/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Certain vegetables and fruits co... [FREE SOLUTION] | 91Ó°ÊÓ

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Certain vegetables and fruits contain plant pigments called carotenoids that are metabolized in the body to produce Vitamin A. Lack of Vitamin A causes an estimated 250,000 to 500,000 children worldwide to become blind every year. An approach to reducing blindness and other childhood health problems resulting from this deficiency is to use genetic engineering of rice- -a food staple in developing countries and economically disadvantaged regions of the world \(-\) so that rice becomes a dietary source of Vitamin A. For example, a strain known as Golden Rice has been genetically engineered so that it can produce and store carotenoids such as \(\beta\) -carotene (which helps give carrots and squash their yellow-orange color). One type of Golden Rice contains approximately 30 micrograms of carotenoids (81\% \beta-carotene, 16\% \alpha- carotene, and 3\% \beta-cryptoxanthin) per gram of uncooked rice. A study has reported that when a person eats Golden Rice, their body metabolizes 1 microgram of Vitamin A for every 3.8 micrograms of \beta-carotene they consume. (a) It is recommended that children between 1 and 3 years of age should get 300 micrograms of Vitamin A per day. Considering only the metabolism of \(\beta\) -carotene given above, how many grams of Golden Rice would a child have to eat in order to obtain this much Vitamin A? Does this seem like a reasonable amount of rice to eat in one day, if one cup of cooked rice is approximately 175 g? (b) \(\alpha\) -carotene and \(\beta\) -cryptoxanthin can also be converted into Vitamin \(A\), but when compared to \beta-carotene, it takes twice as much of each of these compounds to produce one unit of Vitamin A. Considering all of the carotenoids in Golden Rice as potential sources of Vitamin A, how many grams of Golden Rice would a three-year-old child have to eat in order to obtain the recommended daily amount of Vitamin A? (c) Some individuals are not convinced that genetically modified foods are safe to grow or to eat. What kinds of risks or uncertainties are cited by these individuals? What kinds of measures are taken by farmers and suppliers of genetically modified seeds to minimize these risks? (d) Some people do not believe that Golden Rice is a practical, viable solution to Vitamin A deficiency around the world. Summarize the major arguments for and against production and distribution of Golden Rice.

Short Answer

Expert verified
a) About 47 grams of Golden Rice would need to be consumed to get enough beta-carotene to produce the recommended daily amount of Vitamin A, which seems reasonable given a cup of rice weighs 175 g. When considering all of the carotenoids in Golden Rice, a child would need to eat about 32.43 g of Golden Rice. b) Risks and uncertainties around genetically modified foods can include potential health and environmental effects, and issues around regulation. Measures to minimize these risks can include extensive testing and regulations. c) Opinions on Golden Rice as a solution to Vitamin A deficiency vary, with factors such as cost-effectiveness, distribution challenges, and alternative solutions all playing a part.

Step by step solution

01

Calculate Vitamin A from Beta-Carotene

First find the amount of beta-carotene in each gram of Golden Rice. This can be done since 81% of the carotenoids in Golden Rice are beta-carotene. So multiply 30 micrograms by 0.81 to get 24.3 micrograms of beta-carotene per gram of rice. Then, because the body metabolizes 1 microgram of Vitamin A for every 3.8 micrograms of beta-carotene, divide 24.3 by 3.8 to find the amount of Vitamin A per gram of rice which is about 6.4 micrograms. Then, divide the recommended daily amount of Vitamin A (300 micrograms) by the amount of Vitamin A per gram of rice to find the amount of rice one would need to eat. The result is approximately 47 grams of rice.
02

Include Alpha-carotene and Beta-Cryptoxanthin in the Calculation

For the second part of the problem, note that 16% of the carotenoids are alpha-carotene (30 * 0.16 = 4.8 micrograms) and 3% are beta-cryptoxanthin (30 * 0.03 = 0.9 micrograms). Given that it takes twice as much of these compounds to produce one unit of Vitamin A, divide these amounts by 2 to get the Vitamin A contribution from these two sources: 2.4 micrograms from alpha-carotene and 0.45 micrograms from beta-cryptoxanthin. Summing up these three sources, we get approximately 9.25 micrograms of Vitamin A per gram of Golden Rice. Dividing the required daily intake (300 micrograms) by this sum gives the total amount of Golden Rice the child would need to eat, which is approximately 32.43 grams.
03

Discuss Risks of Genetically Modified Foods

The answer to this part of the question will depend on background research. Common risks cited by individuals regarding genetically modified foods might include potential health effects, effects on the environment, and issues around regulation and labeling.
04

Evaluate the Golden Rice Solution

Discussing the effectiveness of Golden Rice as a solution to Vitamin A deficiency needs to consider a variety of factors. This might include cost-effectiveness, distribution challenges, cultural eating practices, and alternative solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carotenoids Metabolism
Carotenoids are natural pigments found in plants that not only give fruits and vegetables their vibrant colors but also play a crucial role in human health. When ingested, some carotenoids, such as \beta-carotene, \(\alpha\)-carotene, and \(\beta\)-cryptoxanthin are metabolized into vitamin A. This process is essential because vitamin A is a vital nutrient responsible for maintaining vision, skin health, and supporting the immune system.

When we consume foods like Golden Rice, our body converts these carotenoids into vitamin A. To understand how much vitamin A we get from Golden Rice, simple calculations are necessary. For instance, from \(\beta\)-carotene, 3.8 micrograms yields 1 microgram of vitamin A, which is essential for dietary planning, especially in populations susceptible to vitamin A deficiency. By integrating carotenoids into staple foods, we can effectively combat this deficiency on a larger scale.
Genetically Modified Foods
Genetically modified (GM) foods are created through a process where the DNA of an organism is altered to express desired traits. For example, Golden Rice is genetically engineered to produce carotenoids, aiming to alleviate vitamin A deficiency. There are many potential benefits of GM foods, including improved nutrition, increased yields, and resistance to pests and diseases.

However, there also arise concerns regarding the safety of consuming GM foods and their impact on the environment. Critics worry about the possibility of allergenicity, transfer of antibiotic resistance markers, and unintended effects on wildlife. Despite stringent regulation and testing designed to address these risks, the debate over GM food safety continues. Measures such as controlled field trials, monitoring for environmental impacts, and post-approval health surveillance are undertaken to minimize risks associated with GM crops.
Biofortification in Rice
Biofortification is the process of increasing the nutritional value of crops through conventional breeding or genetic engineering. It targets staple crops in areas where dietary deficiencies are common. Golden Rice is one of the most well-known biofortified foods, engineered to express genes that enable the production of carotenoids in the edible parts of rice.

The development of biofortified crops like Golden Rice is a strategic effort to address micronutrient malnutrition, also known as 'hidden hunger'. Biofortification offers a sustainable and cost-effective method of delivering essential nutrients, as it does not require extensive changes to existing agricultural practices or dietary habits. However, it's crucial to consider factors like bioavailability, the stability of the added nutrients, and acceptance by local communities to ensure the success of biofortified foods like Golden Rice in improving public health.

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Most popular questions from this chapter

The indicator-dilution method is a technique used to determine flow rates of fluids in channels for which devices like rotameters and orifice meters cannot be used (e.g., rivers, blood vessels, and largediameter pipelines). A stream of an easily measured substance (the tracer) is injected into the channel at a known rate, and the tracer concentration is measured at a point far enough downstream of the injection point for the tracer to be completely mixed with the flowing fluid. The larger the flow rate of the fluid, the lower the tracer concentration at the measurement point. A gas stream that contains 1.50 mole \(\% \mathrm{CO}_{2}\) flows through a pipeline. Twenty (20.0) kilograms of \(\mathrm{CO}_{2}\) per minute is injected into the line. A sample of the gas is drawn from a point in the line 150 meters (a) Estimate the gas flow rate (kmol/min) upstream of the injection point. (b) Eighteen seconds elapse from the instant the additional \(\mathrm{CO}_{2}\) is first injected to the time the \(\mathrm{CO}_{2}\) concentration at the measurement point begins to rise. Assuming that the tracer travels at the average velocity of the gas in the pipeline (i.e., neglecting diffusion of \(\mathrm{CO}_{2}\) ), estimate the average velocity (m/s). If the molar gas density is \(0.123 \mathrm{kmol} / \mathrm{m}^{3}\), what is the pipe diameter?

The respiratory process involves hemoglobin (Hgb), an iron-containing compound found in red bloodcells. In the process, carbon dioxide diffuses from tissue cells as molecular \(\mathrm{CO}_{2}\), while \(\mathrm{O}_{2}\) simultaneously enters the tissue cells. A significant fraction of the \(\mathrm{CO}_{2}\) leaving the tissue cells enters red blood cells and reacts with hemoglobin; the \(\mathrm{CO}_{2}\) that does not enter the red blood cells ( \((\mathrm{D}\) in the figure below) remains dissolved in the blood and is transported to the lungs. Some of the \(\mathrm{CO}_{2}\) entering the red blood cells reacts with hemoglobin to form a compound (Hgb. \(\mathrm{CO}_{2} ;(\) 2) in the figure). When the red blood cells reach the lungs, the Hgb.CO_ dissociates, releasing free CO_ Meanwhile, the CO_ that enters the red blood cells but does not react with hemoglobin combines with water to form carbonic acid, \(\mathrm{H}_{2} \mathrm{CO}_{3},\) which then dissociates into hydrogen ions and bicarbonate ions ( (3) in the figure). The bicarbonate ions diffuse out of the cells ( (4) in the figure), and the ions are transported to the lungs via the bloodstream. For adult humans, every deciliter of blood transports a total of \(1.6 \times 10^{-4}\) mol of carbon dioxide in its various forms (dissolved \(\mathrm{CO}_{2}, \mathrm{Hgb} \cdot \mathrm{CO}_{2},\) and bicarbonate ions) from tissues to the lungs under normal, resting conditions. Of the total \(\mathrm{CO}_{2}, 1.1 \times 10^{-4}\) mol are transported as bicarbonate ions. In a typical resting adult human, the heart pumps approximately 5 liters of blood per minute. You have been asked to determine how many moles of \(\mathrm{CO}_{2}\) are dissolved in blood and how many moles of \(\mathrm{Hgb} \cdot \mathrm{CO}_{2}\) are transported to the lungs during an hour's worth of breathing. (a) Draw and fully label a flowchart and do a degree-of-freedom analysis. Write the chemical reactions that occur, and generate, but do not solve, a set of independent equations relating the unknown variables on the flowchart. (b) If you have enough information to obtain a unique numerical solution, do so. If you do not have enough information, identify a specific piece/pieces of information that (if known) would allow you to solve the problem, and show that you could solve the problem if that information were known. (c) When someone loses a great deal of blood due to an injury, they "go into shock": their total blood volume is low, and carbon dioxide is not efficiently transported away from tissues. The carbon dioxide reacts with water in the tissue cells to produce very high concentrations of carbonic acid, some of which can dissociate (as shown in this problem) to produce high levels of hydrogen ions. What is the likely effect of this occurrence on the blood pH near the tissue and the tissue cells? How is this likely to affect the injured person?

The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product stream is analyzed and found to contain 51.7 mole \(\% \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\) and 17.3\% HBr. The feed to the reactor contains only ethylene and hydrogen bromide. Calculate the fractional conversion of the limiting reactant and the percentage by which the other reactant is in excess. If the molar flow rate of the feed stream is \(165 \mathrm{mol} / \mathrm{s}\), what is the extent of reaction?

Draw and label the given streams and derive expressions for the indicated quantities in terms of labeled variables. The solution of Part (a) is given as an illustration. (a) A continuous stream contains 40.0 mole\% benzene and the balance toluene. Write expressions for the molar and mass flow rates of benzene, \(\dot{n}_{\mathrm{B}}\left(\operatorname{mol} \mathrm{C}_{6} \mathrm{H}_{6} / \mathrm{s}\right)\) and \(\dot{m}_{\mathrm{B}}\left(\mathrm{kg} \mathrm{C}_{6} \mathrm{H}_{6} / \mathrm{s}\right),\) in terms of the total molar flow rate of the stream, \(\dot{n}(\mathrm{mol} / \mathrm{s})\) (b) The feed to a batch process contains equimolar quantities of nitrogen and methane. Write an expression for the kilograms of nitrogen in terms of the total moles \(n(\) mol) of this mixture. (c) A stream containing ethane, propane, and butane has a mass flow rate of \(100.0 \mathrm{g} / \mathrm{s}\). Write an expression for the molar flow rate of ethane, \(\dot{n}_{\mathrm{E}}\left(\text { Ib-mole } \mathrm{C}_{2} \mathrm{H}_{6} / \mathrm{h}\right)\), in terms of the mass fraction of this species, \(x_{\mathrm{E}}\). (d) A continuous stream of humid air contains water vapor and dry air, the latter containing approximately 21 mole \(\% \mathrm{O}_{2}\) and \(79 \% \mathrm{N}_{2}\). Write expressions for the molar flow rate of \(\mathrm{O}_{2}\) and for the mole fractions of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{O}_{2}\) in the gas in terms of \(\dot{n}_{1}\left(\mathrm{lb}-\mathrm{mole} \mathrm{H}_{2} \mathrm{O} / \mathrm{s}\right)\) and \(\dot{n}_{2}(\text { lb- mole dry air/s })\) (e) The product from a batch reactor contains \(\mathrm{NO}, \mathrm{NO}_{2},\) and \(\mathrm{N}_{2} \mathrm{O}_{4} .\) The mole fraction of \(\mathrm{NO}\) is 0.400. Write an expression for the gram-moles of \(\mathrm{N}_{2} \mathrm{O}_{4}\) in terms of \(n(\mathrm{mol}\) mixture) and \(y_{\mathrm{NO}_{2}}\left(\operatorname{mol} \mathrm{NO}_{2} / \mathrm{mol}\right)\)

Effluents from metal-finishing plants have the potential of discharging undesirable quantities of metals, such as cadmium, nickel, lead, manganese, and chromium, in forms that are detrimental to water and air quality. A local metal-finishing plant has identified a wastewater stream that contains 5.15 wt\% chromium (Cr) and devised the following approach to lowering risk and recovering the valuable metal. The wastewater stream is fed to a treatment unit that removes \(95 \%\) of the chromium in the feed and recycles it to the plant. The residual liquid stream leaving the treatment unit is sent to a waste lagoon. The treatment unit has a maximum capacity of 4500 kg wastewater/h. If wastewater leaves the finishing plant at a rate higher than the capacity of the treatment unit, the excess (anything above \(4500 \mathrm{kg} / \mathrm{h}\) ) bypasses the unit and combines with the residual liquid leaving the unit, and the combined stream goes to the waste lagoon. (a) Without assuming a basis of calculation, draw and label a flowchart of the process. (b) Wastewater leaves the finishing plant at a rate \(\dot{m}_{1}=6000 \mathrm{kg} / \mathrm{h}\). Calculate the flow rate of liquid to the waste lagoon, \(\dot{m}_{6}(\mathrm{kg} / \mathrm{h}),\) and the mass fraction of \(\mathrm{Cr}\) in this liquid, \(x_{6}(\mathrm{kg} \mathrm{Cr} / \mathrm{kg})\) (c) Calculate the flow rate of liquid to the waste lagoon and the mass fraction of Crin this liquid for \(\dot{m}_{1}\) varying from \(1000 \mathrm{kg} / \mathrm{h}\) to \(10,000 \mathrm{kg} / \mathrm{h}\) in \(1000 \mathrm{kg} / \mathrm{h}\) increments. Generate a plot of \(x_{6}\) versus \(\dot{m}_{1}\). (Suggestion: Use a spreadsheet for these calculations.) (d) The company has hired you as a consultant to help them determine whether or not to add capacity to the treatment unit to increase the recovery of chromium. What would you need to know to make this determination? (e) What concerns might need to be addressed regarding the waste lagoon?

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