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Two aqueous sulfuric acid solutions containing \(20.0 \mathrm{wt} \% \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{SG}=1.139)\) and \(60.0 \mathrm{wt} \% \mathrm{H}_{2} \mathrm{SO}_{4}\) (SG = 1.498) are mixed to form a 4.00 molar solution (SG = 1.213). (a) Calculate the mass fraction of sulfuric acid in the product solution. (b) Taking \(100 \mathrm{kg}\) of the \(20 \%\) feed solution as a basis, draw and label a flowchart of this process, labeling both masses and volumes, and do the degree-of-freedom analysis. Calculate the feed ratio (liters 20\% solution/liter 60\% solution). (c) What feed rate of the \(60 \%\) solution (L/h) would be required to produce \(1250 \mathrm{kg} / \mathrm{h}\) of the product?

Short Answer

Expert verified
a) The mass fraction of sulfuric acid in the product solution is 0.323.\nb) The feed ratio (liters 20% solution/liter 60% solution) is approximately 0.95.\nc) The feed rate of the 60% solution needed to produce 1250 kg/h of the product is approximately 834 L/h.

Step by step solution

01

Calculating Mass Fraction of Sulfuric Acid in the Product

The molar solution can be calculated using the formula: Mass Fraction = (4 mol/L * 98.08 g/mol) / (1.213 g/mL * 1000 mL/L), which yields a Mass Fraction of 0.323.
02

Drawing and Labelling the Flowchart for the Mixing Process

To make the flowchart, mark two inputs at the top (20% feed solution and 60% feed solution), which converge to form one output at the bottom (product solution). For the 20% feed solution, mark 100 kg for mass, for the volume it will be (100 kg / 1.139 g/mL) * 1000 mL/L. For the 60% feed solution and product solution, we will need to calculate those values.
03

Degree-of-Freedom Analysis and Feed Ratio Calculation

First, recall that Degree-of-Freedom (DoF) is given by number of variables - number of independent equations. Here, the unknown variables are the mass and volume of the 60% feed solution and the mass and volume of the product. We have two balances (mass and sulfuric acid), so the DoF equals 4 - 2 = 2. Then, we can perform sulfuric acid balance: 0.2 * 100 kg + 0.60 * m2 = 0.323 * m3. Since m3 = 100 kg + m2, we can solve for m2 which gives us approximately 75.342 kg. Now, we can compute the volume of the 60% solution with (75.342 kg / 1.498 g/mL) * 1000 mL/L. The feed ratio will then be the volume of the 20% solution divided by volume of the 60% solution.
04

Calculating the Feed Rate of the 60% Solution

Knowing that mass flow rate is equal to volume flow rate times density, we can set this up as follows: mass flow rate of product = volume flow rate of 60% solution * density of 60% solution. Solving for the volume flow rate, we get volume flow rate of 60% solution = 1250 kg/h / (1.498 g/mL * 1000 mL/L).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Fraction Calculation
Understanding the mass fraction of a component within a solution is crucial when dealing with chemical mixtures, especially in creating solutions of a desired concentration. The mass fraction, which is a ratio of the mass of solute to the total mass of the solution, can be calculated using the formula:

\[\begin{equation} \text{Mass Fraction} = \frac{\text{Moles of Solute} \times \text{Molecular Weight of Solute}}{\text{Density of Solution} \times \text{Total Volume of Solution}} \end{equation}\]

In the sulfuric acid example, we calculate the mass fraction using the molarity (moles per liter), the molecular weight of sulfuric acid, and the density of the resulting mixture. By substituting these values into the formula, we find the mass fraction of sulfuric acid in the product solution. Understanding this concept is fundamental for students in chemical engineering to design and evaluate chemical processes efficiently.
Chemical Process Flowchart
A chemical process flowchart provides a visual outline of the steps, equipment, and inputs/outputs involved in a chemical process. It is a valuable tool for planning and analyzing chemical operations, helping to visualize and communicate the process. For the sulfuric acid solution mixing, creating a flowchart requires marking the starting materials and their conditions, processes they undergo, and the final products. This includes specific qualitative and quantitative data like concentration, mass, and volume. Students should remember to incorporate the necessary units and ensure clarity in the flow and transformations occurring within the process.
Degree-of-Freedom Analysis
Degree-of-freedom analysis is an essential step in process design and troubleshooting. It helps to determine if a system of equations describing a process is solvable with the available data. The calculation involves counting the unknown variables and independent equations. For a system to be solvable, the number of equations must be equal to the number of unknowns. Any deviation may indicate insufficient or redundant data. In the sulfuric acid mixing example, we count variables such as the mass and volume of the feed solutions and product, and we subtract the number of independent balances that can be made (e.g., mass and sulfuric acid balance). Assessing the degree-of-freedom helps in identifying whether additional information is needed or if the current system is over-defined.
Feed Ratio
Feed ratio is a concept used to adjust the relative amounts of different reactants entering a process to achieve a desired product composition. In terms of the sulfuric acid mixture, calculating the feed ratio involves determining the volumes of the two solutions being mixed to form the final product. Once we know the volume of each feed solution, we can establish the ratio of the 20% solution to the 60% solution. This is vital for process control in the industry, ensuring that the mixing leads to an end product with the specified properties, such as concentration and volume.
Chemical Engineering Principles
The core principles of chemical engineering revolve around converting raw materials into valuable products through chemical, physical, and biological processes. This requires a deep understanding of various concepts such as reaction kinetics, thermodynamics, mass and heat transfer, and process design. Applying these principles, chemical engineers create processes that are safe, economical, and environmentally friendly. The sulfuric acid mixing problem encapsulates these principles as it involves calculations for mass and volume, understanding solution properties, and the design of process flows – illustrating how diverse knowledge areas come together to solve practical engineering challenges.

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Most popular questions from this chapter

An evaporation-crystallization process of the type described in Example \(4.5-2\) is used to obtain solid potassium sulfate from an aqueous solution of this salt. The fresh feed to the process contains 19.6 wt\% \(\mathrm{K}_{2} \mathrm{SO}_{4}\). The wet filter cake consists of solid \(\mathrm{K}_{2} \mathrm{SO}_{4}\) crystals and a \(40.0 \mathrm{wt} \% \mathrm{K}_{2} \mathrm{SO}_{4}\) solution, in a ratio \(10 \mathrm{kg}\) crystals/kg solution. The filtrate, also a \(40.0 \%\) solution, is recycled to join the fresh feed. Of the water fed to the evaporator, 45.0\% is evaporated. The evaporator has a maximum capacity of 175 kg water evaporated/s. (a) Assume the process is operating at maximum capacity. Draw and label a flowchart and do the degree-of-freedom analysis for the overall system, the recycle-fresh feed mixing point, the evaporator, and the crystallizer. Then write in an efficient order (minimizing simultaneous equations) the equations you would solve to determine all unknown stream variables. In each equation, circle the variable for which you would solve, but don't do the calculations. (b) Calculate the maximum production rate of solid \(\mathrm{K}_{2} \mathrm{SO}_{4}\), the rate at which fresh feed must be supplied to achieve this production rate, and the ratio kg recycle/kg fresh feed. (c) Calculate the composition and feed rate of the stream entering the crystallizer if the process is scaled to 75\% of its maximum capacity. (d) The wet filter cake is subjected to another operation after leaving the filter. Suggest what it might be. Also, list what you think the principal operating costs for this process might be. (e) Use an equation-solving computer program to solve the equations derived in Part (a). Verify that you get the same solutions determined in Part (b).

Methanol is formed from carbon monoxide and hydrogen in the gas-phase reaction The mole fractions of the reactive species at equilibrium satisfy the relation where \(P\) is the total pressure (atm), \(K_{c}\) the reaction equilibrium constant (atm \(^{-2}\) ), and \(T\) the temperature (K). The equilibrium constant \(K_{c}\) equals 10.5 at 373 K, and \(2.316 \times 10^{-4}\) at \(573 \mathrm{K}\). A semilog plot of \(K_{\mathrm{c}}\) (logarithmic scale) versus 1/ \(T\) (rectangular scale) is approximately linear between \(T=300 \mathrm{K}\) and \(T=600 \mathrm{K}\) (a) Derive a formula for \(K_{\mathrm{c}}(T),\) and use it to show that \(K_{\mathrm{e}}(450 \mathrm{K})=0.0548 \mathrm{atm}^{-2}\) (b) Write expressions for \(n_{A}, n_{B},\) and \(n_{C}\) (gram-moles of each species), and then \(y_{A}, y_{B},\) and \(y_{C},\) in terms of \(n_{\mathrm{A} 0}, n_{\mathrm{B} 0}, n_{\mathrm{C} 0},\) and \(\xi,\) the extent of reaction. Then derive an equation involving only \(n_{\mathrm{A} 0}, n_{\mathrm{B} 0}, n_{\mathrm{C} 0}, P, T,\) and \(\xi_{e},\) where \(\xi_{e}\) is the extent of reaction at equilibrium. (c) Suppose you begin with equimolar quantities of CO and \(\mathrm{H}_{2}\) and no \(\mathrm{CH}_{3} \mathrm{OH}\), and the reaction proceeds to equilibrium at 423 K and 2.00 atm. Calculate the molar composition of the product ( \(y_{\mathrm{A}}\), \(\left.y_{\mathrm{B}}, \text { and } y_{\mathrm{C}}\right)\) and the fractional conversion of \(\mathrm{CO}\) (d) The conversion of CO and \(\mathrm{H}_{2}\) can be enhanced by removing methanol from the reactor while leaving unreacted CO and \(\mathrm{H}_{2}\) in the vessel. Review the equations you derived in solving Part (c) and determine any physical constraints on \(\xi_{c}\) associated with \(n_{\mathrm{A} 0}=n_{\mathrm{B} 0}=1\) mol. Now suppose that 90\% of the methanol is removed from the reactor as it is produced; in other words, only 10\% of the methanol formed remains in the reactor. Estimate the fractional conversion of CO and the total gram moles of methanol produced in the modified operation. (e) Repeat Part (d), but now assume that \(n_{\mathrm{B} 0}=2\) mol. Explain the significant increase in fractional conversion of CO. (f) Write a set of equations for \(y_{\mathrm{A}}, y_{\mathrm{B}}, y_{\mathrm{C}},\) and \(f_{\mathrm{A}}\) (the fractional conversion of \(\mathrm{CO}\) ) in terms of \(y_{\mathrm{A} 0}, y_{\mathrm{B} 0}, T,\) and \(P(\) the reactor temperature and pressure at equilibrium). Enter the equations in an equation-solving program. Check the program by running it for the conditions of Part (c), then use it to determine the effects on \(f_{\mathrm{A}}\) (increase, decrease, or no effect) of separately increasing, (i) the fraction of \(\mathrm{CH}_{3} \mathrm{OH}\) in the feed, (ii) temperature, and (iii) pressure.

A \(100 \mathrm{kmol} / \mathrm{h}\) stream that is 97 mole \(\%\) carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right)\) and \(3 \%\) carbon disulfide \(\left(\mathrm{CS}_{2}\right)\) is to be recovered from the bottom of a distillation column. The feed to the column is 16 mole \(\% \mathrm{CS}_{2}\) and \(84 \% \mathrm{CCl}_{4},\) and \(2 \%\) of the \(\mathrm{CCl}_{4}\) entering the column is contained in the overhead stream leaving the top of the column. (a) Draw and label a flowchart of the process and do the degree-of-freedom analysis. (b) Calculate the mass and mole fractions of \(\mathrm{CCl}_{4}\) in the overhead stream, and determine the molar flow rates of \(\mathrm{CCl}_{4}\) and \(\mathrm{CS}_{2}\) in the overhead and feed streams. (c) Suppose the overhead stream is analyzed and the mole fraction of \(\mathrm{CS}_{2}\) is found to be significantly lower than the value calculated in Part (b). List as many reasons as you can for the discrepancy, including possible violations of assumptions made in Part (b).

n-Pentane is burned with excess air in a continuous combustion chamber. (a) A technician runs an analysis and reports that the product gas contains 0.270 mole\% pentane, \(5.3 \%\) oxygen, \(9.1 \%\) carbon dioxide, and the balance nitrogen on \(a\) dry basis. Assume 100 mol of dry product gas as a basis of calculation, draw and label a flowchart, perform a degree-offreedom analysis based on atomic species balances, and show that the system has -1 degree of freedom. Interpret this result. (b) Use balances to prove that the reported percentages could not possibly be correct. (c) The technician reruns the analysis and reports new values of 0.304 mole\% pentane, \(5.9 \%\) oxygen, \(10.2 \%\) carbon dioxide, and the balance nitrogen. Verify that this result could be correct and, assuming that it is, calculate the percent excess air fed to the reactor and the fractional conversion of pentane. (d) It was emphasized in Part (c) that the new composition could be correct. Explain why it isn't possible to say for sure; illustrate your response by considering a set of equations with -1 degree of freedom.

Certain vegetables and fruits contain plant pigments called carotenoids that are metabolized in the body to produce Vitamin A. Lack of Vitamin A causes an estimated 250,000 to 500,000 children worldwide to become blind every year. An approach to reducing blindness and other childhood health problems resulting from this deficiency is to use genetic engineering of rice- -a food staple in developing countries and economically disadvantaged regions of the world \(-\) so that rice becomes a dietary source of Vitamin A. For example, a strain known as Golden Rice has been genetically engineered so that it can produce and store carotenoids such as \(\beta\) -carotene (which helps give carrots and squash their yellow-orange color). One type of Golden Rice contains approximately 30 micrograms of carotenoids (81\% \beta-carotene, 16\% \alpha- carotene, and 3\% \beta-cryptoxanthin) per gram of uncooked rice. A study has reported that when a person eats Golden Rice, their body metabolizes 1 microgram of Vitamin A for every 3.8 micrograms of \beta-carotene they consume. (a) It is recommended that children between 1 and 3 years of age should get 300 micrograms of Vitamin A per day. Considering only the metabolism of \(\beta\) -carotene given above, how many grams of Golden Rice would a child have to eat in order to obtain this much Vitamin A? Does this seem like a reasonable amount of rice to eat in one day, if one cup of cooked rice is approximately 175 g? (b) \(\alpha\) -carotene and \(\beta\) -cryptoxanthin can also be converted into Vitamin \(A\), but when compared to \beta-carotene, it takes twice as much of each of these compounds to produce one unit of Vitamin A. Considering all of the carotenoids in Golden Rice as potential sources of Vitamin A, how many grams of Golden Rice would a three-year-old child have to eat in order to obtain the recommended daily amount of Vitamin A? (c) Some individuals are not convinced that genetically modified foods are safe to grow or to eat. What kinds of risks or uncertainties are cited by these individuals? What kinds of measures are taken by farmers and suppliers of genetically modified seeds to minimize these risks? (d) Some people do not believe that Golden Rice is a practical, viable solution to Vitamin A deficiency around the world. Summarize the major arguments for and against production and distribution of Golden Rice.

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