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Calculate (a) the weight in \(\mathrm{Ib}_{\mathrm{f}}\) of a \(25.0-\mathrm{lb}_{\mathrm{m}}\) object. (b) the mass in \(\mathrm{kg}\) of an object that weighs \(25 \mathrm{N}\). (c) the weight in dynes of a 10 -ton object (not metric tons).

Short Answer

Expert verified
The weight of the \(25.0-\mathrm{lb}_{\mathrm{m}}\) object is \(805.0 \, \mathrm{lb}_{\mathrm{f}}\). The mass of an object that weighs \(25 \, \mathrm{N}\) is \(2.55 \, \mathrm{kg}\). The weight in dynes of a 10-ton object is \(9.072e18 \, dynes\).

Step by step solution

01

- Conversion - Part (a)

To convert pounds mass (\(\mathrm{lb}_{\mathrm{m}}\)) to pounds force (\(\mathrm{lb}_{\mathrm{f}}\)), multiply the given mass by the conversion factor. Hence, weight = \(25.0 \, \text{lb}_{\text{m}} \times 32.2 = 805.0 \, \text{lb}_{\text{f}}\).
02

- Conversion - Part (b)

To convert Newtons (\(\mathrm{N}\)) to kilograms, use the conversion factor. Hence, mass = \(25 \, N \times 0.101972 = 2.5493 \, kg\). You may round this to 2.55 kg for simplicity.
03

- Conversion - Part (c)

For the conversion of tons to dynes, you multiply by the conversion factor. As such, weight = \(10 \, tons \times 9.072e17 = 9.072e18 \, dynes\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass to Weight Conversion
Understanding mass to weight conversion is an important fundamental in chemistry and physics. Mass is a measure of the amount of matter in an object, typically measured in kilograms (kg) or grams (g). Weight, on the other hand, is the force exerted by gravity on that mass and is often measured in newtons (N) or pounds force (\textbf{lb\textsubscript{f}}).

To convert mass to weight, you need to consider the acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s\textsuperscript{2}) on Earth. The formula to find the weight (W) from mass (m) is given by: \[ W = m \times g \]
where \( g \) is the acceleration due to gravity. For the exercise given, the weight in \(\text{lb}\textsubscript{f} \) of a \(25.0-\text{lb}\textsubscript{m} \) object is calculated using the Earth's standard gravity and the conversion factor between mass and weight, resulting in an answer of 805.0 \(\text{lb}\textsubscript{f} \).
  • The exercise should clearly state the value of gravity used for the conversion to avoid confusion.
Pounds to Kilograms
When converting units of mass, pounds to kilograms is a common conversion in scientific and international contexts. One pound (lb) is approximately equal to 0.453592 kilograms (kg).

The formula to convert pounds to kilograms is straightforward:\[ kg = lb \times 0.453592 \]For instance, part (b) of the exercise involves converting \(25 \text{N} \) to kilograms. First, you calculate the mass that would produce a 25 \text{N} force under standard Earth gravity. Using the conversion factor \(0.101972 \text{kg/N} \) provides a result of approximately 2.55 kg.
  • Since the unit of force (newtons) was converted to mass (kilograms), the solution should clearly differentiate between mass and weight to avoid misconceptions. Emphasizing force as a vector quantity that has magnitude and direction, while mass is a scalar quantity, solely a measure of an object's inertia, can also help students comprehend these distinct concepts.
Newtons to Dynes
The conversion between newtons and dynes involves understanding a less commonly used, but still relevant unit of force, the dyne. In the centimeter-gram-second (CGS) system, force is measured in dynes. One newton is equal to \(10^5 \) dynes. To convert newtons to dynes, simply multiply by 10^5.

In the third part of our exercise, we're asked to find the weight in dynes of a 10-ton object. A ton (not a metric ton) is equal to 2000 pounds. Firstly, you would convert tons to pounds, and then to the mass in kilograms. Thereon, the mass is converted to weight in dynes using the conversion factor for Earth's gravity and the respective conversion factor between kilograms and dynes.
  • The solution can be improved by outlining the sequential conversions that are necessary. Providing the intermediate steps—tons to pounds, then to kilograms, and finally to dynes—would help students follow the logic of the conversion process better and replicate it with different values.

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