/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 The observation that adenosine d... [FREE SOLUTION] | 91Ó°ÊÓ

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The observation that adenosine deaminase is inhibited by 1,6 dihydroinosine allowed scientists to propose a structure for the transition state of this enzyme. The compound coformycin also inhibits adenosine deaminase; its \(K_{\mathrm{I}}\) value is about \(0.25 \mu \mathrm{M}\). Does this observation support or refute the proposed transition state for adenosine deaminase? Coformycin

Short Answer

Expert verified
The low \( K_I \) value of coformycin supports the proposed transition state as it indicates strong binding, suggesting coformycin closely resembles the transition state.

Step by step solution

01

Understand the Role of Transition State Analogs

Transition state analogs are molecules that mimic the transition state of an enzyme-catalyzed reaction. These molecules can bind to the enzyme's active site with high affinity, thereby inhibiting the enzyme's activity. A small equilibrium dissociation constant \( K_I \) indicates a strong binding between the inhibitor and the enzyme, suggesting a close resemblance to the transition state.
02

Evaluate the \( K_I \) Value

Coformycin has a \( K_I \) value of approximately \(0.25 \mu M\), which is relatively low. This suggests strong binding affinity between coformycin and adenosine deaminase, indicating that coformycin is a good transition state analog for this enzyme.
03

Compare with Other Inhibitors

To further support this hypothesis, compare the \( K_I \) value of coformycin with other known inhibitors of adenosine deaminase. A similar or lower \( K_I \) compared to these inhibitors would further support the proposed transition state.
04

Conclusion from the Inhibition Data

The low \( K_I \) value of coformycin, indicating strong binding to adenosine deaminase, supports the idea that the structure of coformycin closely resembles the transition state of the enzymatic reaction. This observation validates the proposed transition state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition State Analogs
In enzyme-catalyzed reactions, the concept of the transition state is vital. It represents a high-energy state that the substrate must pass through on the way to becoming a product. Transition state analogs are designed to resemble these ephemeral configurations. They are potent inhibitors because they bind to the enzyme's active site very effectively, mimicking the transition state. When an enzyme encounters a transition state analog, it can mistake it for the actual transition state and bind it tightly. This binding is often much stronger compared to the substrate or product molecules. This is because enzymes have evolved to bind the transition state with higher affinity than the substrate itself, stabilizing this state and accelerating the conversion to products. Thus, transition state analogs, by mimicking this critical point in an enzyme's activity, serve as powerful tools to inhibit enzymatic reactions. The strength of this inhibition is often reflected in the equilibrium dissociation constant, denoted as \( K_I \). A smaller \( K_I \) value indicates stronger inhibition because the analog fits snugly into the active site, outcompeting the natural substrate.
Adenosine Deaminase
Adenosine deaminase is an enzyme that catalyzes the deamination of adenosine to inosine, an essential biochemical process in nucleic acid metabolism. This enzyme plays a key role in the breakdown of adenosine, a nucleoside found in RNA. The inhibition of adenosine deaminase can have significant biological implications. Interrupting this process is especially important in controlling certain diseases, as excessive or insufficient activity of the enzyme can lead to immunodeficiency disorders or contribute to other pathological conditions. In the context of enzyme inhibition, compounds like coformycin and 1,6 dihydroinosine act as inhibitors of adenosine deaminase by mimicking the transition state, effectively halting the enzyme's activity. This inhibition supports understanding of the transition state, helping scientists propose structures that can control or modulate enzymatic activity with precision. Such inhibitors often help in research and therapeutic applications.
Enzyme Kinetics
Enzyme kinetics is the study of the rates at which enzymatic reactions proceed. The kinetics of an enzyme tell us how various factors like substrate concentration, inhibitors, temperature, and pH affect enzyme activity. Understanding enzyme kinetics is crucial to determine how strongly an inhibitor like a transition state analog binds to the enzyme. The key measurement here is the equilibrium dissociation constant \( K_I \), which quantitatively reflects this binding strength. For example, a small \( K_I \) value, such as the \(0.25 \mu M\) for coformycin, indicates a very strong inhibition due to effective binding at the active site of adenosine deaminase. This is significant because it implies that the analog closely resembles the critical transition state of the enzyme's natural reaction. These kinetic properties allow researchers to compare the effectiveness and specificity of different inhibitors and understand how they might influence the reaction rate and enzyme behavior. This understanding is vital for developing drugs and other compounds that can modify enzyme activity, offering potential solutions for treating diseases.

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Most popular questions from this chapter

Brain glutaminase has a \(V_{\max }\) of \(1.1 \mu \mathrm{mol} \cdot \mathrm{min}^{-1} \cdot \mathrm{mL}^{-1}\) and a \(K_{\mathrm{M}}\) of \(0.6 \mathrm{mM}\). What is the substrate concentration when the velocity is \(0.3 \mu \mathrm{mol} \cdot \min ^{-1} \cdot \mathrm{mL}^{-1}\) ?

The enzyme phenylalanine hydroxylase (PAH) catalyzes the hydroxylation of phenylalanine to tyrosine and is deficient in patients with the disease phenylketonuria (PKU). The \(K_{\mathrm{M}}\) for PAH is \(0.5 \mathrm{mM}\) and the \(V_{\max }\) is \(7.5 \mu \mathrm{mol} \cdot \mathrm{min}^{-1} \cdot \mathrm{mg}^{-1}\). What is the velocity of the reaction when the phenylalanine concentration is \(0.15 \mathrm{mM}\) ?

The enzyme polyphenol oxidase acts on several substrates, one of which is dopamine. What is the \(K_{\mathrm{M}}\) for the enzyme if the velocity for the reaction is \(0.23 \mathrm{U} \cdot \mathrm{min}^{-1} \cdot \mathrm{mL}^{-1}\) when the concentration of substrate is \(10 \mathrm{mM}\) ? The \(V_{\max }\) for the reaction is \(0.36 \mathrm{U} \cdot \mathrm{min}^{-1} \cdot \mathrm{mL}^{-1}\) (U stands for enzyme units).

An unprotonated primary amino group in a blood protein can react with carbon dioxide to form a carbamate as shown here: $$ \mathrm{R}-\mathrm{NH}_{2}+\mathrm{CO}_{2} \longrightarrow \underset{\text { Carbamate }}{\mathrm{R}-\mathrm{NH}-\mathrm{COO}^{-}+\mathrm{H}^{+}} $$ The rate constant \(k\) for this reaction is \(4950 \mathrm{M}^{-1} \cdot \mathrm{s}^{-1}\). a. What is the order of this reaction? b. Calculate the velocity of the reaction of an \(\alpha\)-amino group in a blood protein at \(37^{\circ} \mathrm{C}\) if its concentration is \(0.6 \mathrm{mM}\) and the partial pressure of carbon dioxide is 40 torr. (Hint: Convert the units of partial pressure to molar concentration using the ideal gas law. The value of \(R\) is \(0.0821 \mathrm{~L} \cdot \mathrm{atm} \cdot \mathrm{K}^{-1} \cdot \mathrm{mol}^{-1}\).) c. How would the rate constant for this reaction vary with \(\mathrm{pH}\) ? Explain. d. What \(\mathrm{CO}_{2}\) partial pressure is required to yield a velocity of \(0.045 \mathrm{M} \cdot \mathrm{s}^{-1}\) for the reaction?

Computer-modeling studies have shown that uncompetitive and noncompetitive inhibitors of enzymes are more effective than competitive inhibitors. These studies have important implications in drug design. Propose a hypothesis that explains these results.

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