/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Caffeine \(\left(\mathrm{C}_{8} ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Caffeine \(\left(\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}\right)\) is a stimulant found in coffee and tea. If a solution of caffeine in the solvent chloroform \(\left(\mathrm{CHCl}_{3}\right)\) has a concentration of \(0.0500 \mathrm{~m},\) calculate \((\mathbf{a})\) the percentage of caffeine by mass, (b) the mole fraction of caffeine in the solution.

Short Answer

Expert verified
(a) 0.962% by mass caffeine, (b) mole fraction of caffeine is 0.00595.

Step by step solution

01

Write down the Given Information

First, note the given data: the molecular formula for caffeine is \( \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{N}_{4} \mathrm{O}_{2} \), and the molality of the caffeine solution is \( 0.0500 \mathrm{~m} \). The solvent is chloroform \( \mathrm{CHCl}_{3} \).
02

Calculate the Molar Mass of Caffeine

Calculate the molar mass of caffeine by adding up the atomic masses of all the atoms in its formula: \( (8 \times 12.01) + (10 \times 1.01) + (4 \times 14.01) + (2 \times 16.00) = 194.22 \text{ g/mol} \).
03

Calculate the Molar Mass of Chloroform

Determine the molar mass of chloroform: \( \mathrm{CHCl}_3 \) consists of 1 carbon atom, 1 hydrogen atom, and 3 chlorine atoms. Thus, \( 12.01 + 1.01 + (3 \times 35.45) = 119.37 \text{ g/mol} \).
04

Define Molality and Calculate the Mass of Solvent

Molality \( m \) is the number of moles of solute (caffeine) per kilogram of solvent (chloroform). For a concentration of \( 0.0500 \text{ m} \), this means \( 0.0500 \text{ moles of caffeine per 1 kg of chloroform} \). Since \( 1 \text{ kg of chloroform} = 1000 \text{ g} \), use this information moving forwards.
05

Calculate the Mass of Caffeine

Calculate the mass of caffeine from its moles: \( 0.0500 \text{ moles} \times 194.22 \text{ g/mol} = 9.711 \text{ g} \).
06

Calculate the Total Mass of Solution

The total mass of the solution is the sum of the masses of the solute (caffeine) and the solvent (chloroform). So, \( 9.711 \text{ g (caffeine)} + 1000 \text{ g (chloroform)} = 1009.711 \text{ g} \).
07

Calculate the Percentage by Mass of Caffeine

The percentage by mass is given by \( \text{Percent by mass} = \left(\frac{\text{mass of solute (caffeine)}}{\text{total mass of solution}}\right) \times 100 \). Substitute the values: \( \left(\frac{9.711}{1009.711}\right) \times 100 = 0.962\% \).
08

Calculate the Mole Fraction of Caffeine

The mole fraction \( \chi \) of caffeine is calculated by dividing the moles of caffeine by the total moles in the solution. The moles of chloroform are \( \frac{1000}{119.37} = 8.377 \text{ moles} \). The mole fraction of caffeine is \( \frac{0.0500}{0.0500 + 8.377} \approx 0.00595 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Fraction
The mole fraction is a way to express the concentration of a component in a solution without involving its mass or volume. It is the ratio of the number of moles of a particular substance to the total number of moles of all substances present in the solution.

To calculate the mole fraction, begin by determining the number of moles of each component. For example, in a solution where caffeine is dissolved in chloroform, first calculate the moles of caffeine and chloroform using their respective molar masses.

  • Caffeine (C_{8}H_{10}N_{4}O_{2}) has a molar mass of 194.22 g/mol.
  • Chloroform (CHCl_{3}) has a molar mass of 119.37 g/mol.
Using the given molality, you can find that 0.0500 moles of caffeine are in the solution. For chloroform, calculate the moles using its mass in the solution. For instance, 1000 g of chloroform is approximately 8.377 moles.
Now, the mole fraction of caffeine is obtained by dividing the moles of caffeine by the total moles of all components:\[ \chi_{\text{caffeine}} = \frac{\text{moles of caffeine}}{\text{moles of caffeine} + \text{moles of chloroform}} = \frac{0.0500}{0.0500 + 8.377} \approx 0.00595 \]This value reflects the small proportion of caffeine in the solution given the large amount of chloroform.
Molality
Molality is a measure of solute concentration defined as the number of moles of solute per kilogram of solvent. Unlike molarity, molality does not change with temperature because it depends solely on mass, not volume.

To calculate molality (m), divide the moles of solute by the mass of the solvent in kilograms. For instance, if you dissolve caffeine into chloroform, first find the moles of caffeine from its mass and molar mass.
  • Given: Molality is 0.0500 m, which means there are 0.0500 moles of caffeine per kilogram of chloroform.

This direct relationship between moles and mass makes molality a useful concentration measure, especially in thermodynamic equations where temperature may influence solution volume but not its mass.
Mass Percentage
The mass percentage is a way to express the concentration of a component in a solution by comparing the mass of the solute to the total mass of the solution, expressed as a percentage. It indicates how many parts of solute are present in 100 parts of the solution.
To calculate mass percentage, use the formula:\[ \text{mass percent} = \left(\frac{\text{mass of solute}}{\text{total mass of solution}}\right) \times 100 \]Given the mass of caffeine as 9.711 g, and the total mass of the solution (caffeine plus chloroform) as 1009.711 g, the mass percentage of caffeine is:
\[ \text{mass percent of caffeine} = \left(\frac{9.711}{1009.711}\right) \times 100 = 0.962 \% \]
This means that in every 100 grams of the solution, about 0.962 grams is caffeine, offering a clear view of the solution's composition. Such information is particularly handy in chemical formulations where precise solute quantities are crucial.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At \(63.5^{\circ} \mathrm{C},\) the vapor pressure of \(\mathrm{H}_{2} \mathrm{O}\) is \(23.3 \mathrm{kPa},\) and that of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) is \(53.3 \mathrm{kPa}\). A solution is made by mixing equal masses of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\). (a) What is the mole fraction of ethanol in the solution? (b) Assuming idealsolution behavior, what is the vapor pressure of the solution at \(63.5^{\circ} \mathrm{C} ?(\mathbf{c})\) What is the mole fraction of ethanol in the vapor above the solution?

Indicate the principal type of solute-solvent interaction in each of the following solutions and rank the solutions from weakest to strongest solute- solvent interaction: (a) KCl in water, (b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\), (c) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in water.

The concentration of gold in seawater has been reported to be between 5 ppt (parts per trillion) and 50 ppt. Assuming that seawater contains 13 ppt of gold, calculate the number of grams of gold contained in \(1.0 \times 10^{3}\) gal of seawater.

The solubility of alum, \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} \cdot 12 \mathrm{H}_{2} \mathrm{O},\) in water at is \(44 \mathrm{~g}\) per \(100 \mathrm{~g}\) of water at \(50^{\circ} \mathrm{C}\). A solution of alum in water at \(80^{\circ} \mathrm{C}\) is formed by dissolving \(130 \mathrm{~g}\) in \(100 \mathrm{~g}\) of water. When this solution is slowly cooled to \(50^{\circ} \mathrm{C}\), no precipitate forms. (a) Is the solution that has cooled down to \(50^{\circ} \mathrm{C}\) unsaturated, saturated, or supersaturated? (b) You take a metal spatula and scratch the side of the glass vessel that contains this cooled solution, and crystals start to appear. What has just happened? (c) At equilibrium, what mass of crystals do you expect to form?

Oil and water are immiscible. Which is the most likely reason? (a) Oil molecules are denser than water. (b) Oil molecules are composed mostly of carbon and hydrogen. (c) Oil molecules have higher molar masses than water. (d) Oil molecules have higher vapor pressures than water. (e) Oil molecules have higher boiling points than water.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.