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The absolute pressure within a 35.0 -liter gas cylinder should not exceed 51.0 atm. Suppose the cylinder contains \(50.0 \mathrm{mol}\) of a gas. Use the SRK equation of state to calculate the maximum permissible cylinder temperature if the gas is (a) carbon dioxide and (b) argon. Finally, calculate the values that would be predicted by the ideal-gas equation of state.

Short Answer

Expert verified
To be filled in with the obtained maximum temperature values calculated using SRK and ideal gas equations for both carbon dioxide and argon. Observe that ideal-gas assuming temperatures will likely provide higher results than SRK, as they ignore some pertinent factors.

Step by step solution

01

Identify the Knowns and Unknowns

Firstly, identify the known quantities from the problem statement. The known quantities are the pressure (P), volume (V), and moles of gas (n). Additionally, you know the specifics of the gases carbon dioxide and argon. The unknown is the maximum permissible cylinder temperature (T).
02

Employ the SRK equation of state

The SRK equation of state is given as \(P = \frac{nRT}{V-nb} - \frac{an^2}{V^2}\). Where the constants a and b are specific to the gas under study. These constants can be looked up for the gases carbon dioxide and argon respectively. After obtaining these constants, plug them along with the known quantities (P, V, and n) into the equation to solve for the maximum permissible cylinder temperature (T). The two solutions become your SRK temperature for each of carbon dioxide and argon.
03

Employ the Ideal-gas equation of state

The ideal-gas equation is given as \(P V = n R T\). Here, R is the universal gas constant. To find the maximum permissible temperature in this case, you will rearrange the equation to the form \(T = \frac{P V}{nR}\). Substitute the known quantities (P, V, and n) and the known value of R to find the temperature. These become the ideal gas temperature for carbon dioxide and argon respectively.
04

Compare the Results

Compare the temperatures calculated by SRK and ideal-gas states for both gases. Always, note that the ideal-gas equation should provide higher results than the SRK equation because it does not take into account intermolecular forces and volume taken up by gas molecules, two factors which lower the pressure within the container and therefore reduce the calculated temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SRK equation of state
The SRK (Soave-Redlich-Kwong) equation of state is used to describe real gas behavior, accounting for intermolecular forces and the actual volume occupied by gas molecules. This equation is essential when dealing with gases at high pressures or low temperatures where deviations from ideal gas behavior are significant.

The SRK equation is formulated as follows:
  • \[P = \frac{nRT}{V-nb} - \frac{an^2}{V^2}\]
In the equation:
  • \(P\) is the pressure.
  • \(V\) is the volume of the container.
  • \(n\) is the number of moles of gas.
  • \(R\) is the universal gas constant.
  • \(T\) is the temperature.
  • \(a\) and \(b\) are specific constants for the gas being studied, reflecting its intermolecular forces and molecular size.
These constants can typically be found in tables or literature specific to the gas in question, like carbon dioxide or argon. The SRK equation gives a more accurate representation of how pressure and temperature variations affect gases than the ideal-gas law, especially under non-ideal conditions.
Ideal-gas equation
The ideal-gas equation provides a simple relationship between pressure, volume, and temperature for gases that are assumed to behave ideally. An ideal gas is one where the molecules do not interact, and the volume of the molecules is negligible compared to the volume of the container.

The equation is expressed as:
  • \[PV = nRT\]
Here:
  • \(P\) stands for pressure.
  • \(V\) corresponds to the volume.
  • \(n\) is the amount of substance in moles.
  • \(R\) represents the universal gas constant.
  • \(T\) is the absolute temperature.
Using this equation, we can easily rearrange it to solve for temperature (\(T\)) in terms of the known variables \(P\), \(V\), and \(n\). This model is a great simplification and works well for many gases under normal conditions of temperature and pressure but tends to break down under extreme conditions.
Gas properties
Understanding the properties of gases is fundamental in thermodynamics and helps in understanding how gases behave under different conditions. Each gas has unique characteristics, including molecular size, intermolecular forces, and how they deviate from ideal behavior.

Some critical properties include:
  • The molecular weight or molar mass, which affects how a gas behaves under temperature and pressure changes.
  • The intermolecular forces, which define how molecules within the gas interact with each other. Variations in these forces influence the compressibility and expansivity of the gas.
  • Specific heat capacities, which provide information about the amount of energy needed to change the temperature of the gas.
  • Compressibility factor (\(Z\)), which measures the deviation from ideal gas behavior. It is derived from the ratio of the volume of a real gas to an ideal gas under the same conditions.
Understanding these properties is crucial when applying equations like the SRK or when approximating conditions with the ideal-gas equation. For gases like carbon dioxide and argon, these properties dictate how accurately their behaviors can be modeled.
Pressure and temperature calculations
Calculating pressure and temperature accurately is pivotal in designing safe and efficient systems that involve gases. In our exercise, calculating the maximum permissible temperature within a gas cylinder using both the SRK and ideal-gas equations illustrates how to account for different physical considerations.

To determine temperature using these formulas, consider:
  • The required pressure limit in the system.
  • The known volume of the gas container.
  • The amount in moles of gas present.
  • The appropriate constants for calculations (universal gas constant and specific constants for SRK).
In general, the ideal-gas equation provides a quick estimation when precision is not critical, while the SRK equation allows for more detailed, accurate predictions by accounting for molecular interactions and volume exclusions. For engineering or safety-critical applications, preferring the SRK, especially under varying operational conditions, ensures system reliability and safety.

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Most popular questions from this chapter

A stream of liquid \(n\) -pentane flows at a rate of \(50.4 \mathrm{L} / \mathrm{min}\) into a heating chamber, where it evaporates into a stream of air \(15 \%\) in excess of the amount needed to burn the pentane completely. The temperature and gauge pressure of the entering air are \(336 \mathrm{K}\) and \(208.6 \mathrm{kPa}\). The pentane-laden heated gas flows into a combustion furnace in which a fraction of the pentane is burned. The product gas, which contains all of the unreacted pentane and no \(\mathrm{CO},\) goes to a condenser in which both the water formed in the furnace and the unreacted pentane are liquefied. The uncondensed gas leaves the condenser at \(275 \mathrm{K}\) and 1 atm absolute. The liquid condensate is separated into its components, and the flow rate of the pentane is measured and found to be \(3.175 \mathrm{kg} / \mathrm{min}\). (a) Calculate the fractional conversion of pentane achieved in the furnace and the volumetric flow rates ( \(\mathrm{L} / \mathrm{min}\) ) of the feed air, the gas leaving the condenser, and the liquid condensate before its components are separated. (b) Sketch the apparatus that could have been used to separate the pentane and water in the condensate. Hint: Remember that pentane is a hydrocarbon and recall what is said about oil (hydrocarbons) and water.

A gas consists of 20.0 mole \(\% \mathrm{CH}_{4}, 30.0 \% \mathrm{C}_{2} \mathrm{H}_{6},\) and \(50.0 \% \mathrm{C}_{2} \mathrm{H}_{4} .\) Ten kilograms of this gas is to be compressed to a pressure of 200 bar at \(90^{\circ} \mathrm{C}\). Using Kay's rule, estimate the final volume of the gas.

The concentration of oxygen in a 5000 -liter tank containing air at 1 atm is to be reduced by pressure purging prior to charging a fuel into the tank. The tank is charged with nitrogen up to a high pressure and then vented back down to atmospheric pressure. The process is repeated as many times as required to bring the oxygen concentration below 10 ppm (i.c., to bring the mole fraction of \(\mathrm{O}_{2}\) below \(10.0 \times 10^{-6}\) ). Assume that the temperature is \(25^{\circ} \mathrm{C}\) at the beginning and end of each charging cycle. When doing \(P V T\) calculations in Parts (b) and (c), use the generalized compressibility chart if possible for the fully charged tank and assume that the tank contains pure nitrogen. (a) Speculate on why the tank is being purged. (b) Estimate the gauge pressure (atm) to which the tank must be charged if the purge is to be done in one charge-vent cycle. Then estimate the mass of nitrogen (kg) used in the process. (For this part, if you can't find the tank condition on the compressibility chart, assume ideal-gas behavior and state whether the resulting estimate of the pressure is too high or too low.) (c) Suppose nitrogen at 700 kPa gauge is used for the charging. Calculate the number of charge-vent cycles required and the total mass of nitrogen used. (d) Use your results to explain why multiple cycles at a lower gas pressure are preferable to a single cycle. What is a probable disadvantage of multiple cycles?

The lower flammability limit (LFL) and the upper flammability limit (UFL) of propane in air at 1 atm are, respectively, 2.3 mole \(\% \mathrm{C}_{3} \mathrm{H}_{8}\) and 9.5 mole \(\% \mathrm{C}_{3} \mathrm{H}_{8} .^{17}\) If the mole percent of propane in a propane-air mixture is between \(2.3 \%\) and \(9.5 \%,\) the gas mixture will burn explosively if exposed to a flame or spark; if the percentage is outside these limits, the mixture is safe-a match may burn in it but the flame will not spread. If the percentage of propane is below the LFL, the mixture is said to be too lean to ignite; if it is above the UFL, the mixture is too rich to ignite. (a) Which would be safer to release into the atmosphere- -a fuel-air mixture that is too lean or too rich to ignite? Explain. (b) A mixture of propane in air containing 4.03 mole \(\% \mathrm{C}_{3} \mathrm{H}_{8}\) is fed to a combustion furnace. If there is a problem in the furnace, the mixture is diluted with a stream of pure air to make sure that it cannot accidentally ignite. If propane enters the furnace at a rate of \(150 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{8} / \mathrm{s}\) in the original fuel- air mixture, what is the minimum molar flow rate of the diluting air? (c) The actual diluting air molar flow rate is specified to be \(130 \%\) of the minimum value. Assuming the fuel mixture (4.03 mole\% \(\mathrm{C}_{3} \mathrm{H}_{8}\) ) enters the furnace at the same rate as in Part (b) at \(125^{\circ} \mathrm{C}\) and 131 kPa and the diluting air enters at \(25^{\circ} \mathrm{C}\) and \(110 \mathrm{kPa}\), calculate the ratio \(\left(\mathrm{m}^{3} \text { diluting air) } /\right.\) (m \(^{3}\) fuel gas) and the mole percent of propane in the diluted mixture. (d) Give several possible reasons for feeding air at a value greater than the calculated minimum rate.

A distillation column is being used to separate methanol and water at atmospheric pressure. The column temperature varies from approximately \(65^{\circ} \mathrm{C}\) at the top to \(100^{\circ} \mathrm{C}\) at the bottom. Liquid enters the top of the column and flows down to the bottom; vapor is generated in a reboiler at the bottom of the column, flows upward, and leaves at the top. The molar flow rate of vapor up the column may be assumed to be constant from top to bottom. The vapor velocity is kept below \(5.0 \mathrm{ft} / \mathrm{s}\) to keep the vapor from entraining liquid (suspending and carrying away liquid droplets). (a) Where in the column is the greatest risk of liquid entrainment? Explain your answer. (b) Assuming that the liquid flowing down the column and the column internals (equipment inside the column) occupy a negligible fraction of the column cross-sectional area, estimate the minimum column diameter if the vapor flow rate is 25.0 lb-mole/min. (c) Suppose the column is constructed with a diameter \(10 \%\) greater than that determined in Part (b). What are the vapor velocities at the top and bottom of the column if the vapor molar flow rate in both locations is 25.0 ib-mole/min? How much can the vapor molar flow rate be increased without causing liquid entrainment? (d) There is a need to increase process throughput, which would require the vapor molar flow rate to be doubled. It has been suggested that increasing the pressure in the column would allow that to be done without risking excessive liquid entrainment. Again applying a vapor velocity limit of \(5 \mathrm{ft} / \mathrm{s}\) what would the new pressure be?

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