/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A garment to protect the wearer ... [FREE SOLUTION] | 91Ó°ÊÓ

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A garment to protect the wearer from toxic agents may be made of a fabric that contains an adsorbent, such as activated carbon. In a test of such a fabric, a gas stream containing \(7.76 \mathrm{mg} / \mathrm{L}\) of carbon tetrachloride (CCl_) was passed through a 7.71-g sample of the fabric at a rate of 1.0 L/min, and the concentration of \(\mathrm{CCl}_{4}\) in the gas leaving the fabric was monitored. The run was continued for \(15.5 \mathrm{min}\) with no \(\mathrm{CCl}_{4}\) being detected, after which the \(\mathrm{CCl}_{4}\) concentration began to rise. (a) How much CCl_ was fed to the system during the first 15.5 min of the run? How much was adsorbed? Using this information as a guide, sketch the expected concentration of \(\mathrm{CCl}_{4}\) in the exit gas as a function of time, showing the curve from \(t=0\) to \(t \gg 15.5\) min. (b) Assuming a linear relationship between amount of \(\mathrm{CCl}_{4}\) adsorbed and mass of fabric, what fabric mass would be required if the feed concentration is \(5 \mathrm{mg} / \mathrm{L},\) the feed rate \(1.4 \mathrm{L} / \mathrm{min},\) and it is desired that no \(\mathrm{CCl}_{4}\) leave the fabric earlier than 30 min?

Short Answer

Expert verified
For part (a), the total fed amount and the quantity of CCl_4 adsorbed by the fabric is \(120 \, \text{mg}\), and the concentration profile would be at zero for the first 15.5 min, then increase progressively. For part (b), approximately \(16.8 \, \text{g}\) of fabric is required to adsorb all CCl_4 for the first 30 minutes under the new conditions.

Step by step solution

01

Calculate Carbon tetrachloride (CCl4) fed to the system

Use the formula: \[ \text{Mass}_{\text{fed}} = C \times Q \times t \] Where: \(C = 7.76 \, \text{mg/L}\) (Concentration), \(Q = 1.0 \, \text{L/min}\) (Flow rate), and \(t = 15.5 \, \text{min}\) (Time).
02

Calculate adsorbed CCl4

Since there is no CCl4 detected in the exiting gas stream for the first 15.5 minutes, all of it is adsorbed by the fabric. Thus the total adsorbed quantity is equal to the fed quantity.
03

Sketch concentration profile

The concentration profile would be a straight line along the time-axis for the first 15.5 min, indicating zero concentration of CCl4. After this point, the concentration will start to increase progressively as the fabric becomes saturated and cannot adsorb any more CCl4.
04

Calculate Required Fabric Mass for new Conditions

From Step 2, we know that a 7.71 g fabric sample can adsorb all CCl4 fed in the first 15.5 min. With the new conditions, calculation will use the formula: \[ \text{Mass}_{\text{fabric}} = (C_{\text{new}} \times Q_{\text{new}} \times t_{\text{new}} / \text{Mass}_{\text{CCl4, adsorbed}} ) \times \text{Mass}_{\text{fabric}} \] Where: \(C_{\text{new}} = 5 \, \text{mg/L}\), \(Q_{\text{new}} = 1.4 \, \text{L/min}\), \(t_{\text{new}} = 30 \, \text{min}\), \(\text{Mass}_{\text{CCl4, adsorbed}}\) is from step 2 and \(\text{Mass}_{\text{fabric}} = 7.71 \, \text{g}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Adsorbent Materials
Adsorbent materials play a crucial role in protective garments for filtering toxic agents, like in the case of the exercise involving activated carbon and carbon tetrachloride (CCl4). These materials, by virtue of their porous structure, offer extensive surface area for the attachment, or 'adsorption', of molecules from gases or liquids.

Activated carbon, a commonly used adsorbent, is made by processing carbon-rich materials, such as wood, coconut shells, or coal, to increase porosity and surface area. During adsorption, the pollutants adhere to the surface of the activated carbon, getting trapped in the internal pore structure, thereby cleaning the medium (gas or liquid) passing through it.

Understanding the capacity of an adsorbent material is essential, as in the textbook exercise, to determine how long it will effectively filter a specific contaminant before becoming saturated. Once saturated, no more adsorption can occur, and the toxic agents will pass through, hence the rise of CCl4 concentration after 15.5 minutes as indicated in the exercise.
Mass Transfer in Chemical Engineering
Mass transfer is one of the foundational pillars of chemical engineering, dealing with the movement and distribution of a substance from one location to another, which may occur due to concentration gradients or differences in chemical potential. In the context of our exercise, mass transfer explains how the CCl4 moves from the gas stream into the fabric's adsorbent material.

The efficiency of mass transfer in a system such as the gas stream through fabric relates directly to the adsorption kinetics - the rate at which CCl4 molecules come into contact and adhere to the activated carbon in the fabric. Initially, when the adsorbent is fresh, the mass transfer rate is high because there are many available sites for adsorption. However, as these sites fill up over time, the rate decreases, which is why we observe no CCl4 in the exit gas for the first 15.5 minutes in the exercise. Eventually, the fabric becomes saturated, and the mass transfer effectively ceases, leading to a detectable concentration of CCl4 in the exiting gas.
Activated Carbon Filtration
Activated carbon filtration is a common method used in both protective wear and various industrial processes. It leverages the porous nature of activated carbon to remove contaminants via physical adsorption. The adsorption capacity highly depends on factors such as the concentration of contaminants, flow rate, temperature, and contact time.

In the exercise scenario, activated carbon is used in a fabric to filter out CCl4 from the air. The filtration performance relies on the amount of activated carbon present, which is directly proportional to the mass of the fabric. This is demonstrated in part (b) of the exercise, which requires calculation of fabric mass needed for extended filtration time using ratios derived from the initial experiment conditions.

Furthermore, activated carbon filtration is not infinite – it has a finite capacity for adsorbing pollutants, after which it must be replaced or regenerated. This is apparent when the fabric starts to allow CCl4 to pass through after 15.5 minutes, indicating it is a critical factor to consider while designing filtration systems for protective garments or other applications.

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Most popular questions from this chapter

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