/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 The climactic moment in the film... [FREE SOLUTION] | 91Ó°ÊÓ

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The climactic moment in the film "The Eggplant That Ate New Jersey" comes when the brilliant young scientist announces his discovery of the equation for the volume of the eggplant: \(V\left(\mathrm{ft}^{3}\right)=3.53 \times 10^{-2} \exp \left(2 t^{2}\right)\) where \(t\) is the time in hours from the moment the vampire injected the eggplant with a solution prepared from the blood of the beautiful dental hygienist. (a) What are the units of \(3.53 \times 10^{-2}\) and \(2 ?\) (b) The scientist obtained the formula by measuring \(V\) versus \(t\) and determining the coefficients by linear regression. What would he have plotted versus what on what kind of coordinates? What would he have obtained as the slope and intercept of his plot? (c) The European distributor of the film insists that the formula be given for the volume in \(\mathrm{m}^{3}\) as a function of \(t(\mathrm{s}) .\) Derive the formula.

Short Answer

Expert verified
The units of the coefficients are \(\mathrm{ft}^{3}\) and none. The scientist would probably have plotted \(V\left(\mathrm{ft}^{3}\right)\) versus \(t^{2}\) on semi-logarithmic coordinates, with a slope of \(2\) and an intercept of \(ln(3.53 \times 10^{-2})\). The formula in the new units would be \(V\left(\mathrm{m}^{3}\right)=3.53 \times 10^{-2} \times 0.0283168 \exp \left(2 \left(\frac{t}{3600}\right)^{2}\right)\)

Step by step solution

01

Identify Coefficients Units

The given equation is \(V\left(\mathrm{ft}^{3}\right)=3.53 \times 10^{-2}\exp \left(2 t^{2}\right)\), and to balance units on both sides, the first term \(3.53 \times 10^{-2}\) should have units of \(\mathrm{ft}^{3}\). The second term \(2 t^{2}\) is unitless because it's in the power of an exponential, which is a dimensionless number. So, the unit of \(2\) is also none.
02

Identify Method of Deriving the Formula

The scientist obtained this equation through linear regression by plotting \(V\) against \(t\). It indicates that he probably used a graph with \(V\left(\mathrm{ft}^{3}\right)\) on the y-axis and \(t^{2}\) on the x-axis. In the power of the exponential, \(t^{2}\) will be plotted against the natural logarithm of \(V\left(\mathrm{ft}^{3}\right)\). He would have obtained the slope as \(2\) and the intercept as \(ln(3.53 \times 10^{-2})\).
03

Derive Formula in new Units

To change the volume from cubic feet to cubic meters, use the conversion factor \(1 \, \mathrm{ft}^3 = 0.0283168 \, \mathrm{m}^3\) and to change the time from hours to seconds, the conversion factor \(1 \, \mathrm{hour} = 3600 \, \mathrm{seconds}\) will be used. As a result, the new formula will be: \(V\left(\mathrm{m}^{3}\right)=3.53 \times 10^{-2} \times 0.0283168 \exp \left(2 \left(\frac{t}{3600}\right)^{2}\right)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression in Chemistry
Linear regression is a statistical tool that is used frequently in the realm of chemistry to establish a relationship between variables. Imagine you're trying to find out how the concentration of a reactant affects the rate of a reaction. By conducting a series of experiments and measuring the rate at different concentrations, you would end up with a collection of data points.
In the context of the exercise, the young scientist used linear regression to determine the coefficients in the equation for volume of the eggplant. What does this entail in a practical sense? He would measure the volume (V) of the growing eggplant at different time points (t), and then plot these measurements on a graph. However, because the relationship involves an exponential function, he would take the natural logarithm of the volume measurements to linearize the data. By plotting the natural log of the volume versus the square of time, (\(ln(V)\) versus \(t^2\)), he would be able to perform linear regression to find the best straight line that fits his data. This line's slope and y-intercept would then correspond to the coefficients in the exponential equation.
Using linear regression in this manner allows chemists to convert a complex, nonlinear relationship into a simpler one that's easier to analyze. This is invaluable for making predictions and understanding the underlying principles governing chemical processes.
Dimensional Analysis
Dimensional analysis is a cornerstone technique for ensuring that the equations and calculations we perform in science make sense in terms of the units involved. It serves as a tool for converting one set of units to another and checking the consistency of equations. In the exercise, dimensional analysis helps us to deduce that the coefficient \(3.53 \times 10^{-2}\) has units of cubic feet because it's multiplied by an exponential function, which is dimensionless, to get a result in terms of volume.
How does it work in general? Take an equation and break it down by each term's units. Units must balance out on each side of the equation—like a seesaw. If they don't, something is amiss. For example, if you multiply speed (meters per second) by time (seconds), the seconds cancel out, and you end up with distance (meters). That's the essence of dimensional analysis: ensuring that units cancel out appropriately to give you the correct result.
Furthermore, this method is essential when it comes to converting units, as the scientist had to do for the European distributor. By applying conversion factors (\(1 \, \mathrm{ft}^3 = 0.0283168 \, \mathrm{m}^3\) and \(1 \, \mathrm{hour} = 3600 \, \mathrm{seconds}\)), he could adapt his volume equation to use meters and seconds instead of feet and hours, thus applying dimensional analysis to arrive at an equation suitable for an international audience.
Exponential Growth Equations
Exponential growth equations model processes that increase rapidly over time and are frequently encountered in chemistry, biology, and even pop culture scenarios like the fantastical growing eggplant in the exercise. The fundamental form of an exponential growth equation is \(y = a \exp(kx)\), where \(y\) is the quantity of interest, \(a\) is the initial amount, \(x\) is time, and \(k\) is the growth rate.
In the movie plot scenario, the equation \(V(\mathrm{ft}^{3})=3.53 \times 10^{-2} \exp(2 t^{2})\) captures the fantastical volume of the eggplant as it grows at an accelerating pace. The constant \(3.53 \times 10^{-2}\) represents the initial volume when time (\(t\)) is zero, and the term \(2 t^{2}\) in the exponent shows that the growth rate is proportional to the square of the time elapsed.
Exponential growth is non-linear—you don't see a straight increase but rather one that gets faster and faster. This is why linearizing the data through taking the natural logarithm, as mentioned in the linear regression section, is so crucial for analyzing such growth with linear regression techniques.

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Most popular questions from this chapter

According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this principle to solve the following problems. (a) A wooden cylinder 30.0 cm high floats vertically in a tub of water (density \(=1.00 \mathrm{g} / \mathrm{cm}^{3}\) ). The top of the cylinder is \(13.5 \mathrm{cm}\) above the surface of the liquid. What is the density of the wood? (b) The same cylinder floats vertically in a liquid of unknown density. The top of the cylinder is \(18.9 \mathrm{cm}\) above the surface of the liquid. What is the liquid density? (c) Explain why knowing the length and width of the wooden objects is unnecessary in solving Parts (a) and (b).

Suppose you have \(n\) data points \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots,\left(x_{n}, y_{n}\right)\) and you wish to fit a line through the origin \((y=a x)\) to these data using the method of least squares. Derive Equation A.1-6 (Appendix A.1) for the slope of the line by writing the expression for the vertical distance \(d_{i}\) from the \(i\) th data point \(\left(x_{i}, y_{i}\right)\) to the line, then writing the expression for \(\phi=\sum d_{i}^{2},\) and finding by differentiation the value of \(a\) that minimizes this function.

The relationship between the pressure \(P\) and volume \(V\) of the air in a cylinder during the upstroke of a piston in an air compressor can be expressed as \(P V^{k}=C\) where \(k\) and \(C\) are constants. During a compression test, the following data are taken: $$\begin{array}{|c|c|c|c|c|c|c|}\hline P(\mathrm{mm} \mathrm{Hg}) & 760 & 1140 & 1520 & 2280 & 3040 & 3800 \\ \hline V\left(\mathrm{cm}^{3}\right) & 48.3 & 37.4 & 31.3 & 24.1 & 20.0 & 17.4 \\\\\hline\end{array}$$ Determine the values of \(k\) and \(C\) that best fit the data. (Give both numerical values and units.)

L-Serine is an amino acid important for its roles in synthesizing other amino acids and for its use in intravenous feeding solutions. It is often synthesized commercially by fermentation, and recovered by subjecting the fermentation broth to several processing steps and then crystallizing the serine from an aqueous solution. The solubilities of L-serine (L-Ser) in water have been measured at several temperatures, producing the following data: \(^{5}\). $$\begin{array}{|c|c|c|c|c|c|c|c|c|}\hline T(\mathrm{K}) & 283.4 & 285.9 & 289.3 & 299.1 & 316.0 & 317.8 & 322.9 & 327.1 \\ \hline x \text { (mole fraction L-Ser) } & 0.0400 & 0.0426 & 0.0523 & 0.0702 & 0.1091 & 0.1144 & 0.1181 & 0.1248 \\ \hline\end{array}$$ One of the ways such data can be represented is with the van't Hoff equation: \(\ln x=(a / T)+b\) Graph the data so that the resulting plot is linear. Estimate \(a\) and \(b\) and give their units.

Sketch the plots described below and calculate the equations for \(y(x)\) from the given information. The plots are all straight lines. Note that the given coordinates refer to abscissa and ordinate values, not \(x\) and \(y\) values. [The solution of Part (a) is given as an example.] (a) A plot of In \(y\) versus \(x\) on rectangular coordinates passes through \((1.0,0.693)\) and \((2.0,0.0)\) (i.e., at the first point \(x=1.0\) and \(\ln y=0.693\) ). (b) A semilog plot of \(y\) (logarithmic axis) versus \(x\) passes through (1,2) and (2,1). (c) A log plot of \(y\) versus \(x\) passes through (1,2) and (2,1). (d) A semilog plot of \(x y\) (logarithmic axis) versus \(y / x\) passes through (1.0,40.2) and (2.0,807.0). (e) A log plot of \(y^{2} / x\) versus \((x-2)\) passes through (1.0,40.2) and (2.0,807.0).

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