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Ammonium nitrite, \(\mathrm{NH}_{4} \mathrm{NO}_{2}\), decomposes in solution, as shown here. $$\mathrm{NH}_{4} \mathrm{NO}_{2}(a q) \longrightarrow \mathrm{N}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(l)$$ The concentration of \(\mathrm{NH}_{4}{ }^{+}\) ion at the beginning of an experiment was \(0.500 M\). After \(3.00\) hours, it was \(0.432 M\). What is the average rate of decomposition of \(\mathrm{NH}_{4} \mathrm{NO}_{2}\) in this time interval?

Short Answer

Expert verified
The average rate of decomposition is \(-0.0227 \, M/\text{h}\).

Step by step solution

01

Identify Initial and Final Concentrations

The initial concentration of \( \mathrm{NH}_{4}^{+} \) is given as \( 0.500 \, M \) and the concentration after 3 hours is \( 0.432 \, M \).
02

Calculate the Change in Concentration

The change in concentration of \( \mathrm{NH}_{4}^{+} \) is calculated as the initial concentration minus the final concentration: \( 0.500 \, M - 0.432 \, M = 0.068 \, M \).
03

Determine the Time Interval

The time interval over which the change occurs is \( 3.00 \) hours or \( 3.00 \times 60 = 180 \) minutes.
04

Calculate the Average Rate of Decomposition

The average rate of decomposition is given by the change in concentration divided by the time interval: \[- \frac{0.068 \, M}{3.00 \, \text{h}} = -0.0227 \, M/\text{h} \]. The negative sign indicates decomposition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Rate of Reaction
The average rate of reaction measures how quickly a reactant is consumed or a product is formed over a particular period. It is a way to express the speed of a chemical reaction. In the case of the decomposition of ammonium nitrite \(\text{NH}_4\text{NO}_2\), it describes how fast the concentration of ammonium nitrite decreases in solution. For average rate calculations, the general formula is: \[- \frac{\Delta [\text{Reactant}]}{\Delta t} = \text{Average Rate}\]
  • \(\Delta [\text{Reactant}]\) is the change in concentration over the time interval \(\Delta t\).
  • The negative sign indicates the decrease in the concentration of reactants.
This formula helps to understand how the concentration of the ammonium nitrite decreased from \(0.500 \, M\) to \(0.432 \, M\) over a time span of 3 hours. This average rate provides a snapshot of the reaction's progress over that time frame, aiding chemists in understanding the reaction dynamics.
Decomposition Reaction
A decomposition reaction is a type of chemical reaction where one compound breaks down into two or more simpler substances. It often requires an energy input such as heat, light, or electricity. For ammonium nitrite, the reaction is: \[\text{NH}_4\text{NO}_2 (aq) \rightarrow \text{N}_2 (g) + 2 \text{H}_2\text{O} (l)\] Here, ammonium nitrite decomposes into nitrogen gas and water. Decomposition reactions are common in both organic and inorganic chemistry and are essential in various industrial and laboratory processes.
  • They help in extracting pure elements from compounds.
  • Such reactions are essential for combustion, metabolism, and many biological processes.
Understanding decomposition reactions allows scientists to predict the products of chemical changes and to harness these reactions for practical applications.
Ammonium Nitrite
Ammonium nitrite \((\text{NH}_4\text{NO}_2)\) is a chemical compound composed of ammonium ions \((\text{NH}_4^+)\) and nitrite ions \((\text{NO}_2^-)\). It is an unstable salt that decomposes easily, particularly in aqueous solutions, to form nitrogen gas and water. It is important to note that ammonium nitrite is sensitive to heat and can decompose rapidly, which can be hazardous. In the context of this reaction, ammonium nitrite serves as the reactant that breaks down to yield nitrogen, a non-hazardous and inert gas, along with water, a natural solvent. Understanding the properties of ammonium nitrite assists in safe laboratory handling and its effective use in demonstrations and other chemical applications. Despite its instability, it plays critical roles in scientific research and education.
Reaction Rate Calculation
Calculating the reaction rate is crucial for understanding how fast a reaction proceeds. The average rate of a reaction is determined by measuring the concentration change of the reactant or product per unit time. In the given example, the initial concentration of ammonium nitrite was \(0.500 \, M\), which reduced to \(0.432 \, M\) after 3 hours.
  • The change in concentration \(\Delta [\text{NH}_4\text{NO}_2] = 0.068 \, M\).
  • The time interval \(\Delta t = 3.00 \, \text{hours}\).
  • The average rate of decomposition is \[- \frac{0.068 \, M}{3.00 \, \text{h}} = -0.0227 \, M/\text{h}\].
This value indicates that the concentration of ammonium nitrite decreased by \(0.0227 \, M\) per hour. This method of calculation is fundamental to kinetics, allowing chemists to gauge reaction speed and make adjustments in industrial and laboratory settings.

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Most popular questions from this chapter

Azomethane, \(\mathrm{CH}_{3} \mathrm{NNCH}_{3}\), decomposes according to the following equation: $$\mathrm{CH}_{3} \mathrm{NNCH}_{3}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{N}_{2}(g)$$ The initial concentration of azomethane was \(1.50 \times 10^{-2} \mathrm{~mol} / \mathrm{L} .\) After \(7.00 \mathrm{~min}\), this concentration decreased to \(1.01 \times 10^{-2}\) \(\mathrm{mol} / \mathrm{L}\). Obtain the average rate of reaction during this time interval. Express the answer in units of \(\mathrm{mol} /(\mathrm{L} \cdot \mathrm{s})\).

The decomposition of aqueous hydrogen peroxide in a given concentration of catalyst yielded the following data: \(\begin{array}{lllll}\text { Time } & 0.0 \mathrm{~min} & 5.0 \mathrm{~min} & 10.0 \mathrm{~min} & 15.0 \mathrm{~min} \\ {\left[\mathrm{H}_{2} \mathrm{O}_{2}\right]} & 0.1000 M & 0.0804 M & 0.0648 \mathrm{M} & 0.0519 \mathrm{M}\end{array}\) Verify that the reaction is first order. Determine the rate constant for the decomposition of \(\mathrm{H}_{2} \mathrm{O}_{2}\) (in units of \(/ \mathrm{s}\) ) from the slope of the straight-line plot of \(\ln \left[\mathrm{H}_{2} \mathrm{O}_{2}\right]\) versus time.

Methyl acetate reacts in acidic solution. $$\mathrm{CH}_{3} \mathrm{COOCH}_{3}+\mathrm{H}_{2} \mathrm{O} \stackrel{\mathrm{H}^{+}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{OH}+\mathrm{CH}_{3} \mathrm{COOH}$$ methyl acet thanol acetic ac The rate law is first order in methyl acetate in acidic solution, and the rate constant at \(25^{\circ} \mathrm{C}\) is \(1.26 \times 10^{-4} / \mathrm{s}\). How long will it take for \(65 \%\) of the methyl acetate to react?

Sulfuryl chloride, \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\), decomposes when heated. $$\mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{Cl}_{2}(g)$$ In an experiment, the initial concentration of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) was \(0.0248 \mathrm{~mol} / \mathrm{L}\). If the rate constant is \(2.2 \times 10^{-5} / \mathrm{s}\), what is the concentration of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) after \(2.0 \mathrm{hr}\) ? The reaction is first order.

What is the rate law for the following gas-phase elementary reaction? $$2 \mathrm{I}+\mathrm{H}_{2} \longrightarrow 2 \mathrm{HI}$$

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