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Seawater containing 3.50 wt\% salt passes through a series of 10 evaporators. Roughly equal quantities of water are vaporized in each of the 10 units and then condensed and combined to obtain a product stream of fresh water. The brine leaving each evaporator but the tenth is fed to the next evaporator. The brine leaving the tenth evaporator contains \(5.00 \mathrm{wt} \%\) salt. (a) Draw a flowchart of the process showing the first, fourth, and tenth evaporators. Label all the streams entering and leaving these three evaporators. (b) Write in order the set of equations you would solve to determine the fractional yield of fresh water from the process \(\left(\mathrm{kg} \mathrm{H}_{2} \mathrm{O} \text { recovered } / \mathrm{kg} \mathrm{H}_{2} \mathrm{O}\) in process feed) and the weight percent of salt in the \right. solution leaving the fourth evaporator. Each equation you write should contain no more than one previously undetermined variable. In each equation, circle the variable for which you would solve. Do not do the calculations. (c) Solve the equations derived in Part (b) for the two specified quantities. (d) The problem statement made no mention of the disposition of the 5 wt\% effluent from the tenth evaporator. Suggest two possibilities for its disposition and describe any environmental concerns that might need to be considered.

Short Answer

Expert verified
The solution involved drawing a flowchart of the evaporation process, creating and solving equations for the fractional yield of fresh water and the concentration of salt, and considering potential dispositions and environmental impacts of the effluent.

Step by step solution

01

Drawing a Flowchart

To draw the flow chart, each evaporator can be represented as a square box. Salt water is entering the first evaporator and water vapor is being removed from each unit, which can be represented by arrows. The concentrated brine is transferred to the next evaporator. This is done repetitively from the first to fourth and then to tenth evaporator, where the effluent containing 5% of salt is finally released. The condensed water vapor from all the units is combined and considered as the product stream.
02

Setting Up Equations

To find the fractional yield of fresh water, we will consider the total water entering the process, denoted by \(W_{total}\), and the total water vapor removed, denoted by \(W_{removed}\). We can then calculate the fraction of water recovered, \(frac_{water}\), as \(frac_{water} = W_{removed}/W_{total}\). For the weight percent of salt in the solution leaving the fourth evaporator, denote the initial and final weight percentages as \(P_{initial}\) and \(P_{final}\), respectively. Using the concentration change principle, we can set up the equation \(P_{final} = P_{initial} \cdot W_{total} / (W_{total} - W_{removed})\). In both equations, the circled variable to solve for is the one on the left side.
03

Solving The Equations

To solve the equations, remember that for every evaporator, the mass of water removed is roughly equal. The equations set up in the previous step should be used to derive the fractional yield of fresh water and the weight percent of salt.
04

Disposition of The Effluent

Two possible dispositions of the effluent from the tenth evaporator could be: (1) Discharging it directly to the sea, which may affect marine life due to salinity changes; (2) using it to extract valuable salts and minerals. The latter option would involve significant energy and equipment costs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Process Flowchart Creation
Creating a process flowchart is an essential step in understanding and communicating the stages involved in seawater treatment for fresh water extraction.Making the process visual through a flowchart aids in grasping the complexities of the treatment process, readily identifying where each part of the system links to the next, and sequentially showcasing the progression from one stage to another.

A flowchart for seawater treatment could begin with an intake where sea water enters the treatment facility. It would then progress through representation of the series of evaporators, where each evaporator is a node in the flowchart, interconnected by lines depicting the flow of water and brine. For each of these evaporators—first, fourth, and tenth—specific streams entering and leaving are illustrated. These would include streams for the incoming seawater, vaporized water, and the increasingly concentrated brine moving from one evaporator to the next. It's essential that all relevant streams are clearly labelled to establish a clear understanding for anyone analyzing the flow of materials through the evaporators.
Fractional Yield of Fresh Water
The fractional yield of fresh water is a critical parameter in any desalination process as it measures the efficiency of the water recovery. It is defined as the ratio of the mass of fresh water recovered to the mass of the original seawater fed into the process.

To calculate the fractional yield, \( frac_{water} \), equations are set up considering the total mass of water entering the process, \( W_{total} \), and the mass of water vapor removed and subsequently condensed, \( W_{removed} \). The key to these calculations is to ensure that the equations contain only one undetermined variable at a time, thereby simplifying the problem solving for variables step by step. For instance, if we know the total water input and the water lost to evaporation, we can use the provided values to solve for the fractional yield. If the process operates efficiently, we should observe a high fractional yield, indicating that a significant portion of the input water has been converted into fresh water.
Environmental Impact of Brine Effluent
The disposal of brine effluent is one of the main environmental concerns associated with seawater treatment processes. Brine, being a highly concentrated salt solution, can have detrimental effects on marine ecosystems if not managed properly. For instance, discharging brine back into the ocean can increase local salinity levels, which can harm marine flora and fauna.

When discussing the environmental impact of brine effluent, two primary disposal methods are often considered: direct discharge into the sea, which is cost-effective but potentially harmful to aquatic life, and further treatment to extract valuable minerals, which can mitigate environmental risks but with higher capital and operating costs. It's important for students to understand that the chosen method of brine disposal should carefully consider the surrounding environment, regulatory requirements, and potential recovery of resources to reduce negative environmental impacts. These solutions underscore the need for sustainable practices in water treatment to protect our oceans and marine biodiversity.

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Most popular questions from this chapter

In the Deacon process for the manufacture of chlorine, HCI and \(\mathrm{O}_{2}\) react to form \(\mathrm{Cl}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) Sufficient air ( 21 mole \(\% \mathrm{O}_{2}, 79 \% \mathrm{N}_{2}\) ) is fed to provide \(35 \%\) excess oxygen, and the fractional conversion of HCl is \(85 \%\) (a) Calculate the mole fractions of the product stream components, using atomic species balances in your calculation. (b) Again calculate the mole fractions of the product stream components, only this time use the extent of reaction in the calculation. (c) An alternative to using air as the oxygen source would be to feed pure oxygen to the reactor. Running with oxygen imposes a significant extra process cost relative to running with air, but also offers the potential for considerable savings. Speculate on what the cost and savings might be. What would determine which way the process should be run?

A stream of humid air containing 1.50 mole \(\% \mathrm{H}_{2} \mathrm{O}(\mathrm{v})\) and the balance dry air is to be humidified to a water content of 10.0 mole\% \(\mathrm{H}_{2} \mathrm{O}\). For this purpose, liquid water is fed through a flowmeter and evaporated into the air stream. The flowmeter reading, \(R\), is \(95 .\) The only available calibration data for the flowmeter are two points scribbled on a sheet of paper, indicating that readings \(R=15\) and \(R=50\) correspond to flow rates \(\dot{V}=40.0 \mathrm{ft}^{3} / \mathrm{h}\) and \(\dot{V}=96.9 \mathrm{ft}^{3} / \mathrm{h},\) respectively. (a) Assuming that the process is working as intended, draw and label the flowchart, do the degree-offreedom analysis, and estimate the molar flow rate (lb-mole/h) of the humidified (outlet) air if (i) the volumetric flow rate is a linear function of \(R\) and (ii) the reading \(R\) is a linear function of \(\dot{V}^{0.5}\) (b) Suppose the outlet air is analyzed and found to contain only \(7 \%\) water instead of the desired \(10 \%\) List as many possible reasons as you can think of for the discrepancy, concentrating on assumptions made in the calculation of Part (a) that might be violated in the real process.

Methane reacts with chlorine to produce methyl chloride and hydrogen chloride. Once formed, the methyl chloride may undergo further chlorination to form methylene chloride ( \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) ), chloroform, and carbon tetrachloride. A methyl chloride production process consists of a reactor, a condenser, a distillation column, and an absorption column. A gas stream containing 80.0 mole \(\%\) methane and the balance chlorine is fed to the reactor. In the reactor a single-pass chlorine conversion of essentially \(100 \%\) is attained, the mole ratio of methyl chloride to methylene chloride in the product is \(5: 1,\) and negligible amounts of chloroform and carbon tetrachloride are formed. The product stream flows to the condenser. Two streams emerge from the condenser: the liquid condensate, which contains essentially all of the methyl chloride and methylene chloride in the reactor effluent, and a gas containing the methane and hydrogen chloride. The condensate goes to the distillation column in which the two component species are separated. The gas leaving the condenser flows to the absorption column where it contacts an aqueous solution. The solution absorbs essentially all of the HCl and none of the \(\mathrm{CH}_{4}\) in the feed. The liquid leaving the absorber is pumped elsewhere in the plant for further processing, and the methane is recycled to join the fresh feed to the process (a mixture of methane and chlorine). The combined stream is the feed to the reactor. (a) Choose a quantity of the reactor feed as a basis of calculation, draw and label a flowchart, and determine the degrees of freedom for the overall process and each single unit and stream mixing point. Then write in order the equations you would use to calculate the molar flow rate and molar composition of the fresh feed, the rate at which HCI must be removed in the absorber, the methyl chloride production rate, and the molar flow rate of the recycle stream. Do no calculations. (b) Calculate the quantities specified in Part (a), either manually or with an equation-solving program. (c) What molar flow rates and compositions of the fresh feed and the recycle stream are required to achieve a methyl chloride production rate of \(1000 \mathrm{kg} / \mathrm{h} ?\)

Methane and oxygen react in the presence of a catalyst to form formaldehyde. In a parallel reaction, methane is oxidized to carbon dioxide and water: $$\begin{aligned} \mathrm{CH}_{4}+\mathrm{O}_{2} & \rightarrow \mathrm{HCHO}+\mathrm{H}_{2} \mathrm{O} \\ \mathrm{CH}_{4}+2 \mathrm{O}_{2} & \rightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \end{aligned}$$ The feed to the reactor contains equimolar amounts of methane and oxygen. Assume a basis of \(100 \mathrm{mol}\) feed/s. (a) Draw and label a flowchart. Use a degree-of-freedom analysis based on extents of reaction to determine how many process variable values must be specified for the remaining variable values to be calculated. (b) Use Equation 4.6-7 to derive expressions for the product stream component flow rates in terms of the two extents of reaction, \(\xi_{1}\) and \(\xi_{2}\) (c) The fractional conversion of methane is 0.900 and the fractional yield of formaldehyde is 0.855 . Calculate the molar composition of the reactor output stream and the selectivity of formaldehyde production relative to carbon dioxide production. (d) A classmate of yours makes the following observation: "If you add the stoichiometric equations for the two reactions, you get the balanced equation $$2 \mathrm{CH}_{4}+3 \mathrm{O}_{2} \rightarrow \mathrm{HCHO}+\mathrm{CO}_{2}+3 \mathrm{H}_{2} \mathrm{O}$$ The reactor output must therefore contain one mole of \(\mathrm{CO}_{2}\) for every mole of HCHO, so the selectivity of formaldehyde to carbon dioxide must be \(1.0 .\) Doing it the way the book said to do it, \(I\) got a different selectivity. Which way is right, and why is the other way wrong?" What is your response?

Water enters a \(2.00-\mathrm{m}^{3}\) tank at a rate of \(6.00 \mathrm{kg} / \mathrm{s}\) and is withdrawn at a rate of \(3.00 \mathrm{kg} / \mathrm{s}\). The tank is initially half full. (a) Is this process continuous, batch, or semibatch? Is it transient or steady state? (b) Write a mass balance for the process (see Example 4.2-1). Identify the terms of the general balance equation (Equation 4.2-1) present in your equation and state the reason for omitting any terms. (c) How long will the tank take to overflow?

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