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Water enters a \(2.00-\mathrm{m}^{3}\) tank at a rate of \(6.00 \mathrm{kg} / \mathrm{s}\) and is withdrawn at a rate of \(3.00 \mathrm{kg} / \mathrm{s}\). The tank is initially half full. (a) Is this process continuous, batch, or semibatch? Is it transient or steady state? (b) Write a mass balance for the process (see Example 4.2-1). Identify the terms of the general balance equation (Equation 4.2-1) present in your equation and state the reason for omitting any terms. (c) How long will the tank take to overflow?

Short Answer

Expert verified
a) This is a semi-batch transient process. b) The mass balance equation is dV/dt = (6.00 kg/s - 3.00 kg/s) / 1000 kg/m3. c) The tank will overflow after 250 seconds.

Step by step solution

01

Identifying the process

Usually, we have three types of processes, namely continuous process, batch process, or semi-batch process. That depends on whether any material is added or removed from the system over time. Since in this case, both adding and removing of water are simultaneously happening, it is a semi-batch process. Regarding its state, because there's a change in the system with time (as the amount of water in the tank is changing due to the difference in inflow and outflow), the process is transient.
02

Formulating the mass balance equation

The general form of a mass balance equation includes terms for accumulation, in flow, out flow and generation. In this case, the generation term is zero because water is neither being created nor destroyed inside the tank. Thus, the mass balance equation becomes: Accumulation = Inflow - Outflow.
03

Setting up the equation

The flow rates given are in terms of mass (kg/s). Therefore, we'll need to convert them to a volume flow rate by dividing by the density of water, which is about 1000 kg/m3. Then we can apply the mass balance equation developed in Step 2. Thus the equation becomes: change in volume with respect to time = Inflow rate - Outflow rate. This further simplifies to: dV/dt = (6.00 kg/s - 3.00 kg/s) / 1000 kg/m3 = 0.003 m3/s.
04

Solving for time

The time it will take for the tank to be filled up can be calculated by dividing the volume left to be filled by the net volume flow rate (the difference between the inflow and outflow). This can be obtained by integrating the equation from Step 3 over the volume from \(2.00 m3/2\) to \(2.00 m3\), and finding the corresponding time it takes. So, t = ∫(dV/((6 - 3)/1000 kg/m3) = (2 m3 - 2 m3 / 2) / (0.003 m3/s) = 250 seconds. Thus, it will take 250 seconds for the tank to be completely filled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Semi-Batch Process
In chemical process engineering, a semi-batch process is a blend between batch and continuous processes. It involves both the continuous addition and removal of materials from the system.
For instance, imagine you're filling a bathtub while also draining water out. If the tap's flow is faster than the drain, eventually, the bathtub will overflow. This is similar to the tank scenario mentioned in the exercise. The tank is the 'bathtub,' with water constantly entering and leaving. Because there's simultaneous input and output, it's called a semi-batch process.
In real-world applications, semi-batch processes are quite beneficial. They offer flexibility, allowing for controlled reactions, and can be adapted to optimize product yield or purity. Think of it as having a more sophisticated control on your bathtub, where you tweak the inflow and outflow to maintain the right amount of water you need. This is particularly useful in chemical reactions needing precise ingredient additions or in waste treatment processes.
Mass Balance Equation
Moving on, we encounter the mass balance equation—an essential tool for engineers to track the amount of mass moving in and out of a system.
Using our previous bathtub analogy, it's like having a ledger that notes every cup of water added and every cup drained, to keep track of how much water is in the tub at any time.
In more technical terms, the mass balance equation is formulated as: Accumulation = Inflow - Outflow + Generation - Consumption. Here, generation and consumption refer to chemical reactions creating or using up the substance, but since our tank example involves plain water without any reactions, these terms are zero.
  • Accumulation: Represents the change in mass within the system over time.
  • Inflow: The incoming mass to the system (6 kg/s of water entering the tank).
  • Outflow: The outgoing mass from the system (3 kg/s of water leaving the tank).
The difference between inflow and outflow shows whether the mass in the system accumulates or decreases. It's fundamental in designing all sorts of processes, from megastructures like dams to miniature chemical reactors.
Transient State Analysis
Finally, transient state analysis is the examination of non-steady-state conditions, where variables such as concentration or temperature change with time within the system.
Consider when you first turn on the heat under a pot of water. For a while, the water temperature will keep rising—it's not constant. This period, until the water starts boiling at a steady temperature, is akin to a transient state. In the tank scenario, since the water level changes over time (due to different inflow and outflow rates), we’re also dealing with a transient system.
Engineers must understand these changing conditions to design systems that can cope with fluctuations without failure. In our case, knowing how long before the tank overflows is crucial to prevent spillage. Transient analysis involves a lot of differential equations, as seen in the step-by-step solution, to track how the system evolves over time.
This insight goes beyond just tanks—it's used in environmental engineering to predict pollutant spread in a lake, in mechanical engineering to understand heat transfer in car engines, and in nearly every corner where change occurs over time.

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Most popular questions from this chapter

n-Pentane is burned with excess air in a continuous combustion chamber. (a) A technician runs an analysis and reports that the product gas contains 0.270 mole\% pentane, \(5.3 \%\) oxygen, \(9.1 \%\) carbon dioxide, and the balance nitrogen on \(a\) dry basis. Assume 100 mol of dry product gas as a basis of calculation, draw and label a flowchart, perform a degree-offreedom analysis based on atomic species balances, and show that the system has -1 degree of freedom. Interpret this result. (b) Use balances to prove that the reported percentages could not possibly be correct. (c) The technician reruns the analysis and reports new values of 0.304 mole\% pentane, \(5.9 \%\) oxygen, \(10.2 \%\) carbon dioxide, and the balance nitrogen. Verify that this result could be correct and, assuming that it is, calculate the percent excess air fed to the reactor and the fractional conversion of pentane. (d) It was emphasized in Part (c) that the new composition could be correct. Explain why it isn't possible to say for sure; illustrate your response by considering a set of equations with -1 degree of freedom.

A liquid mixture containing 30.0 mole \(\%\) benzene \((\mathrm{B}), 25.0 \%\) toluene \((\mathrm{T}),\) and the balance xylene \((\mathrm{X})\) is fed to a distillation column. The bottoms product contains 98.0 mole \(\% \mathrm{X}\) and no \(\mathrm{B},\) and \(96.0 \%\) of the \(\mathrm{X}\) in the feed is recovered in this stream. The overhead product is fed to a second column. The overhead product from the second column contains \(97.0 \%\) of the \(\mathrm{B}\) in the feed to this column. The composition of this stream is 94.0 mole\% B and the balance T. (a) Draw and label a flowchart of this process and do the degree-of-freedom analysis to prove that for an assumed basis of calculation, molar flow rates and compositions of all process streams can be calculated from the given information. Write in order the equations you would solve to calculate unknown process variables. In each equation (or pair of simultaneous equations), circle the variable(s) for which you would solve. Do not do the calculations. (b) Calculate (i) the percentage of the benzene in the process feed (i.e., the feed to the first column) that emerges in the overhead product from the second column and (ii) the percentage of toluene in the process feed that emerges in the bottom product from the second column.

Ethylene oxide is produced by the catalytic oxidation of ethylene: $$ 2 \mathrm{C}_{2} \mathrm{H}_{4}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O} $$ An undesired competing reaction is the combustion of ethylene: $$ \mathrm{C}_{2} \mathrm{H}_{4}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} $$ The feed to the reactor (not the fresh feed to the process) contains 3 moles of ethylene per mole of oxygen. The single-pass conversion of ethylene is \(20 \%,\) and for every 100 moles of ethylene consumed in the reactor, 90 moles of ethylene oxide emerge in the reactor products. A multiple-unit process is used to separate the products: ethylene and oxygen are recycled to the reactor, ethylene oxide is sold as a product, and carbon dioxide and water are discarded. (a) Assume a quantity of the reactor feed stream as a basis of calculation, draw and label the flowchart, perform a degree-of-freedom analysis, and write the equations you would use to calculate (i) the molar flow rates of ethylene and oxygen in the fresh feed, (ii) the production rate of ethylene oxide, and (iii) the overall conversion of ethylene. Do no calculations. (b) Calculate the quantities specified in Part (a), either manually or with an equation-solving program. (c) Calculate the molar flow rates of ethylene and oxygen in the fresh feed needed to produce 1 ton per hour of ethylene oxide.

The hormone estrogen is produced in the ovaries of females and elsewhere in the body in men and postmenopausal women, and it is also administered in estrogen replacement therapy, a common treatment for women who have undergone a hysterectomy. Unfortunately, it also binds to estrogen receptors in breast tissue and can activate cells to become cancerous. Tamoxifen is a drug that also binds to estrogen receptors but does not activate cells, in effect blocking the receptors from access to estrogen and inhibiting the growth of breast-cancer cells. Tamoxifen is administered in tablet form. In the manufacturing process, a finely ground powder contains tamoxifen (tam) and two inactive fillers- -lactose monohydrate (lac) and corn starch (cs). The powder is mixed with a second stream containing water and suspended solid particles of polyvinylpymolidone (pvp) binder, which keeps the tablets from easily crumbling. The slurry leaving the mixer goes to a dryer, in which 94.2\% of the water fed to the process is vaporized. The wet powder leaving the dryer contains 8.80 wr\% tam, 66.8\% lac, 21.4\% cs, 2.00\% pvp, and 1.00\% water. After some additional processing, the powder is molded into tablets. To produce a hundred thousand tablets, 17.13 kg of wet powder is required. (a) Taking a basis of 100,000 tablets produced, draw and label a process flowchart, labeling masses of individual components rather than total masses and component mass fractions. It is unnecessary to label the stream between the mixer and the dryer. Carry out a degree-of-freedom analysis of the overall two-unit process. (b) Calculate the masses and compositions of the streams that must enter the mixer to make 100,000 tablets. (c) Why was it unnecessary to label the stream between the mixer and the dryer? Under what circumstances would it have been necessary? (d) Go back to the flowchart of Part (a). Without using the mass of the wet powder (17.13 kg) or any of the results from Part (b) in your calculations, determine the mass fractions of the stream components in the powder fed to the mixer and verify that they match your solution to Part (b). (Hint: Take a basis of \(100 \mathrm{kg}\) of wet powder.) (e) Suppose a student does Part (d) before Part (b), and re-labels the powder feed to the mixer on the flowchart of Part (a) with an unknown total mass ( \(m_{1}\) ) and the three now known mole fractions. (Sketch the resulting flowchart.) The student then does a degree-of-freedom analysis, counts four unknowns (the masses of the powder, pvp, and water fed to the mixer, and the mass of water evaporated in the dryer), and six equations (five material balances for five species and the percentage evaporation), for a net of -2 degrees of freedom. since there are more equations than unknowns, it should not be possible to get a unique solution for the four unknowns. Nevertheless, the student writes four equations, solves for the four unknowns, and verifies that all of the balance equations are satisfied. There must have been a mistake in the degree-of-freedom calculation. What was it?

Chlorobenzene \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\right),\) an important solvent and intermediate in the production of many other chemicals, is produced by bubbling chlorine gas through liquid benzene in the presence of ferric chloride catalyst. In an undesired side reaction, the product is further chlorinated to dichlorobenzene, and in a third reaction the dichlorobenzene is chlorinated to trichlorobenzene. The feed to a chlorination reactor consists of essentially pure benzene and a technical grade of chlorine gas (98 wt\% \(\mathrm{Cl}_{2}\), the balance gaseous impurities with an average molecular weight of 25.0 ). The liquid output from the reactor contains \(65.0 \mathrm{wt} \% \mathrm{C}_{6} \mathrm{H}_{6}, 32.0 \% \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}, 2.5 \% \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{Cl}_{2},\) and \(0.5 \%\) \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Cl}_{3} .\) The gaseous output contains only \(\mathrm{HCl}\) and the impurities that entered with the chlorine. (a) You wish to determine (i) the percentage by which benzene is fed in excess, (ii) the fractional conversion of benzene, (iii) the fractional yield of monochlorobenzene, and (iv) the mass ratio of the gas feed to the liquid feed. Without doing any calculations, prove that you have enough information about the process to determine these quantities. (b) Perform the calculations. (c) Why would benzene be fed in excess and the fractional conversion kept low? (d) What might be done with the gaseous effluent? (e) It is possible to use 99.9\% pure ("reagent-grade") chlorine instead of the technical grade actually used in the process. Why is this probably not done? Under what conditions might extremely pure reactants be called for in a commercial process? (Hint: Think about possible problems associated with the impurities in technical grade chemicals.)

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