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The catalytic activity of an insect aminopeptidase was investigated using an artificial peptide substrate. The \(V_{\max }\) was \(4.0 \times 10^{-7} \mathrm{M} \cdot \mathrm{s}^{-1}\) and the \(K_{\mathrm{M}}\) was \(1.4 \times 10^{-4} \mathrm{M}\). The enzyme concentration used in the assay was \(1.0 \times 10^{-7} \mathrm{M}\). a. What is the value of \(k_{\text {cat }}\) ? What is the meaning of \(k_{\text {cat }}\) ? b. Calculate the catalytic efficiency of the enzyme.

Short Answer

Expert verified
The \(k_{\text{cat}}\) value is \(4.0 \ \mathrm{s}^{-1}\), and the catalytic efficiency is \(2.86 \times 10^{4} \ \mathrm{M}^{-1} \cdot \mathrm{s}^{-1}\).

Step by step solution

01

Understanding the Definitions

The turnover number, or \(k_{\text{cat}}\), is defined as the number of substrate molecule conversions per enzyme molecule per unit time when the enzyme is fully saturated with substrate. \(k_{\text{cat}}\) can be calculated using the formula \(k_{\text{cat}} = \frac{V_{\max}}{[E]}\), where \([E]\) is the enzyme concentration. Catalytic efficiency is determined by \(\frac{k_{\text{cat}}}{K_{M}}\).
02

Calculate k_cat

Substitute the given values into the equation for \(k_{\text{cat}}\):\[\begin{align*}k_{\text{cat}} &= \frac{V_{\max}}{[E]} \&= \frac{4.0 \times 10^{-7} \ \mathrm{M} \cdot \mathrm{s}^{-1}}{1.0 \times 10^{-7} \ \mathrm{M}} \&= 4.0 \ \mathrm{s}^{-1}\end{align*}\]Thus, \(k_{\text{cat}}\) is \(4.0 \ \mathrm{s}^{-1}\). This means each enzyme molecule converts 4 substrate molecules per second.
03

Calculate Catalytic Efficiency

Catalytic efficiency is given by \(\frac{k_{\text{cat}}}{K_{M}}\):\[\begin{align*}\text{Catalytic efficiency} &= \frac{4.0 \ \mathrm{s}^{-1}}{1.4 \times 10^{-4} \ \mathrm{M}} \&= 2.86 \times 10^{4} \ \mathrm{M}^{-1} \cdot \mathrm{s}^{-1}\end{align*}\]So, the enzyme's catalytic efficiency is \(2.86 \times 10^{4} \ \mathrm{M}^{-1} \cdot \mathrm{s}^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catalytic Activity
Catalytic activity is a measure of how well an enzyme speeds up a reaction. Enzymes are proteins that act as biological catalysts, meaning they lower the activation energy needed for reactions. This leads to reactions that happen faster than they would otherwise. During a reaction, an enzyme temporarily binds to a substrate, forming an enzyme-substrate complex, which then converts the substrate into the intended products.
One of the main parameters to evaluate catalytic activity is the maximum reaction rate, denoted as \( V_{\max} \). \( V_{\max} \) represents the highest rate of reaction achieved by an enzyme when it is saturated with a substrate. At this point, increasing the substrate concentration further does not increase the reaction rate. Instead, the reaction rate depends solely on the enzyme's availability to interact with new substrate molecules.
Understanding kinetic parameters helps us optimize reactions for desirable outcomes, especially important in industrial, environmental, and medical fields.
Turnover Number
The turnover number, often expressed as \( k_{\text{cat}} \), refers to the number of substrate molecules that a single enzyme molecule can convert into product per second. This happens when the enzyme is fully saturated with the substrate. Turnover numbers are a fundamental characteristic of enzymes, giving insight into how effectively an enzyme can catalyze a reaction.
We calculate the turnover number with the formula:
  • \( k_{\text{cat}} = \frac{V_{\max}}{[E]} \)
where \( [E] \) is the enzyme concentration. In our example, this results in \( k_{\text{cat}} = 4.0 \ \mathrm{s}^{-1} \), showing that the enzyme can convert 4 substrate molecules per second.
This value helps us understand the catalytic capabilities of the enzyme, and it is particularly useful when comparing the efficiencies of different enzymes under similar conditions. With this, we can identify which enzymes might be best suited for specific applications.
Catalytic Efficiency
Catalytic efficiency is a measure that reflects both an enzyme's affinity for a substrate and its turnover number, providing a comprehensive picture of its effectiveness. This is calculated as the ratio of the turnover number \( k_{\text{cat}} \) to the Michaelis constant \( K_{M} \):
  • \( \text{Catalytic efficiency} = \frac{k_{\text{cat}}}{K_{M}} \)
\( K_{M} \) is a measure of the substrate concentration required to reach half of \( V_{\max} \), representing the enzyme's affinity for the substrate. Smaller \( K_{M} \) indicates higher affinity.
In our scenario, the enzyme's catalytic efficiency is \( 2.86 \times 10^{4} \ \mathrm{M}^{-1} \cdot \mathrm{s}^{-1} \), indicating how effectively the enzyme converts substrate molecules into product across a range of concentrations.
Higher catalytic efficiency values signify more effective enzymes, making them preferable in applications where high-speed reactions under low substrate concentrations are needed. This insight is pivotal for fields like drug development and biotechnology, where enzyme performance is key.

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