/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 \- An equimolar liquid mixture o... [FREE SOLUTION] | 91Ó°ÊÓ

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\- An equimolar liquid mixture of benzene and toluene is separated into two product streams by distillation. A process flowchart and a somewhat oversimplified description of what happens in the process follow: Inside the column a liquid stream flows downward and a vapor stream rises. At each point in the column some of the liquid vaporizes and some of the vapor condenses. The vapor leaving the top of the column, which contains 97 mole\% benzene, is completely condensed and split into two equal fractions: one is taken off as the overhead product stream, and the other (the reflux) is recycled to the top of the column. The overhead product stream contains \(89.2 \%\) of the benzene fed to the column. The liquid leaving the bottom of the column is fed to a partial reboiler in which \(45 \%\) of it is vaporized. The vapor generated in the reboiler (the boilup) is recycled to become the rising vapor stream in the column, and the residual reboiler liquid is taken off as the bottom product stream. The compositions of the streams leaving the reboiler are governed by the relation $$\frac{y_{\mathrm{B}} /\left(1-y_{\mathrm{B}}\right)}{x_{\mathrm{B}} /\left(1-x_{\mathrm{B}}\right)}=2.25$$ where \(y_{\mathrm{B}}\) and \(x_{\mathrm{B}}\) are the mole fractions of benzene in the vapor and liquid streams, respectively. (a) Take a basis of 100 mol fed to the column. Draw and completely label a flowchart, and for each of four systems (overall process, column, condenser, and reboiler), do the degree-of-freedom analysis and identify a system with which the process analysis might appropriately begin (one with zero degrees of freedom). (b) Write in order the equations you would solve to determine all unknown variables on the flowchart, circling the variable for which you would solve in each equation. Do not do the calculations in this part. (c) Calculate the molar amounts of the overhead and bottoms products, the mole fraction of benzene in the bottoms product, and the percentage recovery of toluene in the bottoms product \((100 \times\) moles toluene in bottoms/mole toluene in feed).

Short Answer

Expert verified
The problem involves identification of a system with zero degrees of freedom, setting up mass and component balances and solving equations to determine unknown variables. Following computations, product streams are determined, leading to the determination of toluene recovery.

Step by step solution

01

Draw and Label Flowchart

Begin by drawing a process flowchart and labelling each part - feed stream, overhead product stream, bottom product stream, reflux and boilup. Assume a feed of 100 mol. The two main outputs are the overhead and bottoms product.
02

Degree of Freedom Analysis

The important systems identified are the overall process, the condenser, the column and the reboiler. Going by the rules of the degree-of-freedom analysis which involves comparing number of variables, equations, and specs, it is the condenser system that has zero degrees of freedom. It therefore provides the best starting point for process analysis. This is because as per given data, we can identify two equations and two variables (flowrates of the overhead product and reflux), giving a degree-of-freedom count of zero.
03

Write Equations for Unknown Variables

Begin by writing mass and component balance equations for each of the systems. The mass balance over the whole system yields F = D + B, where F, D and B are the molar flow rates of the feed, distillate and bottoms, respectively. Similarly, create component balances for benzene and toluene. Note down these equations and identify potential solutions. Remember not to solve anywhere at this step.
04

Solve Equations for Unknown Variables

The most important equation will be the compositional balance for benzene. The relationship given with respect to \(y_B\) and \(x_B\) can be used as the second equation. The two above-mentioned equations give us a pair of non-linear equations that may be solved simultaneously by numerical methods, providing us with specific values for \(y_B\) and \(x_B\), the mole fractions of benzene in the vapor and liquid streams respectively.
05

Calculate Toluene Recovery

This is a similar calculation where mole fraction is needed. The molar quantities of the overhead and bottom products and the mole fraction of benzene in the bottom product can be calculated from their molar flow rates and molar flow rate ratios. With these, the calculations for the percentage recovery of toluene in the bottom product can be made.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degree of Freedom Analysis
In chemical processes like distillation, understanding the degree of freedom is crucial. It allows us to determine if we have enough information to solve for all unknown variables within a system. Essentially, the degree of freedom (DoF) is calculated as the difference between the number of independent equations and the number of unknown variables. For example, in this exercise focusing on a distillation column, several subsystems need to be evaluated, such as the overall process, the condenser, the column, and the reboiler. The goal is to identify a subsystem with zero degrees of freedom, which means you have a perfectly balanced number of equations and unknowns, so you can begin finding solutions efficiently. In our case, the condenser system fits this criterion, because there are two unknowns and two pieces of information or equations available (namely, the flow rates of the overhead product and the reflux). Keep this concept in mind:
  • If DoF = 0, you can immediately start solving equations.
  • If DoF > 0, more data or assumptions are needed.
  • If DoF < 0, the system is overspecified, indicating redundant data.
This methodology ensures comprehensive system analysis and helps in organizing solutions systematically, promoting a logical approach in breaking down complex problems.
Flowchart Labeling
Labeling a flowchart correctly is vital in understanding and solving process flow problems like distillation. Flowcharts visually represent process streams and equipment, making it easier to balance material and track flow throughout the operation. In this task, drawing and labeling the process flowchart accurately helps show how 100 moles of an equimolar benzene-toluene mixture enters the distillation column.
For effective flowcharting:
  • Identify and draw all significant streams: feed stream, overhead product stream, bottom product stream.
  • Indicate paths for recycling streams such as the reflux and the boilup.
  • Label each stream with its known or assumed values, including compositions, flow rates, and mole fractions.
Such a graphical representation helps visualize how the streams interact and offers a baseline from which degree of freedom analysis and balance equations can be conducted. A well-constructed flowchart is your roadmap for organizing data and efficiently developing a solution strategy.
Mass and Component Balance Equations
Mass and component balances are essential mathematical tools used to analyze chemical processes, especially in distillation systems. They involve setting up equations based on the conservation of mass principle, ensuring input equals output plus accumulation for any substance within a system.For a system like a distillation column, master the two types of balances:
  • **Overall Mass Balance**: Starting with the equation \( F = D + B \), where \( F \) is the feed, \( D \) is the distillate (overhead) product, and \( B \) is the bottoms product.
  • **Component Balance**: Each component (benzene and toluene in this case) must satisfy their own mass balance equations. For benzene, you may have something like \( Fz_F = Dy_D + Bx_B \), where \( z_F \) is the feed composition, and \( y_D \) and \( x_B \) are mole fractions in distillate and bottoms, respectively.
Component balance equations help dissect the compositions within each stream. Applying these equations to individual components aids in solving for unknowns like mole fractions and flow quantities. By using these techniques methodically, you can achieve a detailed understanding of how the system transforms its inputs into outputs, crucial for determining recovery rates and product specifications.

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Most popular questions from this chapter

Seawater containing 3.50 wt\% salt passes through a series of 10 evaporators. Roughly equal quantities of water are vaporized in each of the 10 units and then condensed and combined to obtain a product stream of fresh water. The brine leaving each evaporator but the tenth is fed to the next evaporator. The brine leaving the tenth evaporator contains \(5.00 \mathrm{wt} \%\) salt. (a) Draw a flowchart of the process showing the first, fourth, and tenth evaporators. Label all the streams entering and leaving these three evaporators. (b) Write in order the set of equations you would solve to determine the fractional yield of fresh water from the process \(\left(\mathrm{kg} \mathrm{H}_{2} \mathrm{O} \text { recovered } / \mathrm{kg} \mathrm{H}_{2} \mathrm{O}\) in process feed) and the weight percent of salt in the \right. solution leaving the fourth evaporator. Each equation you write should contain no more than one previously undetermined variable. In each equation, circle the variable for which you would solve. Do not do the calculations. (c) Solve the equations derived in Part (b) for the two specified quantities. (d) The problem statement made no mention of the disposition of the 5 wt\% effluent from the tenth evaporator. Suggest two possibilities for its disposition and describe any environmental concerns that might need to be considered.

The indicator-dilution method is a technique used to determine flow rates of fluids in channels for which devices like rotameters and orifice meters cannot be used (e.g., rivers, blood vessels, and largediameter pipelines). A stream of an easily measured substance (the tracer) is injected into the channel at a known rate, and the tracer concentration is measured at a point far enough downstream of the injection point for the tracer to be completely mixed with the flowing fluid. The larger the flow rate of the fluid, the lower the tracer concentration at the measurement point. A gas stream that contains 1.50 mole \(\% \mathrm{CO}_{2}\) flows through a pipeline. Twenty (20.0) kilograms of \(\mathrm{CO}_{2}\) per minute is injected into the line. A sample of the gas is drawn from a point in the line 150 meters (a) Estimate the gas flow rate (kmol/min) upstream of the injection point. (b) Eighteen seconds elapse from the instant the additional \(\mathrm{CO}_{2}\) is first injected to the time the \(\mathrm{CO}_{2}\) concentration at the measurement point begins to rise. Assuming that the tracer travels at the average velocity of the gas in the pipeline (i.e., neglecting diffusion of \(\mathrm{CO}_{2}\) ), estimate the average velocity (m/s). If the molar gas density is \(0.123 \mathrm{kmol} / \mathrm{m}^{3}\), what is the pipe diameter?

A Claus plant converts gaseous sulfur compounds to elemental sulfur, thereby eliminating emission of sulfur into the atmosphere. The process can be especially important in the gasification of coal, which contains significant amounts of sulfur that is converted to \(\mathrm{H}_{2}\) S during gasification. In the Claus process, the \(\mathrm{H}_{2}\) S-rich product gas recovered from an acid-gas removal system following the gasifier is split, with one-third going to a furnace where the hydrogen sulfide is burned at 1 atm with a stoichiometric amount of air to form SO \(_{2}\). $$\mathrm{H}_{2} \mathrm{S}+\frac{3}{2} \mathrm{O}_{2} \rightarrow \mathrm{SO}_{2}+\mathrm{H}_{2} \mathrm{O}$$ The hot gases leave the furnace and are cooled prior to being mixed with the remainder of the \(\mathrm{H}_{2}\) S-rich gases. The mixed gas is then fed to a catalytic reactor where hydrogen sulfide and \(\mathrm{SO}_{2}\) react to form elemental sulfur. $$2 \mathrm{H}_{2} \mathrm{S}+\mathrm{SO}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}+3 \mathrm{S}$$ The coal available to the gasification process is 0.6 wt\% sulfur, and you may assume that all of the sulfur is converted to \(\mathrm{H}_{2} \mathrm{S}\), which is then fed to the Claus plant. (a) Estimate the feed rate of air to the Claus plant in \(\mathrm{kg} / \mathrm{kg}\) coal. (b) While the removal of sulfur emissions to the atmosphere is environmentally beneficial, identify an environmental concern that still must be addressed with the products from the Claus plant.

Ethylene oxide is produced by the catalytic oxidation of ethylene: $$ 2 \mathrm{C}_{2} \mathrm{H}_{4}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O} $$ An undesired competing reaction is the combustion of ethylene: $$ \mathrm{C}_{2} \mathrm{H}_{4}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} $$ The feed to the reactor (not the fresh feed to the process) contains 3 moles of ethylene per mole of oxygen. The single-pass conversion of ethylene is \(20 \%,\) and for every 100 moles of ethylene consumed in the reactor, 90 moles of ethylene oxide emerge in the reactor products. A multiple-unit process is used to separate the products: ethylene and oxygen are recycled to the reactor, ethylene oxide is sold as a product, and carbon dioxide and water are discarded. (a) Assume a quantity of the reactor feed stream as a basis of calculation, draw and label the flowchart, perform a degree-of-freedom analysis, and write the equations you would use to calculate (i) the molar flow rates of ethylene and oxygen in the fresh feed, (ii) the production rate of ethylene oxide, and (iii) the overall conversion of ethylene. Do no calculations. (b) Calculate the quantities specified in Part (a), either manually or with an equation-solving program. (c) Calculate the molar flow rates of ethylene and oxygen in the fresh feed needed to produce 1 ton per hour of ethylene oxide.

Ethanol can be produced commercially by the hydration of ethylene: $$\mathrm{C}_{2} \mathrm{H}_{4}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$$ Some of the product is converted to diethyl ether in the side reaction $$2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \rightarrow\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O}$$ The feed to the reactor contains ethylene, steam, and an inert gas. A sample of the reactor effluent gas is analyzed and found to contain 43.3 mole\% ethylene, 2.5\% ethanol, 0.14\% ether, 9.3\% inerts, and the balance water. (a) Take as a basis 100 mol of effluent gas, draw and label a flowchart, and do a degree-of-freedom analysis based on atomic species to prove that the system has zero degrees of freedom. (b) Calculate the molar composition of the reactor feed, the percentage conversion of ethylene, the fractional yield of ethanol, and the selectivity of ethanol production relative to ether production. (c) The percentage conversion of ethylene you calculated should be very low. Why do you think the reactor would be designed to consume so little of the reactant? (Hint: If the reaction mixture remained in the reactor long enough to use up most of the ethylene, what would the main product constituent probably be?) What additional processing steps are likely to take place downstream from the reactor?

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