/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 What is meant by the conjugate a... [FREE SOLUTION] | 91影视

91影视

What is meant by the conjugate acid of a base?

Short Answer

Expert verified
The conjugate acid of a base is the species formed when the base accepts a proton (H鈦).

Step by step solution

01

Identify the Base

To understand what is meant by the conjugate acid of a base, begin by identifying the base involved in a reaction. A base is a substance that can accept a proton (H鈦 ion) from another compound. Examples of common bases include OH鈦, NH鈧, and Cl鈦.
02

Add a Proton to the Base

The next step is to add a proton (H鈦) to the base. In the realm of chemistry, the conjugate acid of a base is formed when the base gains a proton. For instance, if the base NH鈧 (ammonia) accepts a proton, it becomes NH鈧勨伜 (ammonium).
03

Define the Conjugate Acid

The conjugate acid is the species formed by the reception of a proton by a base. It is considered the 'acid' counterpart that can donate the proton back, thus reversing the base's action of accepting a proton. So, every base has a corresponding conjugate acid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Transfer
In chemistry, proton transfer is a fundamental process where a proton, which is essentially a hydrogen ion (H鈦), moves from one molecule to another. This transfer is a critical aspect of many chemical reactions, especially those involving acids and bases. When a base receives a proton, the process is called protonation, while when an acid gives away a proton, it is called deprotonation.
Proton transfer is central to understanding how acids and bases interact. When ammonia (NH鈧) acts as a base, it accepts a proton to become ammonium (NH鈧勨伜), demonstrating a clear case of proton transfer. By understanding these interactions, we can predict the behavior of substances in various solutions and reactions.
Bronsted-Lowry Acids and Bases
The Bronsted-Lowry theory is a foundational concept in acid-base chemistry. According to this theory, an acid is any substance that can donate a proton, and a base is any substance that can accept a proton. This definition is broader than the traditional one, which often only considers acids as hydrogen-containing substances that release hydrogen ions in water.
With the Bronsted-Lowry approach, the focus is on proton transfer. Thus, when hydrochloric acid (HCl) donates a proton to water, forming hydronium ions (H鈧僌鈦), HCl acts as a Bronsted-Lowry acid. Conversely, when ammonia (NH鈧) accepts a proton to become ammonium (NH鈧勨伜), it is acting as a Bronsted-Lowry base. This theory effectively explains acid-base reactions that occur even outside of aqueous solutions.
Conjugate Acid
A conjugate acid is formed when a base accepts a proton. The transformation from base to conjugate acid involves the gain of a single proton. For instance, when the base NH鈧 picks up a proton, it becomes its conjugate acid, NH鈧勨伜.
Every base has a corresponding conjugate acid. This conjugate pair represents an important aspect of reversible reactions involving proton transfer. It helps us understand how bases can sometimes turn into acids if the conditions allow them to donate the previously accepted proton. Understanding these conjugate relationships is crucial in predicting how chemicals will behave in response to shifts in pH levels or other reaction conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the \(\mathrm{pH}\) of a neutral solution at \(37^{\circ} \mathrm{C}\), where \(K_{w}\) equals \(2.5 \times 10^{-14} ?\)

The nitride ion and the amide ion, \(\mathrm{NH}_{2}^{-}\), have greater attractions for the hydronium ion than the hydroxide ion does. Write the equations for the reactions that occur when calcium nitride and sodium amide are added to water (each gives \(\mathrm{NH}_{3}\) ). Which is the stronger base, the nitride ion or the amide ion? Why? What is the meaning of the statement that the hydroxide ion is the strongest base that can exist in water?

Boron trifluoride, \(\mathrm{BF}_{3}\), and diethyl ether, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\), react to produce a compound with the formula \(\mathrm{BF}_{3} \cdot\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\). A coordinate covalent bond is formed between the boron atom on \(\mathrm{BF}_{3}\) and the oxygen atom on \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O} .\) Write the equation for this reaction, using Lewis electron-dot formulas. Label the Lewis acid and the Lewis base. Determine how many grams of \(\mathrm{BF}_{3} \cdot\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\) are formed when \(10.0 \mathrm{~g} \mathrm{BF}_{3}\) and \(20.0 \mathrm{~g}\) \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}\) are placed in a reaction vessel, assuming that the reaction goes to completion.

A sample of apple cider has a \(\mathrm{pH}\) of \(3.15 .\) What is the hydroxide- ion concentration of this solution?

A sample of lemon juice has a hydronium-ion concentration equal to \(2.5 \times 10^{-2} M .\) What is the \(\mathrm{pH}\) of this sample?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.