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A gas consists of 20.0 mole \(\% \mathrm{CH}_{4}, 30.0 \% \mathrm{C}_{2} \mathrm{H}_{6},\) and \(50.0 \% \mathrm{C}_{2} \mathrm{H}_{4} .\) Ten kilograms of this gas is to be compressed to a pressure of 200 bar at \(90^{\circ} \mathrm{C}\). Using Kay's rule, estimate the final volume of the gas.

Short Answer

Expert verified
The final volume is the value obtained from the calculation in Step 5. The procedure involves using Kay's rule to determine the pseudo-critical properties of the gas mixture, and then using these values in the Ideal Gas Law to determine the final volume.

Step by step solution

01

Finding Molar Fractions

First, convert the percentages into mole fractions. Mole fractions are equal to the given percentages divided by 100. Therefore for methane \(CH_4\), we get (20/100)= 0.2, for ethane \(C_2H_6\), (30/100) = 0.3 and for ethylene \(C_2H_4\), (50/100) = 0.5.
02

Calculation of Pseudo Critical Pressure

Calculation of the Pseudo critical pressure (Pc) and Pseudo critical temperature (Tc) by using Kay’s rule. Pseudo critical constants for methane, ethane and ethylene are: \(Pc(CH_4) = 46 bars, Pc(C_2H_6) = 48 bars, Pc(C_2H_4) = 50 bars, Tc(CH_4) = -82.6^{\circ}C, Tc(C_2H_6) =32.2^{\circ}C , Tc(C_2H_4) = 9.9^{\circ}C\). Multiply the mole fraction of each gas by its critical pressure to find the partial pressures. Then add all the partial pressures to obtain the pseudo critical pressure. \(Pc_{mix} = (Peercentage(CH_4) * Pc(CH_4)) + (Peercentage(C_2H_6) * Pc(C_2H_6)) + (Peercentage(C_2H_4) * Pc(C_2H_4)) \)
03

Calculation of Pseudo Critical Temperature

Multiply the mole fraction of each gas by its critical temperature to find the partial temperatures. Then add all the partial temperatures to obtain the pseudo critical temperature. \(Tc_{mix} = (Peercentage(CH_4) * Tc(CH_4)) + (Peercentage(C_2H_6) * Tc(C_2H_6)) + (Peercentage(C_2H_4) * Tc(C_2H_4)) \)
04

Calculation of Reduced Temperature and Pressure

Calculate the reduced temperature and pressure using the formula: \(Tr = T/Tc_{mix}\) and \(Pr = P/Pc_{mix}\) where actual gas temperature T= 90 + 273 = 363K and actual pressure P= 200bar. Note: Convert the temperature to Kelvins by adding 273 to Celsius.
05

Calculate Final Volume

Use the ideal gas law to calculate the final volume \(V= nRT/P\), where R= Ideal gas constant = 83.14(dimension depending on the units of P and V) and n = total moles = mass /molecular weight. The molecular weight is a weighted average calculated by multiplying the molecular weights of the individual gases by their percentages and summing the results: \(MW_{mix} = percentage(CH_4)*MW(CH_4) + percentage(C_2H_6)*MW(C_2H_6) +percentage(C_2H_4)*MW(C_2H_4)\), where \(MW(CH_4) = 16 kg/kmol, MW(C_2H_6) = 30 kg/kmol, MW(C_2H_4) = 28 kg/kmol\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Fractions
Understanding mole fractions is essential in mixture calculations. It's a way to express the composition of a mix without worrying about the actual amount of substance. A mole fraction is the ratio of the number of moles of a component to the total number of moles in the mixture. For example, if a mixture is composed of 20% methane, 30% ethane, and 50% ethylene by moles, we could say the mole fraction of methane is 0.2, of ethane is 0.3, and of ethylene is 0.5.

Why do we care about mole fractions? They allow us to make calculations on mixtures, like finding their average properties or behavior under certain conditions, without dealing with masses or volumes directly. This is especially helpful when we're working with gases, which can expand or compress significantly under different temperatures and pressures.
Pseudo Critical Pressure
The pseudo critical pressure concept is vital when dealing with gas mixtures like in Kay's rule for gas compression. It represents an average critical pressure for a mixture based on its composition. But what is critical pressure in the first place? It's the pressure needed to liquefy a gas at its critical temperature. The pseudo critical pressure is found by taking into account the mole fractions and critical pressures for each individual gas.

For our example with methane, ethane, and ethylene, calculating the pseudo critical pressure involves multiplying each component's mole fraction by its own critical pressure, then summing those numbers. This calculation doesn't just give us a number to plug into formulas—it provides insights into how the mixture behaves under compression compared to pure substances. Finding the intersection of such complex behavior requires us to understand and calculate these pseudo properties.
Pseudo Critical Temperature
Similar to pseudo critical pressure, the pseudo critical temperature is an average critical temperature for a gas mixture. The critical temperature itself is the highest temperature at which a substance can exist as a liquid, regardless of pressure. For mixtures, the pseudo critical temperature is crucial for understanding the thermodynamic behavior during processes like compression.

Using mole fractions and critical temperatures of each gas in our mixture, we find this pseudo value. It's done by multiplying the mole fraction of each gas by its critical temperature and then adding them up. This figure is necessary for finding reduced temperatures and pressures, which are used in various equations to predict a mixture's behavior under different conditions, especially when precise models like Kay's rule are applied.
Ideal Gas Law
The ideal gas law is a cornerstone in understanding the behavior of gases under various conditions. It's usually expressed as PV = nRT, where P stands for pressure, V for volume, n for moles of gas, R for the ideal gas constant, and T for temperature. This equation assumes that gas molecules don't interact with one another and occupy no space—though this isn't true for real gases, it's a useful approximation at standard conditions.

When we consider the compression of a gas mixture using Kay's rule, the ideal gas law can still apply under the assumption that the gas behaves ideally. We use it to calculate the final volume of the gas after compression, taking into account the total number of moles, the temperature in Kelvins, and the pressure in the appropriate units. It's an elegant expression revealing how closely interconnected those physical properties are.
Chemical Process Calculations
Performing chemical process calculations involves applying mathematical methods to chemical processes, allowing engineers and scientists to predict the outcomes under different scenarios. Variables like temperature, pressure, volume, and mole fractions are taken into account, often utilizing laws and rules like the ideal gas law and Kay's rule, respectively.

To reliably forecast the results of compressing our gas mixture, we must calculate the mixture's average molecular weight based on its components' molecular weights and their mole fractions. Then, with all these calculations—from determining mole fractions, pseudo critical properties, reduced temperatures and pressures, to finding average molecular weights—we're equipping ourselves to solve complex problems such as estimating final volumes of compressed gases. These skillsets and calculations are the backbone of designing and operating countless industrial processes in the chemical industry.

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Most popular questions from this chapter

Chemicals are stored in a laboratory with volume \(V\left(\mathrm{m}^{3}\right) .\) As a consequence of poor laboratory practices, a hazardous species, A, enters the room air (from inside the room) at a constant rate \(\dot{m}_{\mathrm{A}}(\mathrm{g} \mathrm{A} / \mathrm{h})\) The room is ventilated with clean air flowing at a constant rate \(\dot{V}_{\text {air }}\left(\mathrm{m}^{3} / \mathrm{h}\right) .\) The average concentration of A in the room air builds up until it reaches a steady-state value \(C_{\mathrm{A}, \mathrm{r}}\left(\mathrm{g} \mathrm{A} / \mathrm{m}^{3}\right)\) (a) List at least four situations that could lead to A getting into the room air. (b) Assume that the A is perfectly mixed with the room air and derive the formula $$\dot{m}_{\mathrm{A}}=\dot{V}_{\mathrm{air}} C_{\mathrm{A}}$$ (c) The assumption of perfect mixing is never justificd when the enclosed space is a room (as opposed to, say, a stirred reactor). In practice, the concentration of A varies from one point in the room to another: it is relatively high near the point where A enters the room air and relatively low in regions far from that point, including the ventilator outlet duct. If we say that \(C_{\mathrm{A}, \text { duct }}=k C_{\mathrm{A}}\) where \(k < 1\) is a nonideal mixing factor (generally between 0.1 and \(0.5,\) with the lowest value corresponding to the poorest mixing), then the equation of Part (b) becomes $$\dot{m}_{\mathrm{A}}=k \dot{V}_{\mathrm{air}} C_{\mathrm{A}}$$ Use this equation and the ideal-gas equation of state to derive the following expression for the average mole fraction of \(A\) in the room air: $$y_{\mathrm{A}}=\frac{\dot{m}_{\mathrm{A}}}{k \dot{V}_{\mathrm{air}}} \frac{R T}{M_{\mathrm{A}} P}$$ where \(M_{\mathrm{A}}\) is the molecular weight of \(\mathrm{A}\) (d) The permissible exposure level (PEL) for styrene \((M=104.14\) ) defined by the U.S. Occupational Safcty and Health Administration is 50 ppm (molar basis). \(^{21}\) An open storage tank in a polymerization laboratory contains styrene. The evaporation rate from this tank is estimated to be \(9.0 \mathrm{g} / \mathrm{h}\). Room temperature is \(20^{\circ} \mathrm{C}\). Assuming that the laboratory air is reasonably well mixed (so that \(k=0.5\) ), calculate the minimum ventilation rate \(\left(\mathrm{m}^{3} / \mathrm{h}\right)\) required to keep the average styrene concentration at or below the PEL. Then give several reasons why working in the laboratory might still be hazardous if the calculated minimum ventilation rate is used. (e) Would the hazard level in the situation described in Part (d) increase or decrease if the temperature in the room were to increase? (Increase, decrease, no way to tell.) Explain your answer, citing at least two effects of temperature in your explanation.

An ideal-gas mixture contains \(35 \%\) helium, \(20 \%\) methane, and \(45 \%\) nitrogen by volume at 2.00 atm absolute and \(90^{\circ} \mathrm{C}\). Calculate (a) the partial pressure of each component, (b) the mass fraction of methane, (c) the average molecular weight of the gas, and (d) the density of the gas in \(\mathrm{kg} / \mathrm{m}^{3}\).

The volume of a steady-state crystallizer is 85,000 L, and the solids fraction in the unit and the exiting stream is 0.35 ; that is, there are \(0.35 \mathrm{kg}\) of crystals per \(\mathrm{kg}\) of slurry (the crystal-solution mixture). The density of the solution is \(1.1 \mathrm{g} / \mathrm{mL}\) and that of the crystals is \(2.3 \mathrm{g} / \mathrm{mL}\). The production rate of crystals from the crystallizer is \(19.5 \mathrm{kg}\) crystals/min. Estimate the volumetric flow rate of slurry from the crystallizer and the drawdown time of the crystallizer (the time it would take to empty the crystallizer if the feed were discontinued).

A stream of hot dry nitrogen flows through a process unit that contains liquid acetone. A substantial portion of the acetone vaporizes and is carried off by the nitrogen. The combined gases leave the recovery unit at \(205^{\circ} \mathrm{C}\) and 1.1 bar and enter a condenser in which a portion of the acetone is liquefied. The remaining gas leaves the condenser at \(10^{\circ} \mathrm{C}\) and 40 bar. The partial pressure of acetone in the feed to the condenser is 0.100 bar, and that in the effluent gas from the condenser is 0.379 bar. Assume ideal-gas behavior. (a) Calculate for a basis of \(1 \mathrm{m}^{3}\) of gas fed to the condenser the mass of acetone condensed ( \(\mathrm{kg}\) ) and the volume of gas leaving the condenser \(\left(\mathrm{m}^{3}\right)\) (b) Suppose the volumetric flow rate of the gas leaving the condenser is \(20.0 \mathrm{m}^{3} / \mathrm{h}\). Calculate the rate (kg/h) at which acetone is vaporized in the solvent recovery unit.

Phosgene (CCl, O) is a colorless gas that was used as an agent of chemical warfare in World War I. It has the odor of new-mown hay (which is a good warning if you know the smell of new-mown hay). Pete Brouillette, an innovative chemical engincering student, came up with what he believed was an effective new process that utilized phosgene as a starting material. He immediately set up a reactor and a system for analyzing the reaction mixture with a gas chromatograph. To calibrate the chromatograph (i.e., to determine its response to a known quantity of phosgene), he evacuated a 15.0 cm length of tubing with an outside diameter of \(0.635 \mathrm{cm}\) and a wall thickness of \(0.559 \mathrm{mm}\), and then connected the tube to the outlet valve of a cylinder containing pure phosgene. The idea was to crack the valve, fill the tube with phosgene, close the valve, feed the tube contents into the chromatograph, and observe the instrument response. What Pete hadn't thought about (among other things) was that the phosgene was stored in the cylinder at a pressure high enough for it to be a liquid. When he opened the cylinder valve, the liquid rapidly flowed into the tube and filled it. Now he was stuck with a tube full of liquid phosgene at a pressure the tube was not designed to support. Within a minute he was reminded of a tractor ride his father had once given him through a hayfield, and he knew that the phosgene was leaking. He quickly ran out of the lab, called campus security, and told them that a toxic leak had occurred, that the building had to be evacuated, and the tube removed and disposed of properly. Personnel in air masks shortly appeared, took care of the problem, and then began an investigation that is still continuing. (a) Show why one of the reasons phosgene was an effective weapon is that it would collect in low spots soldiers often mistakenly entered for protection. (b) Pete's intention was to let the tube equilibrate at room temperature ( \(23^{\circ} \mathrm{C}\) ) and atmospheric pressure. How many gram-moles of phosgene would have been contained in the sample fed to the chromatograph if his plan had worked? (c) The laboratory in which Pete was working had a volume of \(2200 \mathrm{ft}^{3}\), the specific gravity of liquid phosgene is \(1.37,\) and Pete had read somewhere that the maximum "safe" concentration of phosgene in air is \(0.1 \mathrm{ppm}\) \(\left(0.1 \times 10^{-6} \mathrm{mol} \mathrm{CCl}_{2} \mathrm{O} / \mathrm{mol}\) air) \right. Would the "safe" concentration have been exceeded if all the liquid phosgene in the tube had evaporated into the room? Even if the limit would not have been exceeded, give several reasons why the lab would still have been unsafe. (d) List several things Pete did (or failed to do) that made his experiment unnecessarily hazardous.

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