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A stream consisting of 44.6 mole \(\%\) benzene and \(55.4 \%\) toluene is fed at a constant rate to a process unit that produces two product streams, one a vapor and the other a liquid. The vapor flow rate is initially zero and asymptotically approaches half of the molar flow rate of the feed stream. Throughout this entire period, no material accumulates in the unit. When the vapor flow rate has become constant, the liquid is analyzed and found to be 28.0 mole\% benzene. (a) Sketch a plot of liquid and vapor flow rates versus time from startup to when the flow rates become constant. (b) Is this process batch or continuous? Is it transient or steady-state before the vapor flow rate reaches its asymptotic limit? What about after it becomes constant? (c) For a feed rate of 100 mol/min, draw and fully label a flowchart for the process after the vapor flow rate has reached its limiting value, and then use balances to calculate the molar flow rate of the liquid and the composition of the vapor in mole fractions.

Short Answer

Expert verified
The process is continuous and moves from transient to steady state. The vapor flow rate of benzene can be calculated using mass balance equations. The mole fraction of toluene in vapor and liquid streams is calculated as the difference between 1 and the mole fraction of benzene in the respective streams.

Step by step solution

01

Identify the nature of the process

The process starts with a single input feed and divides it into two product streams. One stream is vapor and the other is liquid. There are no losses, conversion or accumulation which meets the criteria of a splitting process.
02

Understanding of batch & continuous process

In a batch process, material is processed in definite batches and at the end of processing, the entire batch is removed from the equipment. Also, batch processing typically involves time variation. On the other hand, in a continuous process, the feed and products are continuously added and taken from the unit respectively. Here, since the operation is performed at a constant feed rate, the process is continuous.
03

Understanding of transient & steady-state process

In a transient state, the process variables change with time until the steady state is reached. Once steady state is achieved, variables like flow rate, concentration, temperature do not change with time. Here, the vapor flow rate initially varies and then eventually becomes constant indicating that the process moves from transient to steady state.
04

Draw a plot of liquid and vapor flow rates versus time

At startup, the vapor flow rate is zero and it increases over time eventually becoming a constant value, which is half of the molar feed rate. On the other hand, since the total matter does not accumulate in the system, any increase in the vapor flow rate must be counteracted by a reduction in the liquid flow rate. Therefore, at startup, the liquid flow rate is equal to the feed rate and it decreases until it reaches its steady state value, which is also half of the molar feed rate.
05

Mass balance calculation

Perform a mass balance calculation for both benzene and toluene to determine the molar flow rate and composition of the vapor product. For benzene, it is given by \( 0.446 * Feed Rate = Vapor Flow * Vapor mole fraction + Liquid Flow * Liquid mole fraction \). Similarly, a balance for toluene can be calculated. Substituting feed rate as 100 mol/min, vapor flow rate as 50 mol/min and liquid mole fraction of benzene as 0.280 in the above mentioned equation enables us to solve for the vapor mole fraction of benzene.
06

Calculation of toluene in vapor and liquid streams

As the process involves only benzene and toluene, the sum of mole fractions in every stream should be equal to 1. Therefore, the mole fraction of toluene in vapor and liquid streams can be calculated by subtracting the respective mole fractions of benzene from 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Balance
In chemical process engineering, performing a mass balance is critical for analyzing how stream compositions and flow rates interact in a system. Mass balance involves accounting for the intake, distribution, and exit of materials. In the exercise, a mass balance focuses on a feed stream being split into vapor and liquid streams. Applying this concept ensures that the sum of the input equals the sum of the outputs since no accumulation occurs within the unit. For example, the mass flow rate of benzene and toluene entering the system must match the combined rates leaving in vapor and liquid forms. A mass balance equation might look like this for benzene:
  • \( 0.446 \, \text{mole fraction} \times \text{Feed Rate} = \text{Vapor Flow Rate} \times \text{Vapor mole fraction} + \text{Liquid Flow Rate} \times \text{Liquid mole fraction} \).
This equation ensures all molecules in the process are accounted for and transitions the understanding toward the equilibrium and split behavior of these substances.
Transient State
The transient state in a chemical process refers to the period during which variables—such as flow rate or concentration—change with time. This phase occurs before reaching steady state, highlighting the system's gradual change towards equilibrium. In our exercise, the process starts with a newly introduced feed. Initially, no vapor is present, marking a transient state. Consequently, the vapor flow rate will rise from zero until it stabilizes. During this time, you observe shifting compositions and flow rates that create dynamic conditions. Understanding transient conditions is essential for predicting how a system reaches its final output or equilibrium state, accommodating any operational variability and ensuring system stability.
Steady State
Thriving at steady state is the goal for many continuous processes in chemical engineering. Once reached, steady state means that key variables remain constant over time. In the context of the exercise, once the vapor flow rate becomes constant, so do other variables such as composition and flow rates of the liquid and vapor outlets. At this point, one can consistently predict outputs, optimizing the process for efficiency and desired product quality. Steady state greatly simplifies calculations and control since introductions and removals balance out, leading to stable operation irrespective of the complex dynamics that may have preceded it.
Continuous Process
Continuous processes are characterized by the uninterrupted feeding of materials and extraction of products. In contrast to batch processes, which require stopping and starting, continuous processes maintain a state of equilibrium. In this exercise, the feed is introduced to the system at a constant rate, indicating a continuous process. By maintaining consistent input and output levels, downtime is minimized, allowing for efficient material use and consistent product quality. Continuous processes are ideal for large-scale production due to their ability to manage sustained operations with less intervention.
Vapor-Liquid Equilibrium
Vapor-liquid equilibrium (VLE) is a crucial concept for understanding the distribution of compound components between vapor and liquid phases at given conditions. In the context of the exercise, VLE principles help define how benzene and toluene distribute themselves between the vapor and liquid streams.
  • In a state of equilibrium, at a given temperature and pressure, the chemical potential of each component is equal in both phases.
  • This means that the concentrations in the liquid and vapor phases become stable.
Understanding VLE allows engineers to predict component behavior, facilitating the design of efficient separation and purification processes. The composition in each phase is important for calculating mole fractions of the liquid and vapor streams, making VLE analysis integral to process optimization.

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Most popular questions from this chapter

Methane and oxygen react in the presence of a catalyst to form formaldehyde. In a parallel reaction, methane is oxidized to carbon dioxide and water: $$\begin{aligned} \mathrm{CH}_{4}+\mathrm{O}_{2} & \rightarrow \mathrm{HCHO}+\mathrm{H}_{2} \mathrm{O} \\ \mathrm{CH}_{4}+2 \mathrm{O}_{2} & \rightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \end{aligned}$$ The feed to the reactor contains equimolar amounts of methane and oxygen. Assume a basis of \(100 \mathrm{mol}\) feed/s. (a) Draw and label a flowchart. Use a degree-of-freedom analysis based on extents of reaction to determine how many process variable values must be specified for the remaining variable values to be calculated. (b) Use Equation 4.6-7 to derive expressions for the product stream component flow rates in terms of the two extents of reaction, \(\xi_{1}\) and \(\xi_{2}\) (c) The fractional conversion of methane is 0.900 and the fractional yield of formaldehyde is 0.855 . Calculate the molar composition of the reactor output stream and the selectivity of formaldehyde production relative to carbon dioxide production. (d) A classmate of yours makes the following observation: "If you add the stoichiometric equations for the two reactions, you get the balanced equation $$2 \mathrm{CH}_{4}+3 \mathrm{O}_{2} \rightarrow \mathrm{HCHO}+\mathrm{CO}_{2}+3 \mathrm{H}_{2} \mathrm{O}$$ The reactor output must therefore contain one mole of \(\mathrm{CO}_{2}\) for every mole of HCHO, so the selectivity of formaldehyde to carbon dioxide must be \(1.0 .\) Doing it the way the book said to do it, \(I\) got a different selectivity. Which way is right, and why is the other way wrong?" What is your response?

Certain vegetables and fruits contain plant pigments called carotenoids that are metabolized in the body to produce Vitamin A. Lack of Vitamin A causes an estimated 250,000 to 500,000 children worldwide to become blind every year. An approach to reducing blindness and other childhood health problems resulting from this deficiency is to use genetic engineering of rice- -a food staple in developing countries and economically disadvantaged regions of the world \(-\) so that rice becomes a dietary source of Vitamin A. For example, a strain known as Golden Rice has been genetically engineered so that it can produce and store carotenoids such as \(\beta\) -carotene (which helps give carrots and squash their yellow-orange color). One type of Golden Rice contains approximately 30 micrograms of carotenoids (81\% \beta-carotene, 16\% \alpha- carotene, and 3\% \beta-cryptoxanthin) per gram of uncooked rice. A study has reported that when a person eats Golden Rice, their body metabolizes 1 microgram of Vitamin A for every 3.8 micrograms of \beta-carotene they consume. (a) It is recommended that children between 1 and 3 years of age should get 300 micrograms of Vitamin A per day. Considering only the metabolism of \(\beta\) -carotene given above, how many grams of Golden Rice would a child have to eat in order to obtain this much Vitamin A? Does this seem like a reasonable amount of rice to eat in one day, if one cup of cooked rice is approximately 175 g? (b) \(\alpha\) -carotene and \(\beta\) -cryptoxanthin can also be converted into Vitamin \(A\), but when compared to \beta-carotene, it takes twice as much of each of these compounds to produce one unit of Vitamin A. Considering all of the carotenoids in Golden Rice as potential sources of Vitamin A, how many grams of Golden Rice would a three-year-old child have to eat in order to obtain the recommended daily amount of Vitamin A? (c) Some individuals are not convinced that genetically modified foods are safe to grow or to eat. What kinds of risks or uncertainties are cited by these individuals? What kinds of measures are taken by farmers and suppliers of genetically modified seeds to minimize these risks? (d) Some people do not believe that Golden Rice is a practical, viable solution to Vitamin A deficiency around the world. Summarize the major arguments for and against production and distribution of Golden Rice.

Carbon nanotubes (CNT) are among the most versatile building blocks in nanotechnology. These unique pure carbon materials resemble rolled-up sheets of graphite with diameters of several nanometers and lengths up to several micrometers. They are stronger than steel, have higher thermal conductivities than most known materials, and have electrical conductivities like that of copper but with higher currentcarrying capacity. Molecular transistors and biosensors are among their many applications. While most carbon nanotube research has been based on laboratory-scale synthesis, commercial applications involve large industrial-scale processes. In one such process, carbon monoxide saturated with an organo-metallic compound (iron penta-carbonyl) is decomposed at high temperature and pressure to form CNT, amorphous carbon, and CO_. Each "molecule" of CNT contains roughly 3000 carbon atoms. The reactions by which such molecules are formed are: In the process to be analyzed, a fresh feed of CO saturated with \(\mathrm{Fe}(\mathrm{CO})_{5}(\mathrm{v})\) contains \(19.2 \mathrm{wt} \%\) of the latter component. The feed is joined by a recycle stream of pure CO and fed to the reactor, where all of the iron penta-carbonyl decomposes. Based on laboratory data, \(20.0 \%\) of the CO fed to the reactor is converted, and the selectivity of CNT to amorphous carbon production is (9.00 kmol CNT/kmol C). The reactor effluent passes through a complex separation process that yields three product streams: one consists of solid \(\mathrm{CNT}, \mathrm{C},\) and \(\mathrm{Fe} ;\) a second is \(\mathrm{CO}_{2} ;\) and the third is the recycled \(\mathrm{CO}\). You wish to determine the flow rate of the fresh feed (SCM/h), the total CO_ generated in the process ( \(\mathrm{kg} / \mathrm{h}\) ), and the ratio (kmol CO recycled/kmol CO in fresh feed). (a) Take a basis of \(100 \mathrm{kmol}\) fresh feed. Draw and fully label a process flow chart and do degree-offreedom analyses for the overall process, the fresh-feed/recycle mixing point, the reactor, and the separation process. Base the analyses for reactive systems on atomic balances. (b) Write and solve overall balances, and then scale the process to calculate the flow rate (SCM/h) of fresh feed required to produce \(1000 \mathrm{kg} \mathrm{CNT} / \mathrm{h}\) and the mass flow rate of \(\mathrm{CO}_{2}\) that would be produced. (c) In your degree-of-freedom analysis of the reactor, you might have counted separate balances for C (atomic carbon) and O (atomic oxygen). In fact, those two balances are not independent, so one but not both of them should be counted. Revise your analysis if necessary, and then calculate the ratio (kmol CO recycled/kmol CO in fresh feed). (d) Prove that the atomic carbon and oxygen balances on the reactor are not independent equations.

Propane is burned completely with excess oxygen. The product gas contains 24.5 mole \(\% \mathrm{CO}_{2}, 6.10 \%\) CO, \(40.8 \% \mathrm{H}_{2} \mathrm{O},\) and \(28.6 \% \mathrm{O}_{2}\) (a) Calculate the percentage excess \(\mathrm{O}_{2}\) fed to the furnace. (b) A student wrote the stoichiometric equation of the combustion of propane to form \(\mathrm{CO}_{2}\) and as $$2 \mathrm{C}_{3} \mathrm{H}_{8}+\frac{17}{2} \mathrm{O}_{2} \longrightarrow 3 \mathrm{CO}_{2}+3 \mathrm{CO}+8 \mathrm{H}_{2} \mathrm{O}$$ According to this equation, \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) should be in a ratio of \(1 / 1\) in the reaction products, but in the product gas of Part (a) they are in a ratio of \(24.8 / 6.12 .\) Is that result possible? (Hint: Yes.) Explain how.

If the percentage of fuel in a fuel-air mixture falls below a certain value called the lower flammability limit (LFL), which sometimes is referred to as the lower explosion limit (LEL), the mixture cannot be ignited. In addition there is an upper flammability limit (UFL), which also is known as the upper explosion limit (UEL). For example, the LFL of propane in air is 2.3 mole \(\% \mathrm{C}_{3} \mathrm{H}_{8}\) and the UFL is \(9.5 \%^{14}\). If the percentage of propane in a propane-air mixture is greater than \(2.3 \%\) and less than \(9.5 \%,\) the gas mixture can ignite if it is exposed to a flame or spark. A mixture of propane in air containing 4.03 mole \(\% \mathrm{C}_{3} \mathrm{H}_{8}\) (fuel gas) is the feed to a combustion furnace. If there is a problem in the furnace, a stream of pure air (dilution air) is added to the fuel mixture prior to the furnace inlet to make sure that ignition is not possible. (a) Draw and label a flowchart of the fuel gas-dilution air mixing unit, presuming that the gas entering the furnace contains propane at the LFL, and do the degree-of-freedom analysis. (b) If propane flows at a rate of \(150 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{8} / \mathrm{s}\) in the original fuel-air mixture, what is the minimum molar flow rate of the dilution air? (c) How would the actual dilution air feed rate probably compare with the value calculated in Part (b)? (>, \(<,=\) ) Explain.

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