/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A liquid mixture contains \(60.0... [FREE SOLUTION] | 91Ó°ÊÓ

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A liquid mixture contains \(60.0 \mathrm{wt} \%\) ethanol \((\mathrm{E}), 5.0 \mathrm{wt} \%\) of a dissolved solute \((\mathrm{S}),\) and the balance water. A stream of this mixture is fed to a continuous distillation column operating at steady state. Product streams emerge at the top and bottom of the column. The column design calls for the product streams to have equal mass flow rates and for the top stream to contain 90.0 wt\% ethanol and no S. (a) Assume a basis of calculation, draw and fully label a process flowchart, do the degree-of-freedom analysis, and verify that all unknown stream flows and compositions can be calculated. (Don't do any calculations yet.) (b) Calculate (i) the mass fraction of \(S\) in the bottom stream and (ii) the fraction of the ethanol in the feed that leaves in the bottom product stream (i.e., \(\mathrm{kg} \mathrm{E}\) in bottom stream/kg \(\mathrm{E}\) in feed) if the process operates as designed. (c) An analyzer is available to determine the composition of ethanol-water mixtures. The calibration curve for the analyzer is a straight line on a plot on logarithmic axes of mass fraction of ethanol, \(x\) (kg E/kg mixture), versus analyzer reading, \(R\). The line passes through the points \((R=15, x=\) 0.100) and \((R=38, x=0.400)\). Derive an expression for \(x\) as a function of \(R(x=\cdots\) ) based on the calibration, and use it to determine the value of \(R\) that should be obtained if the top product stream from the distillation column is analyzed. (d) Suppose a sample of the top stream is taken and analyzed and the reading obtained is not the one calculated in Part (c). Assume that the calculation in Part (c) is correct and that the plant operator followed the correct procedure in doing the analysis. Give five significantly different possible causes for the deviation between \(R_{\text {measured and }} R_{\text {prediced }}\), including several assumptions made when writing the balances of Part (c). For each one, suggest something that the operator could do to check whether it is in fact the problem.

Short Answer

Expert verified
The mass fraction of S in the bottom stream is 5%, and the fraction of the ethanol in the feed that leaves in the bottom product stream is 0.5. The value of R for the top stream, based on the derived equation, would depend on the relationship derived from the calibration curve points. Possible causes for deviation in actual and predicted readings could stem from errors in the calibration curve, variations in the distillation process, inaccuracies in sample handling, and possible calculation errors.

Step by step solution

01

Calculate mass fraction of S in the bottom stream from distillation column

From the problem statement, the column is designed such that the product streams have equal mass flow rates. The top stream contains 90% of ethanol E and no solute S. Therefore, since input equals output in a steady-state process, the bottom stream should also contain equal masses of S and water compared to the feed stream. For a mixture containing 60% E, 5% S and 35% water, the bottom stream will be 5% S and 95% water since no S goes to the top stream.
02

Calculate fraction of ethanol in feed that leaves in the bottom stream

Although the distillation column operates such that the two output streams are of equal mass, evenly split between the two outlet streams since equal mass flow rates was a design constraint. Then, half the ethanol in the feed will be in top steam and the other half in the bottom stream. Hence, the mass fraction of the ethanol that leaves the bottom stream compared to the feed will be 50%.
03

Derive an expression for x as a function of R

Using the two given points, we can form two simultaneous equations in loge form. Let the equation of the straight line on the calibration graph be y = mx + c, where y = log(R), x = log(X), m is the slope and c is the intercept. Substituting the two given points into this equation, we can solve for m and c. With those values, we can then rewrite the equation in a suitable form to find x = f(R), where 'f' designates a function which involves exponential because of the logarithms used.
04

Use the formula derived in Step 3 to determine R for the top-stream

Having the x as a function of R, we can calculate the value of R for the distillate from the column. Given that the top stream is 90 wt% ethanol, therefore, x in this analysis is 0.9. Substituting x = 0.9 into the equation obtained in Step 3, we can find the corresponding R value which is the predicted optical density.
05

Analyze possible causes of deviation in measured and predicted R

Possible causes for the difference between the measured and predicted R could include: inaccuracies in the calibration curve, the presence of trace components in the sample which might interfere with the analyzer response, variability in the distillation process leading to inconsistencies in mixture composition, errors in sample collection or handling, and inaccuracies in your calculations. In order to check these assumptions, the operator could discard the first few outputs from the analyzer to remove possible contaminants, rerun the calibration curve, recheck the calculations, or collect and handle samples more carefully according to the standard procedure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Balance Calculations
Understanding the concept of mass balance calculations is crucial when analyzing a distillation column process. These calculations are based on the principle of conservation of mass, which states that mass cannot be created or destroyed in a process. In a distillation column, this means that the mass of each component entering the column must equal the mass exiting, either in the distillate (top stream) or the bottoms (bottom stream).

For instance, if a feed contains a certain percentage of ethanol (E), water, and a solute (S), we can use mass balance to calculate the composition of the product streams. Assuming a steady state and no accumulation within the column, the mass fraction of the solute in the bottom stream would be equal to that in the feed if the solute is non-volatile and does not distill with ethanol. Similarly, understanding the distribution of ethanol between the top and bottom streams hinges on the mass balance - with equal mass flow rates for both streams, half of the ethanol in the feed will be found in each product stream.

When there are deviations in the process or unexpected results, mass balance calculations can be revisited to identify potential errors or changes in the process conditions.
Steady-State Process
A steady-state process is a condition where the variables (mass flow, temperature, composition, etc.) that define the operation of a process do not change with time. In the context of a distillation column, this means that the feed rate, composition, and mass flow rates of the top and bottom streams remain constant with time.

This assumption simplifies mass balance calculations because it eliminates the need to consider changes over time. In practice, achieving and maintaining steady-state requires precise control of the process conditions and is crucial for consistent product quality. If the steady state is not maintained, variables such as the mass fraction of a component in the output streams can fluctuate, leading to deviations from the expected performance of the column.
Calibration Curve Analysis
Calibration curve analysis is an essential tool in analytical chemistry, used to understand the relationship between an instrument's reading and the actual concentration of a substance in a sample. A calibration curve generally plots the instrument response against known concentrations of a substance.

In the exercise, the calibration curve is used to correlate the analyzer reading (R) to the mass fraction of ethanol (x). By knowing two points, a line can be drawn on a log-log plot, and an equation can be derived linking R and x. This equation allows for the prediction of unknown concentrations from their respective analyzer readings. When the measured R deviates from the predicted R, the calibration curve itself may need to be reassessed, or it might indicate a problem with the sample or the analyzer. Regular calibration and verification using standard solutions are essential for maintaining accuracy in such analytical instruments.
Process Flowchart
A process flowchart provides a visual representation of the steps, materials, and streams involved in a process. For the distillation column exercise, a well-labeled flowchart would illustrate the feed entering the column, the two product streams (top and bottom), and the components present in each stream.

Creating a flowchart is a key step in process analysis, as it helps in visually organizing the information and identifying what is known and what needs to be calculated. It serves as a reference point for mass balance calculations and for doing a degree-of-freedom analysis. Ensuring that each stream is labeled with the correct mass flow rate and composition, as mentioned in the exercise's instructions, supports accuracy in calculations and process design.
Degree-of-Freedom Analysis
Degree-of-freedom analysis is a method used to determine whether a system of equations is solvable as it relates to the number of unknowns versus the number of independent equations. In the exercise, before performing any calculations, it's crucial to establish whether there are enough equations to solve for all unknowns associated with the distillation process.

For the provided exercise, the variables include stream flow rates, compositions, and the mass fractions of components within each stream. By setting up a degree-of-freedom analysis, we identify if the system is under-specified, over-specified, or just right. If the degrees of freedom are zero, it indicates that we have exactly as many independent equations as we have unknowns, and the system can be solved with a high degree of confidence.

Considering the degree-of-freedom at an early stage in the problem-solving process helps in understanding the solvability of the system, and it can be a great indicator of whether additional data or assumptions are needed to proceed with the calculations.

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Most popular questions from this chapter

The popularity of orange juice, especially as a breakfast drink, makes this beverage an important factor in the economy of orange-growing regions. Most marketed juice is concentrated and frozen and then reconstituted before consumption, and some is "not-from-concentrate." Although concentrated juices are less popular in the United States than they were at one time, they still have a major segment of the market for orange juice. The approaches to concentrating orange juice include evaporation, freeze concentration, and reverse osmosis. Here we examine the evaporation process by focusing only on two constituents in the juice: solids and water. Fresh orange juice contains approximately 10 wt\% solids (sugar, citric acid, and other ingredients) and frozen concentrate contains approximately 42 wt\% solids. The frozen concentrate is obtained by evaporating water from the fresh juice to produce a mixture that is approximately 65 wt\% solids. However, so that the flavor of the concentrate will closely approximate that of fresh juice, the concentrate from the evaporator is blended with fresh orange juice (and other additives) to produce a final concentrate that is approximately 42 wt\% solids. (a) Draw and label a flowchart of this process, neglecting the vaporization of everything in the juice but water. First prove that the subsystem containing the point where the bypass stream splits off from the evaporator feed has one degree of freedom. (If you think it has zero degrees, try determining the unknown variables associated with this system.) Then perform the degree- offreedom analysis for the overall system, the evaporator, and the bypass- evaporator product mixing point, and write in order the equations you would solve to determine all unknown stream variables. In each equation, circle the variable for which you would solve, but don't do any calculations. (b) Calculate the amount of product (42\% concentrate) produced per 100 kg fresh juice fed to the process and the fraction of the feed that bypasses the evaporator. (c) Most of the volatile ingredients that provide the taste of the concentrate are contained in the fresh juice that bypasses the evaporator. You could get more of these ingredients in the final product by evaporating to (say) 90\% solids instead of 65\%; you could then bypass a greater fraction of the fresh juice and thereby obtain an even better tasting product. Suggest possible drawbacks to this proposal.

A fuel oil is analyzed and found to contain 85.0 wt\% carbon, \(12.0 \%\) elemental hydrogen (H), \(1.7 \%\) sulfur, and the remainder noncombustible matter. The oil is burned with \(20.0 \%\) excess air, based on complete combustion of the carbon to \(\mathrm{CO}_{2}\), the hydrogen to \(\mathrm{H}_{2} \mathrm{O}\), and the sulfur to \(\mathrm{SO}_{2}\). The oil is burned completely, but \(8 \%\) of the carbon forms CO. Calculate the molar composition of the stack gas.

Oxygen consumed by a living organism in aerobic reactions is used in adding mass to the organism and/or the production of chemicals and carbon dioxide. since we may not know the molecular compositions of all species in such a reaction, it is common to define the ratio of moles of \(\mathrm{CO}_{2}\) produced per mole of \(\mathrm{O}_{2}\) consumed as the respiratory quotient, \(R Q,\) where $$R Q=\frac{n_{\mathrm{CO}_{2}}}{n_{\mathrm{O}_{2}}}\left(\text { or } \frac{\dot{n}_{\mathrm{CO}_{2}}}{\dot{n}_{\mathrm{O}_{2}}}\right)$$ since it generally is impossible to predict values of \(R Q\), they must be determined from operating data. Mammalian cells are used in a bioreactor to convert glucose to glutamic acid by the reaction $$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+a \mathrm{NH}_{3}+b \mathrm{O}_{2} \rightarrow p \mathrm{C}_{5} \mathrm{H}_{9} \mathrm{NO}_{4}+q \mathrm{CO}_{2}+r \mathrm{H}_{2} \mathrm{O}$$ The feed to the bioreactor comprises \(1.00 \times 10^{2} \mathrm{mol} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} / \mathrm{day}, 1.20 \times 10^{2} \mathrm{mol} \mathrm{NH}_{3} / \mathrm{day},\) and \(1.10 \times\) \(10^{2}\) mol \(\mathrm{O}_{2} /\) day. Data on the system show that \(R Q=0.45 \mathrm{mol} \mathrm{CO}_{2}\) produced/mol \(\mathrm{O}_{2}\) consumed. (a) Determine the five stoichiometric coefficients and the limiting reactant. (b) Assuming that the limiting reactant is consumed completely, calculate the molar and mass flow rates of all species leaving the reactor and the fractional conversions of the non-limiting reactants.

A liquid-phase chemical reaction \(\mathrm{A} \rightarrow \mathrm{B}\) takes place in a well-stirred tank. The concentration of \(\mathrm{A}\) in the feed is \(C_{\mathrm{A} 0}\left(\operatorname{mol} / \mathrm{m}^{3}\right),\) and that in the tank and outlet stream is \(C_{\mathrm{A}}\left(\mathrm{mol} / \mathrm{m}^{3}\right) .\) Neither concentration varies with time. The volume of the tank contents is \(V\left(\mathrm{m}^{3}\right)\) and the volumetric flow rate of the inlet and outlet streams is \(\dot{V}\left(\mathrm{m}^{3} / \mathrm{s}\right)\). The reaction rate (the rate at which \(\mathrm{A}\) is consumed by reaction in the tank) is given by the expression $$r(\text { mol } A \text { consumed } / \mathrm{s})=k V C_{\mathrm{A}}$$ (a) Is this process continuous, batch, or semibatch? Is it transient or steady-state? (b) What would you expect the reactant concentration \(C_{\mathrm{A}}\) to equal if \(k=0\) (no reaction)? What should it approach if \(k \rightarrow \infty\) (infinitely rapid reaction)? (c) Write a differential balance on \(A,\) stating which terms in the general balance equation (accumulation = input + generation - output - consumption) you discarded and why you discarded them. Use the balance to derive the following relation between the inlet and outlet reactant concentrations: $$C_{\mathrm{A}}=\frac{C_{\mathrm{A} 0}}{1+k V / \dot{V}}$$ Verify that this relation predicts the results in Part (b).

Fermentation of sugars obtained from hydrolysis of starch or cellulosic biomass is an alternative to using petrochemicals as the feedstock in production of ethanol. One of the many commercial processes to do this \(^{16}\) uses an enzyme to hydrolyze starch in corn to maltose (a disaccharide consisting of two glucose units) and oligomers consisting of several glucose units. A yeast culture then converts the maltose to ethyl alcohol and carbon dioxide: $$\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+\mathrm{H}_{2} \mathrm{O}(+\text { yeast }) \rightarrow 4 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+4 \mathrm{CO}_{2}\left(+\text { yeast }+\mathrm{H}_{2} \mathrm{O}\right)$$ As the yeast grows, \(0.0794 \mathrm{kg}\) of yeast is produced for every \(\mathrm{kg}\) ethyl alcohol formed, and \(0.291 \mathrm{kg}\) water is produced for every kg of yeast formed. For use as a fuel, the product from such a process must be around 99.5 wt\% ethyl alcohol. Corn fed to the process is 72.0 wt\% starch on a moisture-free basis and contains 15.5 wt\% moisture. It is estimated that 101.2 bushels of corn can be harvested from an acre of com, that each bushel is equivalent to \(25.4 \mathrm{lb}_{\mathrm{m}}\) of corn, and that \(6.7 \mathrm{kg}\) of ethanol can be obtained from a bushel of corn. What acreage of farmland is required to produce 100,000 kg of ethanol product? What factors (economic and environmental) must be considered in comparing production of ethanol by this route with other routes involving petrochemical feedstocks?

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