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A \(5.0-\mathrm{m}^{3}\) tank is charged with \(75.0 \mathrm{kg}\) of propane gas at \(25^{\circ} \mathrm{C}\). Use the SRK equation of state to estimate the pressure in the tank; then calculate the percentage error that would result from the use of the ideal-gas equation of state for the calculation.

Short Answer

Expert verified
In order to solve this exercise, the pressure in the propane gas tank is estimated first using the SRK equation of state and then using the ideal-gas equation of state. The percentage error that results from the use of the ideal gas equation of state is subsequently calculated by comparing these two pressures.

Step by step solution

01

Understand and use the SRK Equation

The SRK equation of state is given by: \(P = \frac{RT}{(v - b)} - \frac{a}{v(v + b)\sqrt{T}}\). For propane, the specific parameters are given by \(a = 0.42748 \frac{(R^2)(T_c^2)}{P_c}\) and \(b = 0.08664 \frac{RT_c}{P_c}\). For propane, \(T_c = 369.8K\) and \(P_c = 42.48 bar\). Then, within the SRK equation, R is the ideal gas constant (0.08314 bar L/mol K), T is temperature in K and v is molar volume in \(L/mol\).
02

Calculate the pressure using SRK equation

Firstly, convert the given temperature into Kelvin (T = 25ºC = 298.15 K) and find the number of moles of propane (n) by dividing the mass of the gas by the molar mass of propane (n = 75 kg / 44.097 kg/mol = 1700.07 mol). The molar volume v is obtained by dividing the volume of the tank by the number of moles (v = 5.0 m3 / 1700.07 mol = 0.00294 m3/mol = 2.94 L/mol). Plug in these values into the SRK equation to find the pressure P.
03

Calculate the pressure using Ideal Gas Law

The ideal-gas equation of state is given as \(P = \frac{nRT}{V}\), where P is pressure, n is number of moles, R is the gas constant (0.08314 bar L/mol K), T is temperature in K, and V is volume in m3. Using the same values for n, R, T and V as derived in Step 2, calculate the pressure P.
04

Compute the Percentage Error

Percentage error is given by the equation \(Percentage \; Error = \frac{|P_{SRK} - P_{ideal}|}{P_{SRK}} \times 100%\). Substitute the pressure values calculated by the SRK equation and the Ideal Gas Law into the equation to compute the percentage error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SRK Equation
The Soave-Redlich-Kwong (SRK) equation is a popular equation of state used to predict the behavior of real gases. Unlike the Ideal Gas Law, the SRK equation accounts for the interactions between gas molecules and the volume occupied by them. This makes it especially useful for gases under high pressure and temperature conditions. To use the SRK equation, the specific parameters for the gas in question must be known. In our case with propane:
  • The constant a is calculated using the formula: \[a = 0.42748 \frac{(R^2)(T_c^2)}{P_c}\]where T_c and P_c are the critical temperature and pressure of the gas, respectively.
  • The constant b is computed as: \[b = 0.08664 \frac{RT_c}{P_c}\].
These constants correct for the non-ideal behavior of gases. In our example, the calculated pressure using the SRK equation considers the molar volume and temperature of the gas in conditions closer to reality, making the calculation more accurate than the ideal gas assumption would.
Ideal Gas Law
The Ideal Gas Law is a much simpler model for calculating the behavior of gases, expressed as:\[P = \frac{nRT}{V}\]where:
  • P is the pressure of the gas,
  • n is the number of moles,
  • R is the ideal gas constant (0.08314 bar L/mol K),
  • T is the temperature in Kelvin, and
  • V is the volume of the gas.
The assumption made here is that gas molecules do not interact and occupy no space, which is valid only under certain conditions, usually at low pressures and high temperatures relative to the gas's critical point.For our propane example, using the Ideal Gas Law involves inputting the known values of n, R, T, and V to directly find the pressure. However, because real gases deviate from ideal behavior under many conditions, the pressure calculated by this method might not match the actual pressure as closely as the SRK equation would predict.
Percentage Error in Gas Calculations
Percentage error is a way of quantifying the accuracy of an experimental or calculated value by comparing it to a known or more accurate value. In this context, it compares the pressure predicted by the SRK equation to that found using the Ideal Gas Law:\[Percentage \; Error = \frac{|P_{SRK} - P_{ideal}|}{P_{SRK}} \times 100\%\]This formula helps us understand how far off the Ideal Gas Law pressure is from the more accurate SRK equation pressure. When the percentage error is small, it indicates that the ideal gas assumptions are reasonably valid for the given conditions, meaning the gas behaves almost ideally.On the other hand, a larger percentage error suggests that interactions between the gas molecules and their volume are not negligible, warranting the use of more complex equations like SRK for accurate predictions. Thus, understanding percentage errors not only helps us assess the accuracy of a model but also guides us in choosing the appropriate equation of state for different scenarios.

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Most popular questions from this chapter

The current global reliance on fossil fuels for heating, transportation, and electric power generation raises concems regarding the release of \(\mathrm{CO}_{2}\) and \(\mathrm{CH}_{4},\) which are greenhouse gases thought to lead to climate change, and NO, which contributes to smog. One potential solution to these problems is to produce transportation fuels from renewable biomass. You have been asked to evaluate a proposed process for converting forest residues to alcohols that may be used as transportation fuels. In the first stage of the process, steam and dry wood from hybrid poplar trees (which grow between five and eight feet a year and can be harvested roughly every five years) are fed to a gasifier in which the biomass is converted to light gases in the following reactions: $$\begin{aligned} \mathrm{C}+\mathrm{H}_{2} \mathrm{O} & \rightarrow \mathrm{CO}+\mathrm{H}_{2} \\\ \mathrm{CO}+\mathrm{H}_{2} \mathrm{O} & \rightarrow \mathrm{CO}_{2}+\mathrm{H}_{2} \\ \mathrm{C}+\mathrm{CO}_{2} & \rightarrow 2 \mathrm{CO} \\ \mathrm{C}+2 \mathrm{H}_{2} & \rightarrow \mathrm{CH}_{4} \\ \mathrm{CH}_{4}+\mathrm{H}_{2} \mathrm{O} & \rightarrow \mathrm{CO}+3 \mathrm{H}_{2} \end{aligned}$$ The effluents from the reactor are a gas stream containing \(\mathrm{H}_{2}, \mathrm{CO}, \mathrm{CO}_{2}, \mathrm{CH}_{4},\) and \(\mathrm{H}_{2} \mathrm{O},\) and a solid char stream that contains only carbon and hydrogen. The char is discarded and the gases go through additional steps in which the hydrogen and carbon monoxide are converted to mixed alcohols. This problem only concerns the gasifier. \(\cdot\) Elemental composition of biomass: 51.9 mass \(\%\) C \(, 6.3 \%\) H, and \(41.8 \%\) O \(\cdot\) Pressure and temperature of entering steam: \(155^{\circ} \mathrm{C}, 4.4 \mathrm{atm}\) \(\cdot\) Feed ratio of steam to biomass: 1.1 kg steam/kg biomass \(\cdot\) Yield and dry-basis composition of product gas: 1.35 kg dry gas/kg biomass at \(700^{\circ} \mathrm{C}, 1.2\) atm; 50.7 mol\% \(\mathrm{H}_{2}, 23.8 \%\) CO, \(18.0 \% \mathrm{CO}_{2}, 7.5 \% \mathrm{CH}_{4}\) (a) Taking a basis of \(100 \mathrm{kg}\) of biomass fed, draw and completely label a flowchart for the gasifier incorporating the given data, labeling the volumes of the steam fed and the gases produced. Perform a degree-of-freedom analysis. (b) Calculate the mass and mass composition of the char and the volumes of the steam feed and product gas streams. (c) List advantages and possible drawbacks of using biomass rather than petroleum as a fuel source.

When a liquid or a gas occupies a volume, it may be assumed to fill the volume completely. On the other hand, when solid particles occupy a volume, there are always spaces (voids) among the particles. The porosity or void fraction of a bed of particles is the ratio (void volume)/(total bed volume). The bulk density of the solids is the ratio (mass of solids)/(total bed volume), and the absolute density of the solids has the usual definition (mass of solids)/(volume of solids). Suppose \(600.0 \mathrm{g}\) of a crushed ore is placed in a graduated cylinder, filling it to the \(184 \mathrm{cm}^{3}\) level. One hundred \(\mathrm{cm}^{3}\) of water is then added to the cylinder, whereupon the water level is observed to be at the \(233.5 \mathrm{cm}^{3}\) mark. Calculate the porosity of the dry particle bed, the bulk density of the ore in this bed, and the absolute density of the ore.

You have purchased a gas cylinder that is supposed to contain 5.0 mole \(\% \mathrm{Cl}_{2}(\pm 0.1 \%)\) and \(95 \%\) air. The experiments you have been running are not giving reasonable results, and you suspect that the chlorine concentration in the gas cylinder is incorrect. To check this hypothesis, you bubble gas from the suspicious cylinder through \(2.0 \mathrm{L}\) of an aqueous NaOH solution (12.0 wt\% NaOH, SG = 1.13) for exactly one hour. The inlet gas is metered at a gauge pressure of \(510 \mathrm{mm} \mathrm{H}_{2} \mathrm{O}\) and a temperature of \(23^{\circ} \mathrm{C}\). Prior to entering the vessel, the gas passes through a flowmeter that indicates a flow rate of \(2.00 \mathrm{L} / \mathrm{min}\). At the conclusion of the experiment, a sample of the residual \(\mathrm{NaOH}\) solution is analyzed and the results show that the \(\mathrm{NaOH}\) content has been reduced by \(23 \% .\) What is the concentration of \(\mathrm{Cl}_{2}\) in the cylinder gas? (Assume the \(\mathrm{Cl}_{2}\) is completely consumed in the reaction \(\mathrm{Cl}_{2}+2 \mathrm{NaOH} \rightarrow \mathrm{NaCl}+\mathrm{NaOCl}+\mathrm{H}_{2} \mathrm{O}\)

Terephthalic acid (TPA), a raw material in the manufacture of polyester fiber, film, and soft drink bottles, is synthesized from \(p\) -xylene (PX) in the process shown below. A fresh feed of pure liquid \(\mathrm{PX}\) combines with a recycle stream containing \(\mathrm{PX}\) and a solution (S) of a catalyst (a cobalt salt) in a solvent (methanol). The combined stream, which contains \(S\) and \(P X\) in a 3: 1 mass ratio, is fed to a reactor in which \(90 \%\) of the \(\mathrm{PX}\) is converted to TPA. A stream of air at \(25^{\circ} \mathrm{C}\) and 6.0 atm absolute is also fed to the reactor. The air bubbles through the liquid and the reaction given above takes place under the influence of the catalyst. A liquid stream containing unreacted \(\mathrm{PX}\), dissolved TPA, and all the S that entered the reactor goes to a separator in which solid TPA crystals are formed and filtered out of the solution. The filtrate, which contains all the \(S\) and \(P X\) leaving the reactor, is the recycle stream. A gas stream containing unreacted oxygen, nitrogen, and the water formed in the reaction leaves the reactor at \(105^{\circ} \mathrm{C}\) and 5.5 atm absolute and goes through a condenser in which essentially all the water is condensed. The uncondensed gas contains 4.0 mole \(\%\) O. (a) Taking \(100 \mathrm{kmol}\) TPA produced/h as a basis of calculation, draw and label a flowchart for the process. (b) What is the required fresh feed rate (kmol PX/h)? (c) What are the volumetric flow rates \(\left(\mathrm{m}^{3} / \mathrm{h}\right)\) of the air fed to the reactor, the gas leaving the reactor, and the liquid water leaving the condenser? Assume ideal-gas behavior for the two gas streams. (d) What is the mass flow rate ( \(\mathrm{kg} / \mathrm{h}\) ) of the recycle stream? (e) Briefly explain in your own words the functions of the oxygen, nitrogen, catalyst, and solvent in the process. (f) In the actual process, the liquid condensate stream contains both water and PX. Speculate on what might be done with the latter stream to improve the economics of the process. [Hint: Note that PX is expensive, and recall what is said about oil (hydrocarbons) and water.]

A tank in a room at \(19^{\circ} \mathrm{C}\) is initially open to the atmosphere on a day when the barometric pressure is 102 kPa. A block of dry ice (solid \(\mathrm{CO}_{2}\) ) with a mass of \(15.7 \mathrm{kg}\) is dropped into the tank, which is then sealed. The reading on the tank pressure gauge initially rises very quickly, then much more slowly, eventually reaching a value of 3.27 MPa. Assume \(T_{\text {final }}=19^{\circ} \mathrm{C}\) (a) How many moles of air were in the tank initially? Neglect the volume occupied by \(\mathrm{CO}_{2}\) in the solid state, and assume that a negligible amount of \(\mathrm{CO}_{2}\) escapes prior to the sealing of the tank. (b) Estimate the percentage error made by neglecting the volume of the block of dry ice placed in the tank. (The specific gravity of solid carbon dioxide is approximately 1.56 .) (c) What is the final density (g/L) of the gas in the tank? (d) Explain the observed variation of pressure with time. More specifically, what is happening in the tank during the initial rapid pressure increase and during the later slow pressure increase?

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