/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 The following empirical equation... [FREE SOLUTION] | 91Ó°ÊÓ

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The following empirical equation correlates the values of variables in a system in which solid particles are suspended in a flowing gas: $$\frac{k_{g} d_{p} y}{D}=2.00+0.600\left(\frac{\mu}{\rho D}\right)^{1 / 3}\left(\frac{d_{p} u \rho}{\mu}\right)^{1 / 2}$$ Both \((\mu / \rho D)\) and \(\left(d_{p} u \rho / \mu\right)\) are dimensionless groups; \(k_{g}\) is a coefficient that expresses the rate at which a particular species transfers from the gas to the solid particles; and the coefficients 2.00 and 0.600 are dimensionless constants obtained by fitting experimental data covering a wide range of values of the equation variables. The value of \(k_{g}\) is needed to design a catalytic reactor. since this coefficient is difficult to determine directly, values of the other variables are measured or estimated and \(k_{g}\) is calculated from the given correlation. The variable values are as follows: $$\begin{aligned}d_{p} &=5.00 \mathrm{mm} \\\y &=0.100 \quad(\text { dimensionless }) \\\D &=0.100 \mathrm{cm}^{2} / \mathrm{s} \\\\\mu &=1.00 \times 10^{-5} \mathrm{N} \cdot \mathrm{s} / \mathrm{m}^{2} \\\\\rho &=1.00 \times 10^{-3} \mathrm{g} / \mathrm{cm}^{3} \\\u &=10.0 \mathrm{m} / \mathrm{s}\end{aligned}$$ (a) What is the estimated value of \(k_{g} ?\) (Give its value and units.) (b) Why might the true value of \(k_{g}\) in the reactor be significantly different from the value estimated in Part (a)? (Give several possible reasons.) (c) Create a spreadsheet in which up to five sets of values of the given variables ( \(d_{p}\) through \(u\) ) are entered in columns and the corresponding values of \(k_{g}\) are calculated. Test your program using the following variable sets: (i) the values given above; (ii) as above, only double the particle diameter \(d_{p}\) (making it \(10.00 \mathrm{mm}\) ); (iii) as above, only double the diffusivity \(D ;\) (iv) as above, only double the viscosity \(\mu ;(\mathrm{v})\) as above, only double the velocity \(u\). Report all five calculated values of \(k_{g}\).

Short Answer

Expert verified
The estimated values of \(k_{g}\) will be determined by following the calculation in steps, while the reasoning behind potential differences between estimated and actual values of \(k_{g}\) are stated in a theoretical manner. The spreadsheet simulation is better carried out practically but an explanation of the process is given.

Step by step solution

01

Rearrange the equation to solve for \(k_{g}\)

Algebra is used to isolate \(k_{g}\) from the equating, resulting in the formula \( k_{g} = \frac{D \cdot (2.00+0.600\left(\frac{\mu}{\rho D}\right)^{1 / 3}\left(\frac{d_{p} u \rho}{\mu}\right)^{1 / 2})}{d_{p}y} \). This will be used to just insert values and calculate \(k_{g}\)
02

Insert values into the equation

First, we check for units and make sure they are all consistent. Here, we change \(d_{p}= 5.00 \mathrm{mm}\) to \(d_{p}= 0.005 \mathrm{m}\) and \(\rho = 1.00 \times 10^{-3} \mathrm{g}/\mathrm{cm}^3\) to \(\rho = 1.00 \times 10^{3} \mathrm{kg}/\mathrm{m}^3\). Then substitute all the values into the rearranged formula calculated in step 1. Solve the equation to get \(k_{g}\).
03

Reasoning for difference in estimated \(k_{g}\)

Several aspects can enable \(k_{g}\) to differ, among them include: Changes in experiment conditions like temperature and pressure, errors in measurement of variables, approximations in the empirical formula, non - ideal behaviours not captured by the empirical formula. These explanations demonstrate comprehension of the factors that come into play throughout a physical experiment.
04

Spreadsheet simulation

Create a spreadsheet with one column for each variable (\(d_{p}\), \(y\), \(\rho\), \(\mu\), \(u\), and \(D\)), as well as one for \(k_{g}\). For each set of values: repeat step 2 for various sets of variables and keep track of each computed \(k_{g}\) value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Transfer Coefficient Calculation
The mass transfer coefficient, denoted as \(k_g\), plays a crucial role in catalytic reactor design, as it characterizes the rate of transfer of a species from one phase to another—in this case, from the gas phase to solid particles in suspension.

To calculate \(k_g\), we use an empirical equation which correlates various system variables. The correlation aims to bridge the gap between theoretical models and real-world behavior. When we analyze the empirical equation provided in the exercise, \(k_g\) is depicted as partially dependent on the particle diameter \(d_p\), the diffusivity \(D\), and other variables.

The given empirical formula ensures dimensions are consistent, and it can be rearranged algebraically to isolate \(k_g\). With this rearrangement, inserting the given values while taking care to maintain unit consistency—namely converting millimeters to meters and grams to kilograms—allows for the computation of \(k_g\). This step-by-step approach ensures a clear method to evaluate the concept of mass transfer within chemical engineering problems.
Dimensional Analysis in Chemical Processes
Dimensional analysis is a method widely used in chemical engineering to ensure that equations make sense in terms of measurement units. It involves checking that both sides of an equation are dimensionally consistent. This process confirms that the derived relationships between physical quantities are valid and serves as a critical check against calculation errors.

In the given exercise, the dimensionless groups, such as \((\frac{\rho D}{\rho})\) and \((\frac{d_{p} u \rho}{\rho})\), result from the practice of dimensional analysis, ensuring that only ratios of like dimensions are compared. This technique aids in simplifying complex physical phenomena into dimensionless relationships that are universally applicable, allowing for the scaling of processes to different sizes and conditions.

The correct handling of units in the calculation of \(k_g\) showcases the importance of dimensional analysis. This attention to detail is essential, as ignoring the principles of dimensional analysis can lead to significant errors in design and operation of chemical processes.
Empirical Correlation in Chemical Engineering
Empirical correlations are fundamental in chemical engineering for describing complex systems where comprehensive theoretical models may not exist or are too intricate to solve directly. These correlations are derived from experimental data and provide simplified relationships between variables in a form that can be easily utilized for engineering calculations.

The original exercise presents an empirical correlation for the mass transfer coefficient. The constants 2.00 and 0.600 included in the equation come from statistical fits to experimental data across varying conditions. These constants are essential for capturing trends observed in the data, yet their empirical nature means they may not hold exactly across all conceivable scenarios. This underpins the importance of empirically derived correlations, illustrating how they ease the computational burden and enable engineers to estimate process parameters effectively.

Using the empirical correlation to calculate \(k_g\) emphasizes its utility but also highlights why true reactor performance may differ from the estimated values. Factors such as temperature, pressure, or deviations from ideal behavior—which might not be fully represented in the correlation—can lead to discrepancies. Therefore, while extremely useful, engineers often treat empirical correlations with caution, knowing that validation against actual system behavior is paramount.

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Most popular questions from this chapter

A seed crystal of diameter \(D\) (mm) is placed in a solution of dissolved salt, and new crystals are observed to nucleate (form) at a constant rate \(r\) (crystals/min). Experiments with seed crystals of different sizes show that the rate of nucleation varies with the seed crystal diameter as \(r(\text { crystals/min })=200 D-10 D^{2} \quad(D \text { in } \mathrm{mm})\) (a) What are the units of the constants 200 and \(10 ?\) (Assume the given equation is valid and therefore dimensionally homogeneous.) (b) Calculate the crystal nucleation rate in crystals/s corresponding to a crystal diameter of 0.050 inch. (c) Derive a formula for \(r\) (crystals/s) in terms of \(D\) (inches). (See Example \(2.6-1 .\) ) Check the formula using the result of Part (b). (d) The given equation is empirical; that is, instead of being developed from first principles, it was obtained simply by fitting an equation to experimental data. In the experiment, seed crystals of known size were immersed in a well-mixed supersaturated solution. After a fixed run time, agitation was ceased and the crystals formed during the experiment were allowed to settle to the bottom of the apparatus, where they could be counted. Explain what it is about the equation that gives away its empirical nature. (Hint: Consider what the equation predicts as \(D\) continues to increase.)

During the early part of the 20 th century, sulfanilamide (an antibacterial drug) was only administered by injection or in a solid pill. In \(1937,\) a pharmaceutical company decided to market a liquid formulation of the drug. Since sulfanilamide was known to be highly insoluble in water and other common pharmaceutical solvents, a number of alternative solvents were tested and the drug was found to be soluble in diethylene glycol (DEG). After satisfactory results were obtained in tests of flavor, appearance, and fragrance, 240 gallons of sulfanilamide in DEG were manufactured and marketed as Elixir Sulfanilamide. After a number of deaths were determined to have been caused by the formulation, the Food and Drug Administration (FDA) mounted a campaign to recall the drug and recovered about 232 gallons. By this time, 107 people had died. The incident led to passage of the 1938 Federal Food, Drug, and cosmetic Act that significantly tightened FDA safety requirements. Not all of the quantities needed in solving the following problems can be found in the text. Give sources of such information and list all assumptions. (a) The dosage instructions for the elixir were to "take 2 to 3 teaspoons in water every four hours." Assume each teaspoon was pure DEG, and estimate the volume (mL) of DEG a patient would have consumed in a day. (b) The lethal oral dose of diethylene glycol has been estimated to be 1.4 mL DEG/kg body mass. Determine the maximum patient mass \(\left(1 \mathrm{b}_{\mathrm{m}}\right)\) for which the daily dose estimated in Part (a) would be fatal. If you need values of quantities you cannot find in this text, use the Internet. Suggest three reasons why that dose could be dangerous to a patient whose mass is well above the calculated value. (c) Estimate how many people would have been poisoned if the total production of the drug had been consumed. (d) List steps the company should have taken that would have prevented this tragedy.

Suppose you have \(n\) data points \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots,\left(x_{n}, y_{n}\right)\) and you wish to fit a line through the origin \((y=a x)\) to these data using the method of least squares. Derive Equation A.1-6 (Appendix A.1) for the slope of the line by writing the expression for the vertical distance \(d_{i}\) from the \(i\) th data point \(\left(x_{i}, y_{i}\right)\) to the line, then writing the expression for \(\phi=\sum d_{i}^{2},\) and finding by differentiation the value of \(a\) that minimizes this function.

State what you would plot to get a straight line if experimental ( \(x, y\) ) data are to be correlated by the following relations, and what the slopes and intercepts would be in terms of the relation parameters. If you could equally well use two different kinds of plots (e.g., rectangular or semilog), state what you would plot in each case. [The solution to Part (a) is given as an example.] (a) \(y^{2}=a e^{-b / x}\). (b) \(y^{2}=m x^{3}-n\) (c) \(1 / \ln (y-3)=(1+a \sqrt{x}) / b\) (d) \((y+1)^{2}=\left[a(x-3)^{3}\right]^{-1}\) (e) \(y=\exp (a \sqrt{x}+b)\) (f) \(x y=10^{\left[a\left(x^{2}+y^{2}\right)+b\right]}\) (g) \(y=[a x+b / x]^{-1}\)

A waste treatment pond is \(50 \mathrm{m}\) long and \(25 \mathrm{m}\) wide, and has an average depth of \(2 \mathrm{m}\). The density of the waste is \(75.3 \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\). Calculate the weight of the pond contents in \(\mathrm{lb}_{\mathrm{f}},\) using a single dimensional equation for your calculation.

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