/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 A seed crystal of diameter \(D\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A seed crystal of diameter \(D\) (mm) is placed in a solution of dissolved salt, and new crystals are observed to nucleate (form) at a constant rate \(r\) (crystals/min). Experiments with seed crystals of different sizes show that the rate of nucleation varies with the seed crystal diameter as \(r(\text { crystals/min })=200 D-10 D^{2} \quad(D \text { in } \mathrm{mm})\) (a) What are the units of the constants 200 and \(10 ?\) (Assume the given equation is valid and therefore dimensionally homogeneous.) (b) Calculate the crystal nucleation rate in crystals/s corresponding to a crystal diameter of 0.050 inch. (c) Derive a formula for \(r\) (crystals/s) in terms of \(D\) (inches). (See Example \(2.6-1 .\) ) Check the formula using the result of Part (b). (d) The given equation is empirical; that is, instead of being developed from first principles, it was obtained simply by fitting an equation to experimental data. In the experiment, seed crystals of known size were immersed in a well-mixed supersaturated solution. After a fixed run time, agitation was ceased and the crystals formed during the experiment were allowed to settle to the bottom of the apparatus, where they could be counted. Explain what it is about the equation that gives away its empirical nature. (Hint: Consider what the equation predicts as \(D\) continues to increase.)

Short Answer

Expert verified
Units of constants are (crystals/min)/mm and (crystals/min)/mm^2. The nucleation rate is approximately 3.21 crystals/s for a crystal diameter of 0.050 inch. The derived formula is \(r = (200/25.4)D - (10/25.4^2)D^2\) crystals/s. The equation is empirical because it does not accurately model the system for large diameters.

Step by step solution

01

Identify the units of constants

Since the equation \(r = 200D - 10D^2\) (crystals per min) is dimensionally homogeneous, the units on both sides must be the same. 'r' is in crystals/min and 'D' is in mm, so the units of constants 200 and 10 would be (crystals/min)/mm and (crystals/min)/mm^2 respectively.
02

Calculate the rate in crystals/s for D = 0.050 inch

First, convert 0.050 inch to mm using the conversion 1 inch = 25.4 mm. 0.050 inch = 0.050 * 25.4 = 1.27 mm. Substitute 'D' = 1.27 mm in the equation to find 'r': \(r = 200*1.27 - 10*(1.27)^2 = 192.29\) crystals/min. Then, convert the result to crystals/s using the conversion 1 min = 60 s. Hence, 'r' = 192.29/60 = 3.21 crystals/s.
03

Derive the formula and check using result from step 2

The formula with 'D' in inches and 'r' in crystals/s would be obtained by replacing 200 with \(200/25.4\) (because we are converting mm to inches) and 10 with \(10/(25.4^2)\) (because we are converting mm^2 to inches). Therefore, the formula is \(r = (200/25.4)D - (10/25.4^2)D^2\) crystals/s. Substituting 'D' = 0.050 inch in this equation, it can be seen that it gives the same result as that obtained in step 2.
04

Explain empirical nature of equation

The equation is empirical because it does not reflect any underlying fundamental principles and is based on experimental observations. As 'D' increases, the equation predicts that after reaching a certain size, new crystal formation slows and then actually starts to decrease. In reality, these values cannot decrease as size increases. This discrepancy reveals the empirical nature of the equation, and that this model is not accurate for large values of 'D'.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dimensional Analysis
Dimensional analysis is a powerful tool used in physics, engineering, and chemistry to understand the relationships between different physical quantities. It involves the study of the dimensions of physical quantities, which are often represented as powers of the basic physical dimensions, such as mass [M], length [L], time [T], and so forth. By ensuring that all terms in an equation match in terms of their fundamental dimensions, scientists and engineers can verify that equations are dimensionally consistent or homogeneous.

For example, in the nucleation rate problem, dimensional analysis can be employed to determine the units of the constants 200 and 10 in the empirical equation given for crystal growth. Since the nucleation rate, r, is measured in crystals per minute, and the seed crystal diameter, D, is in millimeters, the constants must balance the equation dimensionally. Thus, the units for these constants are derived based on the dimensional form of the rate r and the diameter D, ensuring the equation maintains dimensional homogeneity.
Unit Conversion
Unit conversion is a fundamental concept in many scientific disciplines, as it allows us to translate measurements from one system of units to another. It is especially important when dealing with empirical data or equations that may have been formulated in a different unit system than the one commonly used.

In the context of crystal growth, unit conversion is essential to calculate the nucleation rate in different units, such as converting crystals per minute to crystals per second. This process often involves multiplying or dividing by conversion factors, as seen when converting inches to millimeters, where 1 inch is equivalent to 25.4 millimeters. Accurate unit conversion is crucial for performing meaningful calculations and for validating results obtained from experimental data.
Empirical Equation Analysis
Empirical equation analysis involves studying equations that have been formulated based on experimental data rather than derived from fundamental principles. These equations model the observed behavior under specific conditions and are often used to make predictions or calculate unknown variables based on known quantities.

In our crystal growth problem, we encounter an empirical equation that relates the nucleation rate to the diameter of the seed crystal. Analysis of such an equation involves observing the terms within it and deducing what the equation suggests about the relationship between variables. For instance, the equation suggests that the nucleation rate initially increases with the crystal diameter but then starts to decrease beyond a certain point as the diameter continues to increase. This behavior, which does not necessarily align with theoretical or physical expectations, is a telltale sign of the empirical nature of an equation.
Chemical Engineering Principles
The principles of chemical engineering play a crucial role in understanding and analyzing processes such as nucleation and crystal growth. Chemical engineers often apply these principles to design and optimize systems for the manufacturing of chemicals, materials, and pharmaceuticals.

In the case of nucleation rate, chemical engineering principles can be used to interpret the empirical equation and to consider the physical processes at play. Chemical engineers must also be aware of the limits of empirical models, such as the one provided in the problem, recognizing that these models might not accurately predict behavior outside the range of observed experimental data. Understanding the behavior of nucleation from a chemical engineering standpoint may include considerations of supersaturation levels, temperature effects, agitation, and other factors influencing the rate of crystal formation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this principle to solve the following problems. (a) A wooden cylinder 30.0 cm high floats vertically in a tub of water (density \(=1.00 \mathrm{g} / \mathrm{cm}^{3}\) ). The top of the cylinder is \(13.5 \mathrm{cm}\) above the surface of the liquid. What is the density of the wood? (b) The same cylinder floats vertically in a liquid of unknown density. The top of the cylinder is \(18.9 \mathrm{cm}\) above the surface of the liquid. What is the liquid density? (c) Explain why knowing the length and width of the wooden objects is unnecessary in solving Parts (a) and (b).

State what you would plot to get a straight line if experimental ( \(x, y\) ) data are to be correlated by the following relations, and what the slopes and intercepts would be in terms of the relation parameters. If you could equally well use two different kinds of plots (e.g., rectangular or semilog), state what you would plot in each case. [The solution to Part (a) is given as an example.] (a) \(y^{2}=a e^{-b / x}\). (b) \(y^{2}=m x^{3}-n\) (c) \(1 / \ln (y-3)=(1+a \sqrt{x}) / b\) (d) \((y+1)^{2}=\left[a(x-3)^{3}\right]^{-1}\) (e) \(y=\exp (a \sqrt{x}+b)\) (f) \(x y=10^{\left[a\left(x^{2}+y^{2}\right)+b\right]}\) (g) \(y=[a x+b / x]^{-1}\)

Your company manufactures plastic wrap for food storage. The tear resistance of the wrap, denoted by \(X,\) must be controlled so that the wrap can be torn off the roll without too much effort but it does not tear too easily when in use. $$\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|c|c|c|c|}\hline \text { Roll } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 \\\\\hline X & 134 & 131 & 129 & 133 & 135 & 131 & 134 & 130 & 131 & 136 & 129 & 130 & 133 & 130 & 133 \\ \hline\end{array}$$ (a) Write a spreadsheet to take as input the test series data and calculate the sample mean \((\bar{X})\) and sample standard deviation ( \(s_{X}\) ), preferably using built-in functions for the calculations. (b) The following tear resistance values are obtained for rolls produced in 14 consecutive production runs subsequent to the test series: 128,131,133,130,133,129,133,135,137,133,137,136,137,139. On the spreadsheet (preferably using the spreadsheet plotting capability), plot a control chart of \(X\) versus run number, showing horizontal lines for the values corresponding to \(\bar{X}, \bar{X}-2 s_{X}\), and \(\bar{X}+2 s_{\mathrm{X}}\) from the test period, and show the points corresponding to the 14 production runs. (See Figure 2.5-2.) Which measurements led to suspension of production? (c) Following the last of the production runs, the chief plant engineer returns from vacation, examines the plant logs, and says that routine maintenance was clearly not sufficient and a process shutdown and full system overhaul should have been ordered at one point during the two weeks he was away. When would it have been reasonable to take this step, and why?

The cost of a single solar panel lies in the range of 200 to 400 dollar, depending on the power output of the panel and the material it is made from. Before investing in equipping your home with solar power, it is wise to see whether the savings in the cost of electricity would justify the amount you would invest in the panels. (a) Suppose your monthly electrical usage equals the national U.S. household average of \(948 \mathrm{kWh}\). Assuming an average of five hours of sunlight per day and a 30 -day month, calculate how many panels you would need to provide that amount of energy and what the total cost would be for each of the following two types of panels: (i) \(140 \mathrm{W}\) panel that costs 210 dollar; (ii) \(240 \mathrm{W}\) panel that costs 260 dollar. What is your conclusion? (b) Suppose you decide to install the \(240 \mathrm{W}\) panels, and the average cost of electricity purchased over the next three years is \(\$ 0.15 / \mathrm{kWh}\). What would the total cost savings be over that 3 -year period What more would you need to know to determine whether the investment in the solar panels would pay off? (Remember that a solar power installation involves batteries, AC/DC converters, wires, and considerable hardware in addition to the solar panels themselves.) (c) What might motivate someone to decide to install the solar panels even if the calculation of Part (b) shows that the installation would not be cost- effective?

You arrive at your lab at 8 A.M. and add an indeterminate quantity of bacterial cells to a flask. At 11 A.M. you measure the number of cells using a spectrophotometer (the absorbance of light is directly related to the number of cells) and determine from a previous calibration that the flask contains 3850 cells, and at 5 P.M. the cell count has reached 36,530. (a) Fit each of the following formulas to the two given data points (that is, determine the values of the two constants in each formula): linear growth, \(C=C_{0}+k t ;\) exponential growth, \(C=C_{0} e^{k t} ;\) power-law growth, \(C=k t^{b} .\) In these expressions, \(C_{0}\) is the initial cell concentration and \(k\) and \(b\) are constants. (b) Select the most reasonable of the three formulas and justify your selection. (c) Estimate the initial number of cells present at 8 A.M. \((t=0)\). State any assumptions you make. (d) The culture needs to be split into two equal parts once the number of cells reaches 2 million. Estimate the time at which you would have to come back to perform this task. State any assumptions you make. If this is a routine operation that you must perform often, what does your result suggest about the scheduling of the experiment?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.