/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A waste treatment pond is \(50 \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A waste treatment pond is \(50 \mathrm{m}\) long and \(25 \mathrm{m}\) wide, and has an average depth of \(2 \mathrm{m}\). The density of the waste is \(75.3 \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\). Calculate the weight of the pond contents in \(\mathrm{lb}_{\mathrm{f}},\) using a single dimensional equation for your calculation.

Short Answer

Expert verified
The weight of the pond contents is approximately \(6668269.406 lb_f\).

Step by step solution

01

Convert the dimensions from meters to feet

Converting the dimensions of the pond from meters to feet using the conversion factor \(1 m = 3.281 ft\). Using this conversion factor, the length, width, and depth become: \\(50 m * 3.281 ft/m = 164.042 ft \\) \\(25 m * 3.281 ft/m = 82.021 ft \\) \\(2 m * 3.281 ft/m = 6.562 ft \\)Thus, the dimensions of the pond in feet are approximately \(164.042 ft \times 82.021 ft \times 6.562 ft\).
02

Calculate the volume of the pond

Volume is found by multiplying length, width, and depth. Thus, the volume of the pond in cubic feet will be: \\(Volume = Length \times Width \times Depth = 164.042 ft \times 82.021 ft \times 6.562 ft = 88499.420 ft^3\).
03

Calculate the weight of the pond's contents

Now that we have the volume of the pond in cubic feet, we can multiply it by the density of the waste (given as \(75.3 lb_m/ft^3\)) to find the weight of the pond's contents. Weight is found by multiplying volume by density. Thus, the weight of the pond's contents will be: \\(Weight = Volume \times Density = 88499.420 ft^3 \times 75.3 lb_m/ft^3 =6668269.406 lb_f\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Waste Treatment Pond Calculation
When calculating the metrics for a waste treatment pond, such as the one described in the exercise, understanding the dimensions and their interplay with volume and density is pivotal. Crucial to this calculation is the realization that a waste treatment pond is a three-dimensional space for which the volume must be ascertained to determine other values, such as weight or mass. First, one must compute the volume using the given length, width, and depth measurements. It's essential to use consistent units when performing these calculations, typically converting to either metric or imperial. In the example given, meters were converted to feet to align with the density unit.

To compute the volume, you multiply the length by the width and then by the depth. Once you have the volume, you can proceed to the next step, which is to determine the weight of the pond's contents by multiplying the volume and the density of the matter within the pond. This is vital in the context of environmental engineering, where the mass of waste needs to be known for treatment and regulatory purposes. Careful and accurate calculations ensure compliance with environmental standards and help in designing effective waste treatment strategies.
Unit Conversion in Chemical Engineering
Unit conversion is a fundamental aspect of chemical engineering calculations. As observed in the waste treatment pond scenario, converting the pond dimensions from the metric system (meters) to the imperial system (feet) was necessary for consistent calculations. This process is quintessential because various regions and sectors use different measurement systems, and a standardized approach is required to ensure precise engineering outcomes.

Mathematically, the unit conversion involves multiplying the original measurement by a conversion factor, which is a ratio that expresses how many of one unit are equivalent to another. For example, converting from meters to feet utilizes the conversion ratio where \(1 \text{ meter} = 3.281 \text{ feet}\). It is crucial for students and professionals alike to become proficient in these conversions, as the improper application can lead to significant errors in calculations and potentially to flawed design or operational decisions in a chemical process.
Volume and Density Calculations
Volume and density are key concepts in various scientific and engineering fields, including chemical engineering and environmental management. Volume, which measures the amount of three-dimensional space an object occupies, can be calculated for regular shapes (like the waste treatment pond) by multiplication of its dimensions: length, width, and depth.

Density, on the other hand, is a measure of mass per unit volume and is a critical property that dictates how much matter is packed within a given space. In the given exercise, the density of the waste material was provided, facilitating the calculation of the waste's weight in the pond. The formula for calculating weight in this context is given by the product of volume and density as shown by \( \text{Weight} = \text{Volume} \times \text{Density} \). This concept is widely applied in design and operation processes within chemical engineering, where accurate volume and density calculations are necessary for determining the quantities of reactants and products in various processes, which in turn are essential for scaling up from laboratory to industrial production.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

During the early part of the 20 th century, sulfanilamide (an antibacterial drug) was only administered by injection or in a solid pill. In \(1937,\) a pharmaceutical company decided to market a liquid formulation of the drug. Since sulfanilamide was known to be highly insoluble in water and other common pharmaceutical solvents, a number of alternative solvents were tested and the drug was found to be soluble in diethylene glycol (DEG). After satisfactory results were obtained in tests of flavor, appearance, and fragrance, 240 gallons of sulfanilamide in DEG were manufactured and marketed as Elixir Sulfanilamide. After a number of deaths were determined to have been caused by the formulation, the Food and Drug Administration (FDA) mounted a campaign to recall the drug and recovered about 232 gallons. By this time, 107 people had died. The incident led to passage of the 1938 Federal Food, Drug, and cosmetic Act that significantly tightened FDA safety requirements. Not all of the quantities needed in solving the following problems can be found in the text. Give sources of such information and list all assumptions. (a) The dosage instructions for the elixir were to "take 2 to 3 teaspoons in water every four hours." Assume each teaspoon was pure DEG, and estimate the volume (mL) of DEG a patient would have consumed in a day. (b) The lethal oral dose of diethylene glycol has been estimated to be 1.4 mL DEG/kg body mass. Determine the maximum patient mass \(\left(1 \mathrm{b}_{\mathrm{m}}\right)\) for which the daily dose estimated in Part (a) would be fatal. If you need values of quantities you cannot find in this text, use the Internet. Suggest three reasons why that dose could be dangerous to a patient whose mass is well above the calculated value. (c) Estimate how many people would have been poisoned if the total production of the drug had been consumed. (d) List steps the company should have taken that would have prevented this tragedy.

Suppose you have \(n\) data points \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots,\left(x_{n}, y_{n}\right)\) and you wish to fit a line through the origin \((y=a x)\) to these data using the method of least squares. Derive Equation A.1-6 (Appendix A.1) for the slope of the line by writing the expression for the vertical distance \(d_{i}\) from the \(i\) th data point \(\left(x_{i}, y_{i}\right)\) to the line, then writing the expression for \(\phi=\sum d_{i}^{2},\) and finding by differentiation the value of \(a\) that minimizes this function.

You arrive at your lab at 8 A.M. and add an indeterminate quantity of bacterial cells to a flask. At 11 A.M. you measure the number of cells using a spectrophotometer (the absorbance of light is directly related to the number of cells) and determine from a previous calibration that the flask contains 3850 cells, and at 5 P.M. the cell count has reached 36,530. (a) Fit each of the following formulas to the two given data points (that is, determine the values of the two constants in each formula): linear growth, \(C=C_{0}+k t ;\) exponential growth, \(C=C_{0} e^{k t} ;\) power-law growth, \(C=k t^{b} .\) In these expressions, \(C_{0}\) is the initial cell concentration and \(k\) and \(b\) are constants. (b) Select the most reasonable of the three formulas and justify your selection. (c) Estimate the initial number of cells present at 8 A.M. \((t=0)\). State any assumptions you make. (d) The culture needs to be split into two equal parts once the number of cells reaches 2 million. Estimate the time at which you would have to come back to perform this task. State any assumptions you make. If this is a routine operation that you must perform often, what does your result suggest about the scheduling of the experiment?

A solution containing hazardous waste is charged into a storage tank and subjected to a chemical treatment that decomposes the waste to harmless products. The concentration of the decomposing waste, \(C,\) has been reported to vary with time according to the formula \(C=1 /(a+b t)\) When sufficient time has elapsed for the concentration to drop to \(0.01 \mathrm{g} / \mathrm{L},\) the contents of the tank are discharged appropriately. The following data are taken for \(C\) and \(t\): $$\begin{array}{|c|c|c|c|c|c|}\hline t(\mathrm{h}) & 1.0 & 2.0 & 3.0 & 4.0 & 5.0 \\\\\hline C(\mathrm{g} / \mathrm{L}) & 1.43 & 1.02 & 0.73 & 0.53 & 0.38 \\\\\hline\end{array}$$ (a) If the given formula is correct, what plot would yield a straight line that would enable you to determine the parameters \(a\) and \(b ?\) (b) Estimate \(a\) and \(b\) using the method of least squares (Appendix A.1) or graphics software. Check the goodness of fit by generating a plot of \(C\) versus \(t\) that shows both the measured and predicted values of \(C\). (c) Using the results of Part (b), estimate the initial concentration of the waste in the tank and the time required for \(C\) to reach its discharge level. (d) You should have very little confidence in the time estimated in Part (c). Explain why. (e) There are potential problems with the whole waste disposal procedure. Suggest several of them. (f) The problem statement includes the phrase "discharged appropriately." Recognizing that what is considered appropriate may change with time, list three different means of disposal and concerns with each.

The relationship between the pressure \(P\) and volume \(V\) of the air in a cylinder during the upstroke of a piston in an air compressor can be expressed as \(P V^{k}=C\) where \(k\) and \(C\) are constants. During a compression test, the following data are taken: $$\begin{array}{|c|c|c|c|c|c|c|}\hline P(\mathrm{mm} \mathrm{Hg}) & 760 & 1140 & 1520 & 2280 & 3040 & 3800 \\ \hline V\left(\mathrm{cm}^{3}\right) & 48.3 & 37.4 & 31.3 & 24.1 & 20.0 & 17.4 \\\\\hline\end{array}$$ Determine the values of \(k\) and \(C\) that best fit the data. (Give both numerical values and units.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.