III) Chloride Reduction
The reduction of iron(III) chloride plays a crucial role in various chemical reactions, including redox processes. In the provided reaction between iron(III) chloride (\(\mathrm{FeCl}_3\)) and tin(II) chloride (\(\mathrm{SnCl}_2\)), iron(III) chloride is transformed into iron(II) chloride (\(\mathrm{FeCl}_2\)). This type of reaction is a classic example of a reduction-oxidation (redox) reaction.

In the redox reaction, oxygen transfer occurs, and electrons are exchanged among reactants. Here, \(\mathrm{FeCl}_3\) is reduced because it gains electrons, whereas tingives up electrons, serving as the reducing agent that allows iron in \(\mathrm{FeCl}_3\) to decrease its oxidation state from +3 to +2.
- **Reduction**: Gain of electrons by a species.- **Oxidation**: Loss of electrons by a species.- **Reducing Agent**: Element that donates electrons.
Understanding this mechanism not only illustrates elemental changes but also helps in calculating reaction rates in terms of species concentration changes.
Concentration Change
Solving problems related to concentration change involves calculating how the amount of a substance varies over timeduring a chemical reaction.

In our reaction example, the concentration change of \(\mathrm{Fe}^{3+}\) ions is a central factor in determining the average rate of reaction. We consider the initial concentration (0.03586 M) and the final concentration (0.02638 M) after 4 minutes,adenoting a decrease in concentration of 0.00948 M.
- **Initial Concentration**: The starting amount of a reactant in solution.- **Final Concentration**: The amount of reactant present after a reaction is complete for the given period.
Change in concentration is calculated using:\[\Delta [\mathrm{Fe}^{3+}] = [\mathrm{Fe}^{3+}]_{\text{initial}} - [\mathrm{Fe}^{3+}]_{\text{final}}\]
This change provides insight into how fast the reactant gets consumed, integral for calculating average reaction rates.
Reaction Stoichiometry
Reaction stoichiometry is a fundamental concept in chemistry,to balance equations and to relate reactant quantities with product quantities.

In this particular example, the balanced reaction equation is: \[2 \ \mathrm{FeCl}_{3}(aq) + \mathrm{SnCl}_{2}(aq) \longrightarrow 2 \ \mathrm{FeCl}_{2}(aq) + \mathrm{SnCl}_{4}(aq)\]

This equation shows that two moles of \(\mathrm{FeCl}_3\) react with one mole of \(\mathrm{SnCl}_2\).
- **Balanced Equation**: Ensures the number of atoms for each element is conserved throughout the reaction.- **Mole Ratio**: Derived from the coefficients in the balanced equation,esential for converting between moles of reactants and products.
Understanding mole ratios is key to adjusting the calculated reaction rate. Even though the result showed the average rate as \(0.00237 \ M/\mathrm{min}\),
for \(\mathrm{FeCl}_3\), we must divide by 2, as two moles participate in the reaction. This adjustment aligns with the stoichiometry of the equation, thus giving the accurate reaction rate.

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Most popular questions from this chapter

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