/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A liquid mixture containing etha... [FREE SOLUTION] | 91Ó°ÊÓ

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A liquid mixture containing ethanol ( 55.0 wt\%) and the balance water enters a separation process unit at a rate of \(90.5 \mathrm{kg} / \mathrm{s}\). A technician draws samples of the two product streams leaving the separator and analyzes them with a gas chromatograph, obtaining values of 86.2 wt\% ethanol (Product Stream 1) and \(10.9 \%\) ethanol (Product Stream 2). The technician then reads a manometer attached to an orifice meter mounted in the pipe carrying Product Stream 1, converts the reading to a volumetric flow rate using a calibration curve, and converts that result to a mass flow rate using the average density of ethanol and water. The result is \(54.0 \mathrm{kg} / \mathrm{s}\). Finally, the technician calculates the mass flow rate of the second product stream using a material balance and reports the calculated product stream flow rates and compositions to you. You examine them, do some calculations, and reject them. (a) Draw and label a flow chart of the separation process. (b) Carry out the calculations that led you to reject the submitted results and explain how you knew the values were wrong. (c) List up to five possible reasons for the incorrect results. For each one, briefly state how you might determine whether it was in fact a cause of error and what you might do to correct it if it was.

Short Answer

Expert verified
The technician's results show discrepancies when compared with the calculated mass balances for ethanol and water conservation. The flow rate for Product Stream 2 is incorrectly reported. Possible reasons for these errors include incorrect calibration curve for the manometer, inaccurate density used for conversion, analytical error in gas chromatography, leaks or evaporation during process and inaccurate manometer readings.

Step by step solution

01

Drawing the Flowchart

Firstly, start by establishing a flowchart for the separation process. The flowchart comprises an inlet stream entering the system (90.5 kg/s of mixture containing 55 wt% ethanol), a separation unit where the ethanol-water mixture is divided into two streams – one concentrated in ethanol (Product Stream 1 with 86.2 wt% ethanol and flow rate 54.0 kg/s as measured by an orifice meter mounted in the pipe) and the other dilute ethanol stream (Product Stream 2 with 10.9 wt% ethanol, whose flow rate would be determined by material balance).
02

Calculation of Ethanol and Water Amount in Inlet Stream

Firstly, calculate the mass of ethanol and water in the inlet stream per second. Since it is given that the ethanol is 55% of the weight of the mixture entering, the amount of ethanol entering would be \(0.55*90.5=49.775 kg/s\). The balance is the water so amount would be \(90.5-49.775=40.725 kg/s\).
03

Calculation of Ethanol and Water Amount in Product Stream 1

Next, determine the amount of ethanol and water in product stream 1 per second. Given that the concentration of ethanol is 86.2%, the amount of ethanol in this stream is \(0.862*54.0=46.548 kg/s\). The balance is the water so that amount would be \(54.0-46.548= 7.452 kg/s\).
04

Calculation of Ethanol Amount in Product Stream 2

Next, determine the amount of ethanol in product stream 2 per second by performing a material balance around ethanol. According to conservation of mass, the total amount of ethanol entering the system should be equal to the total amount leaving. Therefore, the amount of ethanol in product stream 2 is \(49.775 - 46.548 = 3.227 kg/s\).
05

Calculation of Water Amount in Product Stream 2

Perform a similar material balance for water: the amount of water in product stream 2 is \(40.725 - 7.452= 33.273 kg/s\).
06

Calculation of Total Mass Flow Rates for each Product Stream

Product stream 1's mass flow rate is \(46.548 + 7.452 = 54.0 kg/s\), which matches the technician's measurement; yet Product stream 2's mass flow rate is \(3.227 + 33.273 = 36.5 kg/s\), which does not match the measured read because it was calculated incorrectly by the technician. This discrepancy leads to the rejection of the submitted results.
07

Potential Reasons for the Error

Several reasons could explain incorrect results. Some possible reasons include 1) The calibration curve for converting the manometer reading to volumetric flow rate may not be correct, 2) The average density used for converting volumetric flow rate to mass flow rate may not be accurate, 3) The gas chromatograph analysis could be inaccurate due to instrument error or mishandling of the sample, 4) Loss of ethanol or water to the environment due to evaporation or leakage during the process, 5) The manometer reading taken could be inaccurate. Each of these could be investigated further by checking calibration records, re-analyzing samples, visual inspections for leaks, and evaluating the conditions and procedures used by the technician.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Process Separation
Chemical process separation is a fundamental part of the chemical industry, designed to separate mixtures of compounds into distinct components. This can be accomplished through a variety of methods such as distillation, filtration, or extraction. In the context of the textbook exercise, an ethanol-water mixture undergoes separation to yield two distinct streams: one with a high concentration of ethanol and the other with a low concentration. Understanding how separations work and the principles behind them, like the equilibrium between components and the conservation of mass, is crucial for engineers and technicians in optimizing these processes.
Mass Flow Rate
The mass flow rate in chemical engineering refers to the amount of mass passing through a given point in a system per unit of time. It's denoted as kg/s in the metric system and is a critical parameter in the design and operation of most chemical processes. In the exercise, the mass flow rates of the product streams from the separation unit are focal points of the analysis. Accurate calculation of the mass flow rates is essential in ensuring that the inputs and outputs of the process balance, which is the basis of material balance calculations in process engineering.
Ethanol-Water Separation
Ethanol-water separation is often carried out using distillation, a process that takes advantage of the difference in boiling points between the two compounds. However, the separation is not perfect, and the process must be evaluated to ensure efficiency. With a binary mixture like ethanol and water, the separation strives to produce one stream enriched in ethanol and another in water. Inaccuracies in the separation process could lead to incorrect compositions or flow rates, leading to operational inefficiencies and potential product losses.
Flowchart Diagramming
Flowchart diagramming is an essential tool in process engineering for visualizing the steps and operations within a chemical process. Flowcharts use symbols and arrows to depict the flow of materials and transformation steps in the process. Properly drawing and labeling a flowchart, as required in part (a) of the exercise, helps process operators, engineers, and technicians to understand and communicate the process flow clearly. It serves as a blueprint that outlines how inputs are processed to yield desired outputs.
Process Unit Operation
A process unit operation refers to a fundamental step in a processing system where a physical or chemical change happens. Common unit operations in chemical engineering include separation, reaction, heat exchange, and mass transfer. Each operation requires careful design and control to meet specific objectives. In the case of the textbook exercise, the separation process unit operation focuses on dividing the ethanol-water mixture into distinct streams with different ethanol concentrations.
Material Balance Error Analysis
Material balance error analysis involves inspecting the inputs and outputs of a process to ensure the law of conservation of mass is satisfied. When the numbers don't add up, as in the erroneous technician's data reported in the exercise, it indicates possible measurement errors, process leaks, or procedural mistakes. Identifying and addressing these issues is vital for reliable operation and credibility of the process performance. Error analysis often starts with a return to the basic principles, measuring and validating each step of the process, from raw data collection through to the final calculation of flow rates and compositions.

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Most popular questions from this chapter

A garment to protect the wearer from toxic agents may be made of a fabric that contains an adsorbent, such as activated carbon. In a test of such a fabric, a gas stream containing \(7.76 \mathrm{mg} / \mathrm{L}\) of carbon tetrachloride (CCl_) was passed through a 7.71-g sample of the fabric at a rate of 1.0 L/min, and the concentration of \(\mathrm{CCl}_{4}\) in the gas leaving the fabric was monitored. The run was continued for \(15.5 \mathrm{min}\) with no \(\mathrm{CCl}_{4}\) being detected, after which the \(\mathrm{CCl}_{4}\) concentration began to rise. (a) How much CCl_ was fed to the system during the first 15.5 min of the run? How much was adsorbed? Using this information as a guide, sketch the expected concentration of \(\mathrm{CCl}_{4}\) in the exit gas as a function of time, showing the curve from \(t=0\) to \(t \gg 15.5\) min. (b) Assuming a linear relationship between amount of \(\mathrm{CCl}_{4}\) adsorbed and mass of fabric, what fabric mass would be required if the feed concentration is \(5 \mathrm{mg} / \mathrm{L},\) the feed rate \(1.4 \mathrm{L} / \mathrm{min},\) and it is desired that no \(\mathrm{CCl}_{4}\) leave the fabric earlier than 30 min?

A stream consisting of 44.6 mole \(\%\) benzene and \(55.4 \%\) toluene is fed at a constant rate to a process unit that produces two product streams, one a vapor and the other a liquid. The vapor flow rate is initially zero and asymptotically approaches half of the molar flow rate of the feed stream. Throughout this entire period, no material accumulates in the unit. When the vapor flow rate has become constant, the liquid is analyzed and found to be 28.0 mole\% benzene. (a) Sketch a plot of liquid and vapor flow rates versus time from startup to when the flow rates become constant. (b) Is this process batch or continuous? Is it transient or steady-state before the vapor flow rate reaches its asymptotic limit? What about after it becomes constant? (c) For a feed rate of 100 mol/min, draw and fully label a flowchart for the process after the vapor flow rate has reached its limiting value, and then use balances to calculate the molar flow rate of the liquid and the composition of the vapor in mole fractions.

In an absorption tower (or absorber), a gas is contacted with a liquid under conditions such that one or more species in the gas dissolve in the liquid. A stripping tower (or stripper) also involves a gas contacting a liquid, but under conditions such that one or more components of the feed liquid come out of solution and exit in the gas leaving the tower. A process consisting of an absorption tower and a stripping tower is used to separate the components of a gas containing 30.0 mole \(\%\) carbon dioxide and the balance methane. A stream of this gas is fed to the bottom of the absorber. A liquid containing 0.500 mole\% dissolved \(\mathrm{CO}_{2}\) and the balance methanol is recycled from the bottom of the stripper and fed to the top of the absorber. The product gas leaving the top of the absorber contains 1.00 mole \(\% \mathrm{CO}_{2}\) and essentially all of the methane fed to the unit. The CO_-rich liquid solvent leaving the bottom of the absorber is fed to the top of the stripper and a stream of nitrogen gas is fed to the bottom. Ninety percent of the \(\mathrm{CO}_{2}\) in the liquid feed to the stripper comes out of solution in the column, and the nitrogen/CO_stream leaving the column passes out to the atmosphere through a stack. The liquid stream leaving the stripping tower is the \(0.500 \% \mathrm{CO}_{2}\) solution recycled to the absorber. The absorber operates at temperature \(T_{\mathrm{a}}\) and pressure \(P_{\mathrm{a}}\) and the stripper operates at \(T_{\mathrm{s}}\) and \(P_{\mathrm{s}}\) Methanol may be assumed to be nonvolatile- -that is, none enters the vapor phase in either column and \(\mathrm{N}_{2}\), may be assumed insoluble in methanol. (a) In your own words, explain the overall objective of this two-unit process and the functions of the absorber and stripper in the process. (b) The streams fed to the tops of each tower have something in common, as do the streams fed to the bottoms of each tower. What are these commonalities and what is the probable reason for them? (c) Taking a basis of 100 mol/h of gas fed to the absorber, draw and label a flowchart of the process. For the stripper outlet gas, label the component molar flow rates rather than the total flow rate and mole fractions. Do the degree-of-freedom analysis and write in order the equations you would solve to determine all unknown stream variables except the nitrogen flow rate entering and leaving the stripper. Circle the variable(s) for which you would solve each equation (or set of simultaneous equations), but don't do any of the calculations yet. (d) Calculate the fractional \(\mathrm{CO}_{2}\) removal in the absorber (moles absorbed/mole in gas feed) and the molar flow rate and composition of the liquid feed to the stripping tower. (e) Calculate the molar feed rate of gas to the absorber required to produce an absorber product gas flow rate of \(1000 \mathrm{kg} / \mathrm{h}\). (f) Would you guess that \(T_{\mathrm{s}}\) would be higher or lower than \(T_{\mathrm{a}} ?\) Explain. (Hint: Think about what happens when you heat a carbonated soft drink and what you want to happen in the stripper.) What about the relationship of \(P_{\mathrm{s}}\) to \(P_{\mathrm{a}} ?\) (g) What properties of methanol would you guess make it the solvent of choice for this process? (In more general terms, what would you look for when choosing a solvent for an absorption-stripping process to separate one gas from another?)

An evaporation-crystallization process of the type described in Example \(4.5-2\) is used to obtain solid potassium sulfate from an aqueous solution of this salt. The fresh feed to the process contains 19.6 wt\% \(\mathrm{K}_{2} \mathrm{SO}_{4}\). The wet filter cake consists of solid \(\mathrm{K}_{2} \mathrm{SO}_{4}\) crystals and a \(40.0 \mathrm{wt} \% \mathrm{K}_{2} \mathrm{SO}_{4}\) solution, in a ratio \(10 \mathrm{kg}\) crystals/kg solution. The filtrate, also a \(40.0 \%\) solution, is recycled to join the fresh feed. Of the water fed to the evaporator, 45.0\% is evaporated. The evaporator has a maximum capacity of 175 kg water evaporated/s. (a) Assume the process is operating at maximum capacity. Draw and label a flowchart and do the degree-of-freedom analysis for the overall system, the recycle-fresh feed mixing point, the evaporator, and the crystallizer. Then write in an efficient order (minimizing simultaneous equations) the equations you would solve to determine all unknown stream variables. In each equation, circle the variable for which you would solve, but don't do the calculations. (b) Calculate the maximum production rate of solid \(\mathrm{K}_{2} \mathrm{SO}_{4}\), the rate at which fresh feed must be supplied to achieve this production rate, and the ratio kg recycle/kg fresh feed. (c) Calculate the composition and feed rate of the stream entering the crystallizer if the process is scaled to 75\% of its maximum capacity. (d) The wet filter cake is subjected to another operation after leaving the filter. Suggest what it might be. Also, list what you think the principal operating costs for this process might be. (e) Use an equation-solving computer program to solve the equations derived in Part (a). Verify that you get the same solutions determined in Part (b).

A fuel oil is fed to a furnace and burned with \(25 \%\) excess air. The oil contains \(87.0 \mathrm{wt} \% \mathrm{C}, 10.0 \% \mathrm{H},\) and 3.0\% S. Analysis of the furnace exhaust gas shows only \(\mathrm{N}_{2}, \mathrm{O}_{2}, \mathrm{CO}_{2}, \mathrm{SO}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}\). The sulfur dioxide emission rate is to be controlled by passing the exhaust gas through a scrubber, in which most of the \(\mathrm{SO}_{2}\) is absorbed in an alkaline solution. The gases leaving the scrubber (all of the \(\mathrm{N}_{2}, \mathrm{O}_{2},\) and \(\mathrm{CO}_{2}\), and some of the \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{SO}_{2}\) entering the unit) pass out to a stack. The scrubber has a limited capacity, however, so that a fraction of the furnace exhaust gas must be bypassed directly to the stack. At one point during the operation of the process, the scrubber removes \(90 \%\) of the \(\mathrm{SO}_{2}\) in the gas fed to it, and the combined stack gas contains 612.5 ppm (parts per million) \(\mathrm{SO}_{2}\) on a dry basis; that is, every million moles of dry stack gas contains 612.5 moles of \(\mathrm{SO}_{2}\). Calculate the fraction of the exhaust bypassing the scrubber at this moment.

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