Chapter 16: Problem 5
Write an equation in which \(\mathrm{H}_{2} \mathrm{PO}_{3}^{-}\) acts as an acid and another in which it acts as a base.
Short Answer
Expert verified
\( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) can act as an acid by forming \( \mathrm{HPO}_{3}^{2-} \) and as a base by forming \( \mathrm{H}_{3} \mathrm{PO}_{3} \).
Step by step solution
01
Identify Acid and Base Behavior
To write equations showing the behavior of \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) as both an acid and a base, we need to recall the definitions: an acid donates a proton (\( \mathrm{H}^{+} \)), and a base accepts a proton. \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) can act as an acid by donating a proton, forming \( \mathrm{HPO}_{3}^{2-} \). Conversely, it can act as a base by accepting a proton, forming \( \mathrm{H}_{3} \mathrm{PO}_{3} \).
02
Write Acid Behavior Equation
When \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as an acid, it donates a proton. For example, reacting with water, the equation is: \[ \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{HPO}_{3}^{2-} + \mathrm{H}_{3} \mathrm{O}^{+} \] This equation shows \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) losing a \( \mathrm{H}^{+} \) and forming \( \mathrm{HPO}_{3}^{2-} \), demonstrating its acid behavior.
03
Write Base Behavior Equation
When \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as a base, it accepts a proton. For example, reacting with \( \mathrm{H}^{+} \), the equation is: \[ \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{3} \] This equation shows \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) gaining a \( \mathrm{H}^{+} \) and forming \( \mathrm{H}_{3} \mathrm{PO}_{3} \), demonstrating its base behavior.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Proton Donation
Proton donation is a fundamental concept in chemistry, especially in acid-base reactions. To understand proton donation, recall the definition of an acid according to the Brønsted-Lowry theory: an acid is a substance that donates a proton (which is essentially a hydrogen ion, \( \mathrm{H}^+ \)). This process can be seen in various chemical reactions where a compound releases a proton into the surrounding environment.
In the given exercise, \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as an acid by donating a proton. This donation turns \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) into \( \mathrm{HPO}_{3}^{2-} \), illustrating its acidic properties. The chemical equation showing this is:
In the given exercise, \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as an acid by donating a proton. This donation turns \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) into \( \mathrm{HPO}_{3}^{2-} \), illustrating its acidic properties. The chemical equation showing this is:
- \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{HPO}_{3}^{2-} + \mathrm{H}_{3} \mathrm{O}^{+} \)
Proton Acceptance
Proton acceptance occurs when a substance behaves as a base. A base, as defined by the Brønsted-Lowry theory, is a compound that accepts a proton from another substance. When accepting a proton, the base typically forms a new compound.
In the provided exercise, \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) is capable of acting as a base by accepting a proton to become \( \mathrm{H}_{3} \mathrm{PO}_{3} \). The corresponding chemical equation for this transformation is:
In the provided exercise, \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) is capable of acting as a base by accepting a proton to become \( \mathrm{H}_{3} \mathrm{PO}_{3} \). The corresponding chemical equation for this transformation is:
- \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{3} \)
Chemical Equations
Chemical equations are symbolic representations of chemical reactions. They provide insight into how substances interact and change during a reaction. A chemical equation must balance in terms of atoms and charge, obeying the law of conservation of mass.
In acid-base reactions, chemical equations illustrate how protons are transferred between substances. For instance, in the example where \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as an acid, the chemical equation is:
Conversely, when \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as a base, the following chemical equation describes the reaction:
In acid-base reactions, chemical equations illustrate how protons are transferred between substances. For instance, in the example where \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as an acid, the chemical equation is:
- \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{HPO}_{3}^{2-} + \mathrm{H}_{3} \mathrm{O}^{+} \)
Conversely, when \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} \) acts as a base, the following chemical equation describes the reaction:
- \( \mathrm{H}_{2} \mathrm{PO}_{3}^{-} + \mathrm{H}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{3} \)