/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The daily production of carbon d... [FREE SOLUTION] | 91Ó°ÊÓ

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The daily production of carbon dioxide from an \(880 \mathrm{MW}\) coal-fired power plant is estimated to be 31,000 tons. A proposal has been made to capture and sequester the \(\mathrm{CO}_{2}\) at approximately \(300 \mathrm{K}\) and 140 atm. At these conditions, the specific volume of \(\mathrm{CO}_{2}\) is estimated to be \(0.012 \mathrm{m}^{3} / \mathrm{kg}\). What volume \(\left(\mathrm{m}^{3}\right)\) of \(\mathrm{CO}_{2}\) would be collected during a one-year period?

Short Answer

Expert verified
The volume of \(CO_{2}\) that would be collected in a year is approximately \(31,000 \times 365 \times 1000 \times 0.012\) m³.

Step by step solution

01

Determine the total production of CO2 in one year

Firstly, it's important to calculate the total production of CO2 in a year. Since the daily production is given as 31,000 tons, to find the annual production, it needs to be multiplied by the number of days in a year, which is 365. Therefore, the total production is \(31,000 \times 365\) tons.
02

Convert the total CO2 production to kg

Now, the value obtained needs to be converted to kg as the specific volume of CO2 is given in m³/kg. Since 1 ton equals 1000 kg, the total production of CO2 in a year is \(31,000 \times 365 \times 1000\) kg.
03

Calculate the volume of CO2

Finally, this obtained value have to be multiplied with the specific volume of CO2 to get the total volume of CO2 produced. Hence, the volume of CO2 produced in a year is \(31,000 \times 365 \times 1000 \times 0.012\) m³.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Volume of Gases
Understanding the specific volume of gases is crucial when dealing with chemical processes. Specific volume, typically denoted as 'v', refers to the volume occupied by a unit mass of a substance. In the context of gases, the specific volume is affected by temperature and pressure conditions.
When we work with gases at high pressures or low temperatures, as seen in the exercise, these conditions can significantly change the physical properties of the gas. For carbon dioxide at 300 K and 140 atm, the specific volume is given as 0.012 m³/kg, meaning every kilogram of carbon dioxide occupies 0.012 cubic meters under those specific conditions.
This property is essential to calculate how much space a certain mass of gas will take. For industrial applications, like capturing and sequestering CO2 from a power plant, knowing the specific volume helps in designing the storage facilities and transportation infrastructure. The specific volume is not fixed; it varies depending on the Ideal Gas Law or Real Gas Equations, which incorporate variables such as pressure, temperature, and gas constants.

Relation to the Ideal Gas Law

For ideal gases, the specific volume can be derived from the Ideal Gas Law (\( PV = nRT \)), where 'P' is pressure, 'V' is volume, 'n' is the number of moles, 'R' is the universal gas constant, and 'T' is temperature. Although CO2 doesn't behave ideally under all conditions, the Ideal Gas Law provides a baseline for understanding gas behavior.
Conversion of Units
In chemical calculations, unit conversion is often a necessary step to ensure consistency and accuracy. In the context of our exercise, the conversion of tons to kilograms is key, as different units can describe mass. The common metric units for mass are grams (g), kilograms (kg), and tonnes (ton). One ton is equivalent to 1,000 kg or 1,000,000 g.
Converting units relies on defined conversion factors, which are ratios that allow you to express a measurement in different units. For example, to convert 31,000 tons to kg, we multiply by the conversion factor of 1,000 kg/ton, resulting in a large mass figure in kilograms.

Why Unit Conversion is Important

Accurate unit conversion is imperative in science and engineering as it ensures compatibility across systems and processes. If units are not converted properly, it could result in errors in calculations and potential real-world consequences, particularly in sensitive applications like pharmaceuticals, environmental engineering, and aerospace. It's always important to double-check unit conversions to avoid any mistakes, which is exactly what was done in the step-by-step solution to ensure correct results.
Stoichiometry of Chemical Reactions
Stoichiometry is the branch of chemistry that quantitatively relates the amounts of reactants and products in a chemical reaction. It is based on the conservation of mass and the concept that atoms are rearranged during chemical reactions.The stoichiometric coefficients in a balanced chemical equation indicate the relative amounts of substances involved. For instance, considering the combustion of coal primarily produces carbon dioxide, stoichiometry can help determine how much CO2 is produced from a known amount of coal.
The exercise provided does not directly involve balancing reactions or discerning stoichiometric ratios; instead, it requires the application of stoichiometric principles to calculate the volume from a known mass of CO2. Knowing that CO2 production is constant, and assuming complete conversion from coal to CO2, we can apply stoichiometric reasoning.

Applying Stoichiometry to Real-world Problems

Stoichiometry isn't just theoretical; it's used to solve practical problems, such as controlling pollutant levels or determining the required amounts of reactants for industrial processes. In the context of environmental engineering, understanding stoichiometry can help in calculating the quantities of byproducts like CO2, and thus contribute to developing strategies for pollution mitigation, which is illustrated in the carbon sequestration scenario of our exercise.

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Most popular questions from this chapter

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