/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Sodium reacts with anhydrous amm... [FREE SOLUTION] | 91Ó°ÊÓ

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Sodium reacts with anhydrous ammonia to produce sodium amide, \(\mathrm{NaNH}_{2}(s) .\) How many grams of sodium amide can be produced from \(10.0\) grams of sodium?

Short Answer

Expert verified
16.97 grams of sodium amide can be produced.

Step by step solution

01

Write Balanced Chemical Equation

First, we write the balanced chemical equation for the reaction. Sodium (Na) reacts with ammonia (NH₃) to form sodium amide (NaNH₂) and hydrogen gas (H₂): \[\mathrm{2Na + 2NH_3 \rightarrow 2NaNH_2 + H_2}\] This equation tells us that 2 moles of sodium will produce 2 moles of sodium amide.
02

Calculate Moles of Sodium

Calculate the number of moles of sodium present in 10.0 grams using its molar mass. The molar mass of sodium (Na) is 22.99 g/mol. \[\text{Moles of Na} = \frac{10.0 \text{ g}}{22.99 \text{ g/mol}} \approx 0.435 \text{ moles}\]
03

Determine Moles of Sodium Amide Produced

Using the balanced equation from Step 1, we find the moles of sodium amide produced. Since the ratio of sodium to sodium amide is 1:1 in the balanced equation, 0.435 moles of Na will produce 0.435 moles of NaNHâ‚‚.
04

Convert Moles of Sodium Amide to Grams

To find the mass of sodium amide produced, we multiply the moles of NaNHâ‚‚ by its molar mass. The molar mass of NaNHâ‚‚ (sodium amide) is calculated as follows:- Na: 22.99 g/mol- N: 14.01 g/mol- H: 1.01 g/mol (for 2 H atoms: 2.02 g/mol)\[\text{Molar mass of NaNH}_2 = 22.99 + 14.01 + 2.02 = 39.02 \text{ g/mol}\]Now calculate the mass:\[\text{Mass of NaNH}_2 = 0.435 \text{ moles} \times 39.02 \text{ g/mol} \approx 16.97 \text{ grams}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Chemical Reactions
Chemical reactions are processes where substances, or reactants, undergo a transformation to become new substances, known as products. These reactions can involve the making or breaking of chemical bonds, primarily focusing on rearranging atoms. The original exercise focuses on sodium reacting with ammonia.In our example, sodium (\(\text{Na}\)) and ammonia (\(\text{NH}_3\)) are reactants, which means they interact and undergo changes. Through the reaction, these substances form sodium amide (\(\text{NaNH}_2\)) and hydrogen gas (\(\text{H}_2\)), which are the products.
  • Reactants: Sodium and Ammonia
  • Products: Sodium Amide and Hydrogen
This transformation involves sodium atoms bonding with ammonia molecules. Understanding which elements and compounds are reacting can be key to successfully predicting the products of a chemical reaction. Carefully studying these interactions helps to balance chemical equations and, thus, determine the productive outcome of a reaction.
The Process of Moles Calculation
Moles are a fundamental concept in chemistry that allow scientists to count particles in a substance. The mole is a unit to measure the amount of a substance, based on Avogadro's number, which equals approximately 6.022 \times 10^{23} particles/mol. This exercise calculates how many moles from the given mass of sodium are there.For sodium, the molar mass is 22.99 g/mol. To find the moles, divide the given mass by the molar mass. For example, with 10.0 grams of sodium:\[\text{Moles of Na} = \frac{10.0 \text{ g}}{22.99 \text{ g/mol}} \approx 0.435 \text{ moles}\]Once we determine the amount in moles, it becomes easier to understand how it will interact with other substances in a reaction. This calculation is vital in converting the knowledge of mass into usable mole values for stoichiometric equations.
The Importance of Balanced Chemical Equations
Balanced chemical equations are crucial because they demonstrate the conservation of mass and energy in reactions. They show that the number of atoms for each element in the reactants side is equal to that in the products side.A fundamental part of the original step-by-step solution involves balancing the equation for the reaction between sodium and ammonia:\[\mathrm{2Na + 2NH_3 \rightarrow 2NaNH_2 + H_2}\]This balanced equation indicates that two moles of sodium react with ammonia to produce two moles of sodium amide.
  • It helps predict the amounts of product formed.
  • Ensures that the same amount of each type of atom appears on both sides.
Balancing equations allows chemists to understand the proportions in which substances combine during reactions, ensuring accurate predictions of the outcomes of real-world chemical processes.

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Most popular questions from this chapter

The addition of iron to sulfuric acid is found to produce iron(II) sulfate and hydrogen gas with a \(95 \%\) yield. (a) Write a balanced equation for this reaction. (b) How many kilograms of iron are required to generate \(1.00\) kilograms of hydrogen gas?

An oxide of molybdenum with the chemical formula \(\mathrm{Mo}_{2} \mathrm{O}_{3}(s)\) is converted completely to another oxide. The oxide \(\mathrm{Mo}_{2} \mathrm{O}_{3}(s)\) had a mass of \(12.64\) grams and the new oxide has a mass of \(13.48\) grams. Determine the empirical formula of the new oxide.

Combustion analysis of a \(1.000\) -gram sample of a compound known to contain only carbon, hydrogen, and oxygen produces \(1.500\) grams of \(\mathrm{CO}_{2}(g)\) and \(0.409\) grams of \(\mathrm{H}_{2} \mathrm{O}(g)\). Determine the empirical formula of the compound.

An ore is analyzed for its lead content as follows. A sample is dissolved in water; then sodium sulfate is added to precipitate the lead as lead(II) sulfate, \(\mathrm{PbSO}_{4}(s) .\) The net ionic equation for the reaction is $$ \mathrm{Pb}^{2+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \rightarrow \mathrm{PbSO}_{4}(s) $$ It was found that \(13.73\) grams of lead(II) sulfate were precipitated from a sample of ore having a mass of \(53.92\) grams. How many grams of lead are there in the sample? What is the mass percentage of lead in the ore?

A solution containing \(17.5\) grams of cadmium chloride is mixed with a solution containing \(35.5\) grams of silver perchlorate. (a) Write the balanced chemical equation for this reaction. (b) Determine how many grams of silver chloride are produced after the reaction comes to completion. (c) How many grams of the reactant in excess will remain after the reaction?

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